参考参考 [英] Reference to a reference

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问题描述



我正在阅读现代C ++设计,其中Anderi引用了C ++不允许

引用引用。


假设我有

DoThat(const string& strData2)

{

...

}


DoThis(const string& strData)

{

..

DoThat(strData) ;

}


int main()

{

字符串数据;

DoThis(数据);

}


现在我在DoThis里面的strData是对Data的引用。

strData2我有一个对strData.ie的引用strData2是一个参考

参考。

这里安德烈的声明让我感到困惑......我失去了什么?


谢谢,

Senthil

Hi,
I am reading Modern C++ Design where Anderi quoted "C++ does not allow
references to references".

Assume i have
DoThat(const string& strData2)
{
...
}

DoThis(const string& strData)
{
..
DoThat(strData);
}

int main()
{
string Data;
DoThis(Data);
}

Now the strData i have inside DoThis is a reference to Data.The
strData2 I have is a reference to strData.i.e strData2 is a reference
to a reference.
Here Andrei''s statement confuses me..Am i missing something?

Thanks,
Senthil

推荐答案

Senthil写道:
Senthil wrote:

我正在阅读现代C ++设计,其中Anderi引用C ++不允许
参考参考文献。

假设我有这个问题(const string& strData2)
{
...

DoThis(const string& strData)
{
..
DoThat (strData);
}
int main()
{
字符串数据;
DoThis(数据);
}

现在strData我在里面DoThis是对Data的引用。
strData2我有一个strData.ie引用strData2是一个参考
来引用。
这里安德烈的陈述使我感到困惑......我错过了什么?

谢谢,
Senthil
Hi,
I am reading Modern C++ Design where Anderi quoted "C++ does not allow
references to references".

Assume i have
DoThat(const string& strData2)
{
...
}

DoThis(const string& strData)
{
..
DoThat(strData);
}

int main()
{
string Data;
DoThis(Data);
}

Now the strData i have inside DoThis is a reference to Data.The
strData2 I have is a reference to strData.i.e strData2 is a reference
to a reference.
Here Andrei''s statement confuses me..Am i missing something?

Thanks,
Senthil




什么是上下文(部分编号和段落)?也许他的意思是

你不能用引用用指针做什么:


int anInt = 42;

int * pointer_to_int =& anInt;

int ** pointer_to_pointer_to_int =& pointer_to_int;


干杯! --M



What''s the context (section number and paragraph)? Perhaps he means
that you can''t do with references what you can do with pointers:

int anInt = 42;
int *pointer_to_int = &anInt;
int **pointer_to_pointer_to_int = &pointer_to_int;

Cheers! --M




Senthil写道:

Senthil wrote:

我正在读书现代C ++设计,其中Anderi引用了C ++不允许引用引用。

假设我有#That(const string& strData2)
{
...
}
DoThis(const string& strData)
{
..
DoThat(strData);
}

int main()
{
字符串数据;
DoThis(数据);
}
现在strData i有里面的DoThis是对Data的引用。
strData2我有一个对strData.ie strData2的引用是一个引用的参考。
这里你错了。 strData2是一个字符串的引用,根据

它的声明。

这里安德烈的声明让我很困惑......我错过了什么?
谢谢,
Senthil
Hi,
I am reading Modern C++ Design where Anderi quoted "C++ does not allow
references to references".

Assume i have
DoThat(const string& strData2)
{
...
}

DoThis(const string& strData)
{
..
DoThat(strData);
}

int main()
{
string Data;
DoThis(Data);
}

Now the strData i have inside DoThis is a reference to Data.The
strData2 I have is a reference to strData.i.e strData2 is a reference
to a reference. Here you are wrong. strData2 is a reference to a string according with
its declaration.
Here Andrei''s statement confuses me..Am i missing something?

Thanks,
Senthil




/ dan



/dan


Senthil写道:
Senthil wrote:

我正在阅读现代C ++设计,其中Anderi引用了C ++不允许引用引用。

假设我有
DoThat(const string& strData2)


根据声明,strData2是对const字符串的引用。

{
...

DoThis(const string& strData)


根据声明,strData是对const string的引用。 />
{
..
DoThat(strData);
}
int main()
{
字符串数据;
DoThis(数据);
}
现在我在DoThis里面的strData是对Data的引用。
strData2我有一个strData的引用。


这是对数据的引用。

即strData2是对引用的引用。
Hi,
I am reading Modern C++ Design where Anderi quoted "C++ does not allow
references to references".

Assume i have
DoThat(const string& strData2)
According to the declaration, strData2 is a reference to const string.
{
...
}

DoThis(const string& strData)
According to the declaration, strData is a reference to const string.
{
..
DoThat(strData);
}

int main()
{
string Data;
DoThis(Data);
}

Now the strData i have inside DoThis is a reference to Data.The
strData2 I have is a reference to strData.
It''s a refernce to Data.
i.e strData2 is a reference to a reference.




编号如果允许,对参考文献的引用将被声明为:


const string&& strData2



No. If allowed, a reference to a reference would be declared something like:

const string&& strData2


这篇关于参考参考的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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