介绍一个C编译器ucc [英] Introduce a C Compiler ucc

问题描述

ucc是ANSI C编译器。它的代码大小约为15,000行。

词法分析器，解析器和代码生成器都是手写的。

代码结构非常清晰明了。还有一个

有趣的值编号算法。

它还有一个解释内部实现的文档。

如果你对这个编译器感兴趣，您可以从
http://sourceforge.net/projects/ucc <下载/ a>，这将帮助你掌握

C语言。

解决方案

5月11日，4：15 am，dreamAnders< dream_and ... @ yahoo.com.cnwrote：

ucc是ANSI C编译器。它的代码大小约为15,000行。

词法分析器，解析器和代码生成器都是手写的。

代码结构非常清晰明了。还有一个

有趣的值编号算法。

它还有一个解释内部实现的文档。

如果你对这个编译器感兴趣，您可以从http://sourceforge.net/projects/ucc下载它，它将帮助您掌握

C语言。

你在ucc / ucl / linux / include / assert.h中执行assert不是
ANSI C，（或ISO C）因为如果没有定义NDEBUG，它会多次评估它的参数。

示例：assert（printf（" hello world \ n"））;会打印两次。


我建议你重写_assert（并重命名为_Assert）返回

void，并在那里进行两次检查。 />

5月10日晚上9:15，dreamAnders< dream_and ... @ yahoo.com.cn写道：

ucc是ANSI C编译器。它的代码大小约为15,000行。

词法分析器，解析器和代码生成器都是手写的。

代码结构非常清晰明了。还有一个

有趣的值编号算法。

它还有一个解释内部实现的文档。

如果你对这个编译器感兴趣，您可以从http://sourceforge.net/projects/ucc下载它，它将帮助您掌握

C语言。

每1000行代码大约有1条评论，这可能很难获得用于研究和教学用途的

。


-

Robert Gamble

5月11日上午9:35，vipps。 .. @ gmail.com写道：

5月11日凌晨4:15，dreamAnders< dream_and ... @ yahoo.com.cnwrote：

ucc是ANSI C编译器。它的代码大小约为15,000行。

词法分析器，解析器和代码生成器都是手写的。

代码结构非常清晰明了。还有一个

有趣的值编号算法。

它还有一个解释内部实现的文档。

如果你对这个编译器感兴趣，您可以从http://sourceforge.net/projects/ucc下载它，它将帮助您掌握

C语言。

你在ucc / ucl / linux / include / assert.h中执行assert不是

ANSI C，（或ISO C）因为如果没有定义NDEBUG，它会多次评估它的参数。

示例：assert（printf（" hello world \ n"））;会打印两次。


我建议你重写_assert（并重命名为_Assert）返回

void，并在那里进行两次检查。

不，它不会多次评估其参数。


#define assert（e）（（void） （（e）|| _assert（＃e，__ FILE __，__LINE__）））


请注意第二个e'的外观，它是''＃e''

ucc is an ANSI C Compiler. Its code size is about 15,000 lines.
The lexer, parser and code generator are all hand-written.
The code structure is very clear and straightforward. And there is an
interesting value numbering algorithm.
It also has a document explaining the internal implementation.
If you are interested at this compiler, you can download it from
http://sourceforge.net/projects/ucc, which will help you to master the
C language.

解决方案

On May 11, 4:15 am, dreamAnders <[e-mail]:

ucc is an ANSI C Compiler. Its code size is about 15,000 lines.
The lexer, parser and code generator are all hand-written.
The code structure is very clear and straightforward. And there is an
interesting value numbering algorithm.
It also has a document explaining the internal implementation.
If you are interested at this compiler, you can download it fromhttp://sourceforge.net/projects/ucc, which will help you to master the
C language.

Your implementation of assert in ucc/ucl/linux/include/assert.h is not
ANSI C, (or ISO C) as it evaluates it''s parameter more than once if
NDEBUG is not defined.
Example: assert(printf("hello world\n")); would call print twice.

I suggest you rewrite _assert (and also rename to _Assert) to return
void, and make the check twice there.

On May 10, 9:15 pm, dreamAnders <[e-mail]:

ucc is an ANSI C Compiler. Its code size is about 15,000 lines.
The lexer, parser and code generator are all hand-written.
The code structure is very clear and straightforward. And there is an
interesting value numbering algorithm.
It also has a document explaining the internal implementation.
If you are interested at this compiler, you can download it fromhttp://sourceforge.net/projects/ucc, which will help you to master the
C language.

At about 1 comment per 1000 lines of code it may be difficult to get
this adopted for "research and instructional use".

--
Robert Gamble

On May 11, 9:35 am, [e-mail] wrote:

On May 11, 4:15 am, dreamAnders <[e-mail]:

ucc is an ANSI C Compiler. Its code size is about 15,000 lines.
The lexer, parser and code generator are all hand-written.
The code structure is very clear and straightforward. And there is an
interesting value numbering algorithm.
It also has a document explaining the internal implementation.
If you are interested at this compiler, you can download it fromhttp://sourceforge.net/projects/ucc, which will help you to master the
C language.

Your implementation of assert in ucc/ucl/linux/include/assert.h is not
ANSI C, (or ISO C) as it evaluates it''s parameter more than once if
NDEBUG is not defined.
Example: assert(printf("hello world\n")); would call print twice.

I suggest you rewrite _assert (and also rename to _Assert) to return
void, and make the check twice there.

No, It will not evaluate its parameter more than once.

#define assert(e) ((void)((e)||_assert(#e, __FILE__, __LINE__)))

please notice that the second e''s appearance, it is ''#e''

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