PHP内部的Javascript？ [英] PHP Inside Javascript?

问题描述

我有以下代码：

function deletet(username){
if(confirm("Do you REALLY want to delete your account?")){
    if(confirm("Are you POSITIVE?")){
        var check = prompt("Enter your password","");
        if(check){
            <?php
                require('functions.php');
                mysqlLogin();
                $password = 
                $username = $_COOKIE['sqlusername'];
                $queyreg = ("SELECT * FROM `users` WHERE username='$username'");
                $row = mysql_fetch_array($queryreg,MYSQL_ASSOC);
                $hash = hash('sha256', $row['salt'] . hash('sha256', $password));
                if($hash == $row['password']){
                    $sql = mysql_query("DELETE FROM `users` WHERE username='$username' AND password='$hash'");
                    if($sql){
                        ?> alert("Account deleted, thank you"); window.location='login.php'; <?php
                    } else {
                        ?> alert("There was an error deleting your account"); return false; <?php
                    }
                } else {
                ?> alert("Passwords don't match!"); return false; <?php
                }
            ?>
            return true;
        } else {
            alert("Please enter your password!");
            return false;
        }   
    } else {
        return false;
    }   
} else {
    return false;
}
}

几个问题。

1. 如何设置 $ password 等于用户名传递给函数的变量？


2. 为什么我在调用函数时没有得到 confirm（）对话框？

1. How do I set $password equal to the username variable passed into the function?
2. Why don't I get the confirm() dialog when I call the function?

推荐答案

你需要 AJAX 来处理这个问题，这是一个使用 jQuery 的示例。$
将此代码放在一个PHP文件中， ajax.php

You need AJAX to handle that, here's a sample using jQuery.
Put this code in one PHP file, ajax.php

       <?php
            require('functions.php');
            mysqlLogin();
            $password = $_GET['password'];
            $username = $_COOKIE['sqlusername'];
            $queyreg = ("SELECT * FROM `users` WHERE username='$username'");
            $row = mysql_fetch_array($queryreg,MYSQL_ASSOC);
            $hash = hash('sha256', $row['salt'] . hash('sha256', $password));
            if($hash == $row['password']){
                $sql = mysql_query("DELETE FROM `users` WHERE username='$username' AND password='$hash'");
                if($sql){
                    echo 'deleted';
                } else {
                    echo 'error';
                }
            } else {
             echo 'false';
            }
        ?>

然后修改你的JS代码，通过AJAX调用ajax.php。

Then modify your JS code to call ajax.php through AJAX.

function deletet(username){
  if(confirm("Do you REALLY want to delete your account?")){
      if(confirm("Are you POSITIVE?")){
          var check = prompt("Enter your password","");
          if(check){
              jQuery.ajax({
                url: 'ajax.php?password='+username,
                type: 'GET',
                data: '',
                success: function(data) {
                  if (data == 'deleted') {
                    alert("Account deleted, thank you"); window.location='login.php';
                  }
                  else if (data == 'error'){
                    alert("There was an error deleting your account"); return false;
                  }
                  else if (data == 'false'){
                    alert("Passwords don't match!"); return false;
                  }
                }
              });
              return true;
          } else {
              alert("Please enter your password!");
              return false;
          }   
      } else {
          return false;
      }   
  } else {
      return false;
  }
}

希望这有帮助。

这篇关于PHP内部的Javascript？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！