使std :: string成为union的成员??? [英] Making a std::string a member of a union ???

问题描述

除了从头开始创建自己的字符串之外，还有这样做吗？


union AnyType {

std :: string String;

double number;

};

Is there anyway of doing this besides making my own string from scratch?

union AnyType {
std::string String;
double Number;
};

推荐答案

" Peter Olcott" < No **** @ SeeScreen.com在新闻中写道：ZtPoh.8718

"Peter Olcott" <No****@SeeScreen.comwrote in news:ZtPoh.8718

rv1.8337

@ newsfe21.lga：

rv1.8337
@newsfe21.lga:

除了从头开始创建自己的字符串之外还有这样做吗？


union AnyType {

std :: string String;

double Number;

};

Is there anyway of doing this besides making my own string from scratch?

union AnyType {
std::string String;
double Number;
};

即使使用自己的字符串也不能这样做：


第12.1.11节：工会成员不应是具有非平凡构造函数的类类型（或数组

）。

You can''t do this even with your own string:

Section 12.1.11: "A union member shall not be of a class type (or array
thereof) that has a non-trivial constructor.".

Peter Olcott schrieb ：

Peter Olcott schrieb:

除了从头开始创建自己的字符串之外还有这样做吗？


union AnyType {

std :: string String;

double Number;

};

Is there anyway of doing this besides making my own string from scratch?

union AnyType {
std::string String;
double Number;
};

你不能。但是根据你想做什么，你可能会发现

boost :: variant或boost :: any非常有用：

http://www.boost.org/doc/html/variant.html
< a rel =nofollowhref =http://www.boost.org/doc/html/any.htmltarget =_ blank> http://www.boost.org/doc/html/any.html


-

Thomas
http://www.netmeister.org/news/learn2quote.html

You cannot. But depending on what you want to do, you might find
boost::variant or boost::any quite useful:

http://www.boost.org/doc/html/variant.html
http://www.boost.org/doc/html/any.html

--
Thomas
http://www.netmeister.org/news/learn2quote.html

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