在javascript中保存xml [英] saving xml in javascript
问题描述
大家好。我有以下问题。我有一个xml文件，而我将在下面列出
列表，我试图根据
用户输入表单向xml文档添加节点。
XML文档是......
<？xml version =" 1.0"？>
< board>
< message>
< authorAuthor One< / author>
< commentThis是第一个测试评论< / comment>
< / message>
< message>
< authorAuthor Two< / author>
< comment这是第二次测试评论< / comment>
< / message>
< message>
< authorAuthor Three< / author>
< commentThis是第三次测试评论< / comment>
< / message>
< / board>
我必须插入新节点的代码是....
< script type =" text / javascript">
var xmlDoc;
var xmlObj;
va作者;
var评论;
var message;
函数loadXMLDoc（）{
xmlDoc = new ActiveXObject（" Microsoft.XMLDOM"）;
xmlDoc.async =" false";
xmlDoc.load（" Guestbook.xml"）;
xmlObj = xmlDoc.documentElement;
processInput（）;
}
函数processInput（ ）{
var new_message = xmlDoc.createElement（''message''）;
var new_author = xmlDoc.createElement（''author''）;
var new_comment = xmlDoc.createElement（''comment''）;
var new_author_text = new_author.createTextNode（''author test
works''）;
var new_comment_text = new_comment.createTextNode（''comme nt test
works''）;
new_message.appendChild（new_author）;
new_message.appendChild（new_comment）;
xmlObj.appendChild（new_message）;
xmlDoc.save（" Guestbook.xml"）;
}
< / script>
目前我执行此操作时对xml没有任何改变
档。我所期望的是手动打开xml doc并查看root的4个子节点b $ b节点而不是3节点，如上面xml列表中所示。关于我做错了什么的想法或想法？
另外值得注意的是上面的代码在JSP文件的head部分。
只使用JSP而不是HTML文件，但实际上没有jsp代码在
文件中，只需要html。
谢谢，
Charles
ch ********** @ gmail.com 写道：
I有以下问题。我有一个xml文件，而我将在下面列出
，我试图根据
用户输入表单向xml文档添加节点。
xmlDoc = new ActiveXObject（" Microsoft.XMLDOM"）;
xmlDoc.save（" Guestbook.xml"）;
是否允许成功调用save方法取决于您的脚本使用的
主机。具有正常安全设置的IE不会
允许，我甚至不确定降低安全设置是否允许它。
但是允许在Windows脚本宿主脚本中调用保存，
ASP页面，在HTML应用程序（HTA）中，命名最常见的主机。
-
Martin Honnen
http://JavaScript.FAQTs.com/
大家好。我有以下问题。我有一个xml文件，而我将在下面列出
列表，我试图根据
用户输入表单向xml文档添加节点。
XML文档是......
<？xml version =" 1.0"？>
< board>
< message>
< authorAuthor One< / author>
< commentThis是第一个测试评论< / comment>
< / message>
< message>
< authorAuthor Two< / author>
< comment这是第二次测试评论< / comment>
< / message>
< message>
< authorAuthor Three< / author>
< commentThis是第三次测试评论< / comment>
< / message>
< / board>
我必须插入新节点的代码是....
< script类型= QUOT;文本/ javasc ript">
var xmlDoc;
var xmlObj;
var author;
var comment;
var message;
函数loadXMLDoc（）{
xmlDoc = new ActiveXObject（" Microsoft.XMLDOM"）;
xmlDoc.async =" false";
xmlDoc.load（" Guestbook.xml"）;
xmlObj = xmlDoc.documentElement;
processInput（）;
}
函数processInput（）{
var new_message = xmlDoc.createElement （''message''）;
var new_author = xmlDoc.createElement（''author''）;
var new_comment = xmlDoc.createElement（''comment'' ）;
var new_author_text = new_author.createTextNode（''author test
works''）;
var new_comment_text = new_comment.createTextNode（' '纪念est
作品''）;
new_message.appendChild（new_author）;
new_message.appendChild（new_comment）;
xmlObj.appendChild（new_message）;
xmlDoc.save（" Guestbook.xml"）;
}
< / script>
目前执行此操作时，对xml
文件不做任何更改。我所期望的是手动打开xml doc并查看root的4个子节点b $ b节点而不是3节点，如上面xml列表中所示。关于我做错了什么的想法或想法？
另外值得注意的是上面的代码在JSP文件的head部分。
只使用JSP而不是HTML文件，但实际上没有jsp代码在
文件中，只需要html。
谢谢，
Charles
Desidero appena dire che e un luogo ben cotto http://www.usate348.org/progetti
BizTalk实用工具 - 无懈可击的BizTalk适配器
http://www.topxml.com/biztalkutilities
大家好。我有以下问题。我有一个xml文件，而我将在下面列出
列表，我试图根据
用户输入表单向xml文档添加节点。
XML文档是......
<？xml version =" 1.0"？>
< board>
< message>
< authorAuthor One< / author>
< commentThis是第一个测试评论< / comment>
< / message>
< message>
< authorAuthor Two< / author>
< comment这是第二次测试评论< / comment>
< / message>
< message>
< authorAuthor Three< / author>
< commentThis是第三次测试评论< / comment>
< / message>
< / board>
我必须插入新节点的代码是....
< script类型= QUOT;文本/ javasc ript">
var xmlDoc;
var xmlObj;
var author;
var comment;
var message;
函数loadXMLDoc（）{
xmlDoc = new ActiveXObject（" Microsoft.XMLDOM"）;
xmlDoc.async =" false";
xmlDoc.load（" Guestbook.xml"）;
xmlObj = xmlDoc.documentElement;
processInput（）;
}
函数processInput（）{
var new_message = xmlDoc.createElement （''message''）;
var new_author = xmlDoc.createElement（''author''）;
var new_comment = xmlDoc.createElement（''comment'' ）;
var new_author_text = new_author.createTextNode（''author test
works''）;
var new_comment_text = new_comment.createTextNode（' '纪念est
作品''）;
new_message.appendChild（new_author）;
new_message.appendChild（new_comment）;
xmlObj.appendChild（new_message）;
xmlDoc.save（" Guestbook.xml"）;
}
< / script>
目前执行此操作时，对xml
文件不做任何更改。我所期望的是手动打开xml doc并查看root的4个子节点b $ b节点而不是3节点，如上面xml列表中所示。关于我做错了什么的想法或想法？
另外值得注意的是上面的代码在JSP文件的head部分。
只使用JSP而不是HTML文件，但实际上没有jsp代码在
文件中，只需要html。
谢谢，
Charles
mmm ..漂亮的设计，我必须说.. http://www.bovso.org/amici
BizTalk实用工具 - 无懈可击的BizTalk适配器
http://www.topxml.com/biztalkutilities
Hi all. I have the following problem. I have an xml file, while I will
list below and I am trying to add nodes to the xml document based on
user input to a form.
The XML doc is ...
<?xml version="1.0"?>
<board>
<message>
<authorAuthor One </author>
<commentThis is the first test comment </comment>
</message>
<message>
<authorAuthor Two </author>
<commentThis is the second test comment </comment>
</message>
<message>
<authorAuthor Three </author>
<commentThis is the third test comment </comment>
</message>
</board>
The code I have to insert a new node is ....
<script type="text/javascript">
var xmlDoc;
var xmlObj;
var author;
var comment;
var message;
function loadXMLDoc() {
xmlDoc = new ActiveXObject("Microsoft.XMLDOM");
xmlDoc.async="false";
xmlDoc.load("Guestbook.xml");
xmlObj=xmlDoc.documentElement;
processInput();
}
function processInput() {
var new_message=xmlDoc.createElement(''message'');
var new_author=xmlDoc.createElement(''author'');
var new_comment=xmlDoc.createElement(''comment'');
var new_author_text=new_author.createTextNode(''author test
works'');
var new_comment_text=new_comment.createTextNode(''comme nt test
works'');
new_message.appendChild(new_author);
new_message.appendChild(new_comment);
xmlObj.appendChild(new_message);
xmlDoc.save("Guestbook.xml");
}
</script>
Currently when I execute this is makes no change whatsoever to the xml
file. What I expected was to open the xml doc manually and see 4 child
nodes of the root instead of 3 as shown above in the xml listing. Any
thoughts or ideas on what I''m doing wrong?
Also of note is the above code is in the head section of a JSP file.
Just using JSP instead of HTML file but no jsp code is actually in the
file, just html.
Thanks,
Charles
ch**********@gmail.com wrote:
I have the following problem. I have an xml file, while I will
list below and I am trying to add nodes to the xml document based on
user input to a form.
xmlDoc = new ActiveXObject("Microsoft.XMLDOM");
xmlDoc.save("Guestbook.xml");Whether calling the save method successfully is allowed depends on the
host your script is used in. IE with normal security settings does not
allow that, I am not even sure lowering security settings will allow it.
It is however allowed to call save in a Windows Script Host script, in
an ASP page, in a HTML application (HTA), to name the most common hosts.
--
Martin Honnen
http://JavaScript.FAQTs.com/
Hi all. I have the following problem. I have an xml file, while I will
list below and I am trying to add nodes to the xml document based on
user input to a form.
The XML doc is ...
<?xml version="1.0"?>
<board>
<message>
<authorAuthor One </author>
<commentThis is the first test comment </comment>
</message>
<message>
<authorAuthor Two </author>
<commentThis is the second test comment </comment>
</message>
<message>
<authorAuthor Three </author>
<commentThis is the third test comment </comment>
</message>
</board>
The code I have to insert a new node is ....
<script type="text/javascript">
var xmlDoc;
var xmlObj;
var author;
var comment;
var message;
function loadXMLDoc() {
xmlDoc = new ActiveXObject("Microsoft.XMLDOM");
xmlDoc.async="false";
xmlDoc.load("Guestbook.xml");
xmlObj=xmlDoc.documentElement;
processInput();
}
function processInput() {
var new_message=xmlDoc.createElement(''message'');
var new_author=xmlDoc.createElement(''author'');
var new_comment=xmlDoc.createElement(''comment'');
var new_author_text=new_author.createTextNode(''author test
works'');
var new_comment_text=new_comment.createTextNode(''comme nt test
works'');
new_message.appendChild(new_author);
new_message.appendChild(new_comment);
xmlObj.appendChild(new_message);
xmlDoc.save("Guestbook.xml");
}
</script>
Currently when I execute this is makes no change whatsoever to the xml
file. What I expected was to open the xml doc manually and see 4 child
nodes of the root instead of 3 as shown above in the xml listing. Any
thoughts or ideas on what I''m doing wrong?
Also of note is the above code is in the head section of a JSP file.
Just using JSP instead of HTML file but no jsp code is actually in the
file, just html.
Thanks,
CharlesDesidero appena dire che e un luogo ben cotto http://www.usate348.org/progetti
BizTalk Utilities - Frustration free BizTalk Adapters
http://www.topxml.com/biztalkutilities
Hi all. I have the following problem. I have an xml file, while I will
list below and I am trying to add nodes to the xml document based on
user input to a form.
The XML doc is ...
<?xml version="1.0"?>
<board>
<message>
<authorAuthor One </author>
<commentThis is the first test comment </comment>
</message>
<message>
<authorAuthor Two </author>
<commentThis is the second test comment </comment>
</message>
<message>
<authorAuthor Three </author>
<commentThis is the third test comment </comment>
</message>
</board>
The code I have to insert a new node is ....
<script type="text/javascript">
var xmlDoc;
var xmlObj;
var author;
var comment;
var message;
function loadXMLDoc() {
xmlDoc = new ActiveXObject("Microsoft.XMLDOM");
xmlDoc.async="false";
xmlDoc.load("Guestbook.xml");
xmlObj=xmlDoc.documentElement;
processInput();
}
function processInput() {
var new_message=xmlDoc.createElement(''message'');
var new_author=xmlDoc.createElement(''author'');
var new_comment=xmlDoc.createElement(''comment'');
var new_author_text=new_author.createTextNode(''author test
works'');
var new_comment_text=new_comment.createTextNode(''comme nt test
works'');
new_message.appendChild(new_author);
new_message.appendChild(new_comment);
xmlObj.appendChild(new_message);
xmlDoc.save("Guestbook.xml");
}
</script>
Currently when I execute this is makes no change whatsoever to the xml
file. What I expected was to open the xml doc manually and see 4 child
nodes of the root instead of 3 as shown above in the xml listing. Any
thoughts or ideas on what I''m doing wrong?
Also of note is the above code is in the head section of a JSP file.
Just using JSP instead of HTML file but no jsp code is actually in the
file, just html.
Thanks,
Charlesmmm.. nice design, I must say.. http://www.bovso.org/amici
BizTalk Utilities - Frustration free BizTalk Adapters
http://www.topxml.com/biztalkutilities
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