strlen的 [英] strlen
问题描述
Hello All
我有一个2D数组，
char arr [4] [10] = {" Hello"， world，test，hi};
如何找到数组的strlen
我期待数组长度为4
感谢Adv
Hello All
I have a 2D array,
char arr[4][10] = {"Hello","world","test","hi"};
how can find the strlen of the array
am expecting array length as "4"
Thanks in Adv
推荐答案
" Imran" < IM ****** @ in.bosch.com>在消息中写道
news：cf ********** @ ns1.fe.internet.bosch.com ...
"Imran" <im******@in.bosch.com> wrote in message
news:cf**********@ns1.fe.internet.bosch.com...
Hello All
我有一个2D数组，
如何找到阵列的strlen
我希望数组长度为4
感谢Adv
Hello All
I have a 2D array,
char arr[4][10] = {"Hello","world","test","hi"};
how can find the strlen of the array
am expecting array length as "4"
Thanks in Adv
您的预期答案表明您确实在尝试确定多维数组的第一个维度。 strlen函数没有这样做。
这样做。在什么情况下你想确定这个？如果你在函数内部是
，那么你可能必须将第一个维度传递给
函数。例如：
void foo（char（* arr）[10]，int size）{
for（int i = 0; i< size ; ++ i）{
std :: cout<< arr [i]<< std :: endl;
}
}
int main（）{
char arr [4] [10] = {" Hello"，world，test，hi};
foo（arr，sizeof（arr）/ sizeof（arr [ 0]））;
返回0;
}
-
David Hilsee
Your expected answer indicates that you are really trying to determine the
first dimension of a multi-dimensional array. The strlen function does not
do this. In what context are you trying to determine this? If you''re
inside a function, then you may have to pass the first dimension to that
function. For example:
void foo(char (*arr)[10], int size) {
for ( int i = 0; i < size; ++i ) {
std::cout << arr[i] << std::endl;
}
}
int main() {
char arr[4][10] = {"Hello","world","test","hi"};
foo(arr,sizeof(arr)/sizeof(arr[0]));
return 0;
}
--
David Hilsee
" Imran" < IM ****** @ in.bosch.com>在消息新闻中写道：< cf ********** @ ns1.fe.internet.bosch.com> ...
"Imran" <im******@in.bosch.com> wrote in message news:<cf**********@ns1.fe.internet.bosch.com>...
Hello All
我有一个2D数组，
char arr [4] [10] = {" Hello"，world，test，hi};
<如何找到数组的strlen
我希望数组长度为4
Hello All
I have a 2D array,
char arr[4][10] = {"Hello","world","test","hi"};
how can find the strlen of the array
am expecting array length as "4"
当你''时有一种可能性真正使用数组（即不是一个
指针）就像：
#define elements（x）（（sizeof（x）/ sizeof （x [0]））
请记住，数组会随时衰减到指针
它作为参数传递，所以这实际上只能应用于
全局，或者在定义数组的函数内部。
-
后来，
杰瑞。
宇宙是自己想象的虚构。
One possibility when you''re truly working with an array (i.e. NOT a
pointer) is something like:
#define elements(x) ((sizeof(x)/sizeof(x[0]))
Keep in mind, however, that an array will decay to a pointer anytime
it is passed as a parameter, so this can really only be applied to
globals, or else inside of the function where the array is defined.
--
Later,
Jerry.
The universe is a figment of its own imagination.
这篇关于strlen的的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
