从我的数据填充计划并将其附加到表中 [英] Populating a schedule from my data and appending it to a table
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问题描述
我正在努力寻找能够帮助我编写代码的人，这样我就可以在随机事件过程中计算出天数....我有每个周期的天数，所需的周期数和开始日期。我必须能够通过单击CmdButton来填充计划。
这可能吗？任何人都可以建议任何其他方式做到这一点:)
请参阅附件数据库。
I have am trying to find someone who is able to help me write a code so i can calculate the ''days on'' in a course of random events.... I have the Number of days in each cycle, the number of cycles required and a start date. I have to be able to populate the schedule from clicking a CmdButton.
Is this possible? Can Anyone Suggest a way of doing it any other way :)
See the attached database.
推荐答案
不完全确定你的意思是什么，但如果你正在寻找
Not exactly sure what you mean by the above Statement, but if you are looking for
展开 | 选择 | Wrap | 行号
Even虽然在一个周期中可能有'n'个天数，但我想找到该周期中特定日期的日期...
例如：
在任何14天的周期中，我必须在第2天，第11天，第14天给妈妈打电话。我的第一个电话是在01/01/2010。我必须重复这个循环3次。所以....
周期日日期日期将附加到新表：
1 1 01/01/2010
1 2 02/01/2010 X
1 3 03/01/2010
1 4 04/01/2010
1 5 05 / 01/2010
1 6 06/01/2010
1 7 07/01/2010
1 8 08/01/2010
1 9 09/01/2010
1 10 10/01/2010
1 11 11/01/2010 X
1 12 12/01/2010
1 13 13/01/2010
1 14 2010年1月14日X
2 1 15/01/2010
2 2 16/01/2010 Y
2 3 17/01 / 2010
2 4 18/01/2010
2 5 19/01/2010
2 6 20/01/2010
2 7 21/01/2010
2 8 22/01/2010
2 9 23/01/2010
2 10 24/01/2010
2 11 25/01/2010 X
2 12 26/01/2010
2 13 27 / 01/2010
2 14 28/01/2010 X
3 1 29/01/2010
3 2 30/01/2010 X
3 3 31/01/2010
3 4 01/02 / 2010
3 5 02/02/2010 X
3 6 03/02/2010
3 7 04/02/2010
3 8 05/02/2010
3 9 06/02/2010
3 10 07/02/2010
3 11 08/02/2010 X
3 12 09/02/2010
3 13 10/02/2010
3 14 11 / 02/2010 X
Even though there may be ''n'' number of days in a cycle, i want to find the date for a specfic date in that cycle...
for example:
In any 14 day cycle, I have to phone my mum on day 2, day 11, day 14. My first phone call is on 01/01/2010. I have to repeat this cycle 3 times. So....
Cycle Day Date Dates to be Appended to new table:
1 1 01/01/2010
1 2 02/01/2010 X
1 3 03/01/2010
1 4 04/01/2010
1 5 05/01/2010
1 6 06/01/2010
1 7 07/01/2010
1 8 08/01/2010
1 9 09/01/2010
1 10 10/01/2010
1 11 11/01/2010 X
1 12 12/01/2010
1 13 13/01/2010
1 14 14/01/2010 X
2 1 15/01/2010
2 2 16/01/2010 Y
2 3 17/01/2010
2 4 18/01/2010
2 5 19/01/2010
2 6 20/01/2010
2 7 21/01/2010
2 8 22/01/2010
2 9 23/01/2010
2 10 24/01/2010
2 11 25/01/2010 X
2 12 26/01/2010
2 13 27/01/2010
2 14 28/01/2010 X
3 1 29/01/2010
3 2 30/01/2010 X
3 3 31/01/2010
3 4 01/02/2010
3 5 02/02/2010 X
3 6 03/02/2010
3 7 04/02/2010
3 8 05/02/2010
3 9 06/02/2010
3 10 07/02/2010
3 11 08/02/2010 X
3 12 09/02/2010
3 13 10/02/2010
3 14 11/02/2010 X
这绝对是''可能'' - 让我在脑海中解决逻辑问题，而且我LL拿出东西给你。请继续关注...
P.S. - 02/02/2010 不应该是结果集的一部分，是吗？
This is definitely ''possible'' - just let me work out the logic in my mind, and I''ll come up with something for you. Stay tuned...
P.S. - 02/02/2010 should not be part of the Result Set, should it?
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