你能告诉我代码是那样的吗？ [英] can you tell that y the code is work like that
问题描述
int * p = 20;
printf（"％d"，* p）;
printf（"％d"，p）;
以上代码将输出打印为
somegarbage value // for * p（可能是地址
20 // for p
为什么你能解释
感谢你
venkatesh，le 2005年10月21日，écrit：int * p = 20;
printf（"％d"，* p）;
printf（"％d" ，p）;
上面的代码打印输出为
somegarbage值//为* p（可能是地址
20 //为了p
你为什么可以解释
谢谢你
int dummy = 20;
int * p =& dummy;
printf（"％d \ nn"，* p）;
printf（"％p\ n"，p）;
或
int * p = malloc（sizeof int）;
* p = 20;
printf（" ％d \ n"，* p）;
printf（"％p \ n"，p）;
-
Pierre Maurette
venkatesh< pv *********** @ gmail.com>写道：
int * p = 20;
破碎。是什么让你怀疑20是一个指向整数的
指针的适当值？
printf（"％d"，* p）;
破碎。你认为具有值20的指针究竟是什么意思
指向？
printf（"％d"，p）;
破碎。指向整数的指针大小不必等于
sizeof（int）。
printf（"％p"，（void *） p）;
为什么你能解释
纯粹的随机机会，就C标准而言。
-
Christopher Benson-Manica |我*应该*知道我在说什么 - 如果我
ataru（at）cyberspace.org |不，我需要知道。火焰欢迎。
venkateshaécrit：int * p = 20;
这有点胡说八道。您认为它意味着什么？
初始化指向对象的指针的便携方式是
- NULL
- 相同类型对象的地址
- malloc返回的值（）
- 如果类型为void，则返回fopen（）返回的值*或者文件*
和类似的情况。
但是用
语言初始化一个带有普通整数的指针是不明确的。实际上，它可能适用于特定平台。它被称为
依赖于实现的行为。
-
C是一个敏锐的工具
int *p=20;
printf("%d",*p);
printf("%d",p);
the above code prints the output as
somegarbage value //for *p(may be address
20 //for p
why can you explain
thanks for that
venkatesh, le 21/10/2005, a écrit :int *p=20;
printf("%d",*p);
printf("%d",p);
the above code prints the output as
somegarbage value //for *p(may be address
20 //for p
why can you explain
thanks for that
int dummy = 20;
int* p = &dummy;
printf("%d\n",*p);
printf("%p\n",p);
or
int* p = malloc(sizeof int);
*p = 20;
printf("%d\n",*p);
printf("%p\n",p);
--
Pierre Maurette
venkatesh <pv***********@gmail.com> wrote:
int *p=20;
Broken. What makes you suspect that 20 is an appropriate value for a
pointer to an integer?
printf("%d",*p);
Broken. What exactly do you think a pointer with the value 20 might
point to?
printf("%d",p);
Broken. The size of a pointer to an integer need not be equal to
sizeof(int).
printf( "%p", (void*)p );
why can you explain
Pure random chance, as far as the C standard is concerned.
--
Christopher Benson-Manica | I *should* know what I''m talking about - if I
ataru(at)cyberspace.org | don''t, I need to know. Flames welcome.
venkatesh a écrit :int *p=20;
This is kinda nonsense. What to you think it meant ?
The portable way of initializing a pointer to an object are
- NULL
- The address of an object of the same type
- the value returned by malloc()
- the value returned by fopen() if the type is void* or FILE*
and similar cases.
But initialising a pointer with a plain integer is undefined by the
language. Actually, it may work on a specific platform. It''s called an
implementation-dependent behaviour.
--
C is a sharp tool
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