因子的迭代 [英] Iteration for Factorials

问题描述

我试图编写一个函数，使用迭代而不是递归生成一个
数的阶乘。任何简单的想法都会受到赞赏。

解决方案

Py-Fun写道：
< blockquote class =post_quotes>
我试图编写一个函数，使用迭代而不是递归来生成一个
数的阶乘。任何简单的想法都会受到赞赏。

向我们展示您的尝试，我们可能会建议修复。因为否则这个

听起来像是家庭作业。


Diez

10月22日，13： 28，Diez B. Roggisch， < de ... @nospam.web.dewrote：

Py-Fun写道：

我试图编写一个函数，使用迭代而不是递归生成一个
数的阶乘。任何简单的想法都会受到赞赏。

向我们展示您的尝试，我们可能会建议修复。因为否则这个

听起来像是家庭作业。


Diez

这是我徒劳的尝试。小心这一点，我只是跑了

类似的东西，它永远不会结束......


def itforfact（n）：

而n< 100：

打印n

n + 1

n =输入（请输入低于100的数字）


itforfact（n）

Py-Fun写道：

我试图编写一个函数，使用迭代而不是递归来生成一个
数的阶乘。任何简单的想法都会受到赞赏。

与什么相比，一个复杂的？

I''m stuck trying to write a function that generates a factorial of a
number using iteration and not recursion. Any simple ideas would be
appreciated.

解决方案

Py-Fun wrote:

I''m stuck trying to write a function that generates a factorial of a
number using iteration and not recursion. Any simple ideas would be
appreciated.

Show us your attempts, and we might suggest a fix. Because otherwise this
sounds suspiciously like homework.

Diez

On 22 Oct, 13:28, "Diez B. Roggisch" <[e-mail]:

Py-Fun wrote:

I''m stuck trying to write a function that generates a factorial of a
number using iteration and not recursion. Any simple ideas would be
appreciated.

Show us your attempts, and we might suggest a fix. Because otherwise this
sounds suspiciously like homework.

Diez

Here is my futile attempt. Be careful with this though, I just ran
something similar and it was never ending...

def itforfact(n):
while n<100:
print n
n+1
n = input("Please enter a number below 100")

itforfact(n)

Py-Fun wrote:

I''m stuck trying to write a function that generates a factorial of a
number using iteration and not recursion. Any simple ideas would be
appreciated.

As opposed to what, a complicated one?

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