如果函数在3秒内未被调用N个记录中的1个,则如何应用超时 [英] How to apply a timeout if a function hasn't been called 1 of N records in 3 seconds
问题描述
当用户执行某个操作(输入)时,我运行一个功能,在100个用户的列表中将特定样式应用于该用户。随着用户继续键入此功能继续运行。
When a user performs a certain action (typing) I run a function that applies a specific styling to that user in a list of 100s of users. As the user continues to type this function continues to run.
我想要的是应用超时来删除样式。意思是如果在3秒内没有调用该函数,则运行另一个命令来删除样式。
What I would like to do is apply a time out to remove the styling. Meaning if the function hasn't been called in 3 secs, run another command to remove the styling.
有关如何创建这样的超时的任何建议吗?
Any suggestions on how to create a timeout like this?
谢谢
推荐答案
使用JavaScript的 setTimeout()
调用方法以在3秒(3000毫秒)后删除样式的方法。见下文:
Use JavaScript's setTimeout()
method to invoke a method to remove the styling after 3 seconds (3000 ms). See below:
var timeout;
function clearStyling() {
// clear your styling here
};
$("#typingBox").on("keypress", function() {
clearTimeout(timeout);
timeout = setTimeout(clearStyling, 3000);
// do your styling here ...
});
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