发现错误...... [英] Spot the error...
问题描述
一位同事正在阅读一些C文章，并被问到以下代码中是否有任何错误
。我们都没有发现任何
问题，我已经用最严格的
设置用VC8和GCC编译了它并没有任何注意事项。
以下是代码：
#include< stdio.h>
void usage（char * ptCommand）;
int main（int argc，char * argv []）{
if（argc< 2）
用法（argv [0]）;
返回0;
}
无效用法（char * ptCommand）{< br $>
char usageInfo [1023];
_snprintf（usageInfo，1023，" Usage：％s \ n"，ptCommand）;
< br $> b $ b printf（usageInfo）;
}
谢谢。
A colleague is reading through some C articles and was asked if there
are any errors in the following code. Neither of us can spot any
issues, I have compiled it with VC8 and GCC at their strictest
settings and got nothing of note.
Here is the code:
#include <stdio.h>
void usage(char *ptCommand);
int main(int argc, char * argv[]) {
if (argc < 2)
usage(argv[0]);
return 0;
}
void usage(char *ptCommand) {
char usageInfo[1023];
_snprintf(usageInfo, 1023, "Usage: %s \n", ptCommand);
printf(usageInfo);
}
Thank you.
推荐答案
NwsGrp1写道：
NwsGrp1 wrote:
一位同事正在阅读一些C文章并被问到是否有
是以下代码中的任何错误。我们都没有发现任何
问题，我已经用最严格的
设置用VC8和GCC编译了它并没有任何注意事项。
以下是代码：
#include< stdio.h>
void usage（char * ptCommand）;
int main（int argc，char * argv []）{
if（argc< 2）
用法（argv [0]）;
返回0;
}
无效用法（char * ptCommand）{< br $>
char usageInfo [1023];
_snprintf（usageInfo，1023，" Usage：％s \ n"，ptCommand）;
A colleague is reading through some C articles and was asked if there
are any errors in the following code. Neither of us can spot any
issues, I have compiled it with VC8 and GCC at their strictest
settings and got nothing of note.
Here is the code:
#include <stdio.h>
void usage(char *ptCommand);
int main(int argc, char * argv[]) {
if (argc < 2)
usage(argv[0]);
return 0;
}
void usage(char *ptCommand) {
char usageInfo[1023];
_snprintf(usageInfo, 1023, "Usage: %s \n", ptCommand);
标准C中没有名为_snprintf的函数。
-
Ian Collins。
There isn''t a function called _snprintf in standard C.
--
Ian Collins.
NwsGrp1写于20/03/2007 11:44：
NwsGrp1 wrote on 20/03/2007 11:44:
一位同事正在阅读一些C文章和被问到以下代码中是否有任何错误
。我们都没有发现任何
问题，我已经用最严格的
设置用VC8和GCC编译了它并没有任何注意事项。
以下是代码：
#include< stdio.h>
void usage（char * ptCommand）;
int main（int argc，char * argv []）{
if（argc< 2）
用法（argv [0]）;
返回0;
}
无效用法（char * ptCommand）{< br $>
char usageInfo [1023];
_snprintf（usageInfo，1023，" Usage：％s \ n"，ptCommand）;
< br $> b $ b printf（usageInfo）;
}
谢谢。
A colleague is reading through some C articles and was asked if there
are any errors in the following code. Neither of us can spot any
issues, I have compiled it with VC8 and GCC at their strictest
settings and got nothing of note.
Here is the code:
#include <stdio.h>
void usage(char *ptCommand);
int main(int argc, char * argv[]) {
if (argc < 2)
usage(argv[0]);
return 0;
}
void usage(char *ptCommand) {
char usageInfo[1023];
_snprintf(usageInfo, 1023, "Usage: %s \n", ptCommand);
printf(usageInfo);
}
Thank you.
使用
printf（"％s"，usageInfo）
，以防ptCommand包含格式说明符。
Bavo
Use
printf("%s", usageInfo)
in case ptCommand contains format specifiers.
Bavo
NwsGrp1< nw ***** @ googlemail.comwrote：
NwsGrp1 <nw*****@googlemail.comwrote:
_snprintf（usageInfo，1023， "用途： ％s \ n"，ptCommand）;
_snprintf(usageInfo, 1023, "Usage: %s \n", ptCommand);
（我没有_snprintf（），但确实有snprintf（）。我说...... 4个人
是即将打电话给你。:)
至于错误，请查看：我将可执行文件命名为foo％s。而且当我跑的时候，
崩溃了。为什么？
-Beej
(I don''t have _snprintf(), but do have snprintf(). I say... 4 people
are about to call you on this one. :)
As for "errors", check this out: I named the executable "foo%s" and it
crashed when I ran it. Why?
-Beej
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