获取函数的地址?? [英] get the address of a function??

问题描述

以下程序是否打印了该功能的地址？


void hello（）

{printf（" hello \ n"）;

}


void main（）

{

printf（" hello function =％ d \ n"，你好）;

}


请指教。谢谢....

解决方案

John说：

Is以下程序打印函数的地址？

void hello（）

{printf（" hello \ n）;

}


void main（）

{

printf（" hello function =％d \ n" ;，你好）;

}

程序的行为至少有三种方式未定义。所以 - 也许

它会做你想要的，也许它不会。也许它会做你想要的/ b / b它不会告诉你的其他东西。没办法告诉。


-

Richard Heathfield

Usenet是一个奇怪的地方 - dmr 29/7/1999
http://www.cpax.org.uk

电子邮件：rjh在上面的域名（但显然放弃了www）

Richard Heathfield写道：
< blockquote class =post_quotes>
John说：

>>以下程序是否打印了该函数的地址？ br />
void hello（）
{printf（" hello \ n"）;
}

void main（）
{
printf（" hello function =％d \ n"，hello）;
}

程序的行为至少在三个方面是不确定的。所以 - 也许

它会做你想要的，也许它不会。也许它会做你想要的/ b / b它不会告诉你的其他东西。没办法告诉。

有没有找到这三种方式的奖品？


-

Ian Collins。

文章< 4q ************ @ individual.net>，

Ian Collins< ia ****** @ hotmail.comwrote：

>>> void hello（）
{printf（" hello \\\
"）;
}



{
printf（" hello function =％d \ n"，hello）;
}

>程序的行为至少在三个方面是不确定的。所以 - 也许是

是否有奖励发现这三种方式？

否< stdio.h> ;, main（）声明中的两个错误，将

指针传递给printf（） ％d格式。尽管如此，它还是可以工作。


- 理查德

-

应考虑在一些字母表中需要多达32个字符

- 1963年的X3.4。

Is the following program print the address of the function?

void hello()
{ printf("hello\n");
}

void main()
{
printf("hello function=%d\n", hello);
}

please advice. thanks....

解决方案

John said:

Is the following program print the address of the function?

void hello()
{ printf("hello\n");
}

void main()
{
printf("hello function=%d\n", hello);
}

The behaviour of the program is undefined in at least three ways. So - maybe
it will do what you want, and maybe it won''t. Maybe it will do what you
want /and/ something else that it doesn''t tell you about. No way to tell.

--
Richard Heathfield
"Usenet is a strange place" - dmr 29/7/1999
http://www.cpax.org.uk
email: rjh at above domain (but drop the www, obviously)

Richard Heathfield wrote:

John said:

>>Is the following program print the address of the function?

void hello()
{ printf("hello\n");
}

void main()
{
printf("hello function=%d\n", hello);
}

The behaviour of the program is undefined in at least three ways. So - maybe
it will do what you want, and maybe it won''t. Maybe it will do what you
want /and/ something else that it doesn''t tell you about. No way to tell.

Is there a prize for spotting the three ways?

--
Ian Collins.

In article <4q************@individual.net>,
Ian Collins <ia******@hotmail.comwrote:

>>>void hello()
{ printf("hello\n");
}

void main()
{
printf("hello function=%d\n", hello);
}

>The behaviour of the program is undefined in at least three ways. So - maybe

Is there a prize for spotting the three ways?

No <stdio.h>, two errors in the declaration of main(), passing a
pointer to printf() with a %d format. And despite all that, it will
probably work.

-- Richard
--
"Consideration shall be given to the need for as many as 32 characters
in some alphabets" - X3.4, 1963.

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