如何在JSLint中禁用奇怪条件检查？ [英] How to disable the Weird Condition check in JSLint?

问题描述

我有一些代码将键盘键映射到不同长度的代码块，从简单的 return false 到主要的2-3行代码片段到复杂的代码块函数：

I have some code that maps keyboard keys to blocks of code of varying length, from something as simple as return false, to mainly 2-3 line snippets, to complex functions:

var k = window.event.keycode;

switch(true){
    case(k === 9):
       //
    break;

    case(k === 13):
       //
    break;

    case(k === 38 && selectedRecord > 1):
       //
    break;
}

我不想创建一个包含函数列表的对象并映射它这样，因为它们主要是短代码块，并且存在奇怪的复杂情况。

I'd rather not create an object with a list of functions and map it that way, because they're mainly short blocks of code and there is the odd complex case.

是否存在禁用检查开关（true）的选项（因为有其他检查）？

Is there an option to disable the check for switch(true) (as there are for other checks)?

相关的，但不是重复：反向切换语句是否可接受JavaScript？

Related, but not a duplicate: Is a reversed switch statement acceptable JavaScript?

推荐答案

两个想法：

1）你可以让linter开心通过在文件顶部添加此注释： / * jshint eqeqeq：true * / 这就是说，我仍然得到这个'开关'应该是'if'。警告。可能是jslint / jshint不会忽略这种构造。

1) You can make the linter happy by adding this comment at the top of the file: /*jshint eqeqeq: true */ That said, I still get a This 'switch' should be an 'if'. warning. It may be that jslint/jshint just won't ignore this kind of construct.

2）我会恭敬地建议你抓住这个机会而不是转换linter选项清理相当奇怪的代码并重写开关，如下所示：

2) Instead of turning of linter options, I would respectfully suggest that you take this opportunity to clean up rather strange code and rewrite your switch as follows:

var k = window.event.keycode;

if(k === 9) {
       //
} else if(k === 13) {
       //
} else if(k === 38 && selectedRecord > 1) {
       //
}

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