枚举和随机数 [英] Enumerations And Random Numbers
问题描述
我有一个基本的问题，一直在唠叨我，但我从来没有抽出时间来讨论它。
如果我有一个这样的枚举
Fiend Enum TravelDirection
北
南
东
West < br $>
结束枚举
和
方向= TravelDirection
现在我要设置方向随机到一个TravelDirection枚举
值
如果我知道我的枚举在1到4之间我可以很容易地得到一个新的随机
可以做到，我有，但我正在寻找最简单的解决方案。
doesent似乎是枚举的Max属性。
如果这听起来很愚蠢，那么我就会道歉
-
OHM（Terry Burns）*使用以下内容给我发电子邮件*
Dim ch （）作为Char =" ufssz / cvsotAhsfbuTpmvujpotXjui / OFU" .ToCharArray（）
For i As Int32 = 0 to ch.Length - 1
ch（i）= Convert.ToChar（Convert.ToInt16（ch（i）） - 1）
Next
Process.Start（" mailto："& New String（ch） ）
-
I have a basic question thats been niggling me, but I never found time to
look at it before.
If I have an enumeration such as this
Fiend Enum TravelDirection
North
South
East
West
End Enum
and
Direction = TravelDirection
Now I want to set the Direction Randomly to one of the TravelDirection enum
values
If I know that my enum is between 1 and 4 I can easily get a new random
number and assign it, however, As I add to the enumeration, I wont want to
worry about coding all the changes, so how could I easily do this I know I
can do it, and I have but Im looking for the most simple solution. There
doesent seem to be a Max property for enumerations.
If this sounds dumb, then I appologise
--
OHM ( Terry Burns ) * Use the following to email me *
Dim ch() As Char = "ufssz/cvsotAhsfbuTpmvujpotXjui/OFU".ToCharArray()
For i As Int32 = 0 To ch.Length - 1
ch(i) = Convert.ToChar(Convert.ToInt16(ch(i)) - 1)
Next
Process.Start("mailto:" & New String(ch))
--
推荐答案
嗨特里，
是否有理由认为你这样做对我来说很困难？我想我
错过了什么。
环境滴答计的最后位置+ 5除以5的两倍应该是我的b $ b意见诀窍。
Cor
单手男子（OHM - Terry Burns） < news.microsoft.com>
Hi Terry,
Is there a reason that it seems that you do it for me difficult? I think I
miss something.
Two times the last position of environment tickcount + 5 divided by 5 should
in my opinion do the trick.
Cor
"One Handed Man ( OHM - Terry Burns )" <news.microsoft.com>
我有一个基本的问题，一直在唠叨我，但我从来没有时间去看它。
如果我有一个这样的枚举
Fiend Enum TravelDirection
North
South
东
West
End Enum
和
方向= TravelDirection
现在我想将方向随机设置为其中一个TravelDirection
枚举值
<如果我知道我的枚举在1到4之间，我可以轻松获得一个新的随机数字并分配它，但是，正如我添加到枚举中，我不想担心编码所有的变化，所以我怎么能轻易做到这一点我知道
我能做到，我有，但我正在寻找最简单的解决方案。在那里
doesent似乎是枚举的Max属性。
如果这听起来很愚蠢，那么我就会道歉
> -
OHM（Terry Burns）*使用以下内容给我发电子邮件*
Dim ch（）As Char =" ufssz / cvsotAhsfbuTpmvujpotXjui / OFU" .ToCharArray（）
对于我因为Int32 = 0到ch.Length - 1
ch（i）= Convert.ToChar（Convert.ToInt16（ch（i）） - 1）
下一步
Process.Start （" mailto："& New String（ch））
-
I have a basic question thats been niggling me, but I never found time to
look at it before.
If I have an enumeration such as this
Fiend Enum TravelDirection
North
South
East
West
End Enum
and
Direction = TravelDirection
Now I want to set the Direction Randomly to one of the TravelDirection
enum values
If I know that my enum is between 1 and 4 I can easily get a new random
number and assign it, however, As I add to the enumeration, I wont want to
worry about coding all the changes, so how could I easily do this I know
I can do it, and I have but Im looking for the most simple solution. There
doesent seem to be a Max property for enumerations.
If this sounds dumb, then I appologise
--
OHM ( Terry Burns ) * Use the following to email me *
Dim ch() As Char = "ufssz/cvsotAhsfbuTpmvujpotXjui/OFU".ToCharArray()
For i As Int32 = 0 To ch.Length - 1
ch(i) = Convert.ToChar(Convert.ToInt16(ch(i)) - 1)
Next
Process.Start("mailto:" & New String(ch))
--
" One Handed Man（ OHM - Terry Burns） < news.microsoft.com> schrieb：
"One Handed Man ( OHM - Terry Burns )" <news.microsoft.com> schrieb:
如果我有一个这样的枚举
Fiend Enum TravelDirection
North
South
东
West 结束枚举
方向= TravelDirection
现在我想将方向随机设置为其中一个TravelDirection
枚举值
如果我知道我的枚举在1到4之间，我可以很容易地得到一个新的随机数字并分配它，但是，当我添加到枚举时，我不想要
担心编码所有的变化，所以我怎么能轻松地做到这一点我知道
我能做到，我有但我正在寻找最简单的解决方案。
If I have an enumeration such as this
Fiend Enum TravelDirection
North
South
East
West
End Enum
and
Direction = TravelDirection
Now I want to set the Direction Randomly to one of the TravelDirection
enum values
If I know that my enum is between 1 and 4 I can easily get a new random
number and assign it, however, As I add to the enumeration, I wont want to
worry about coding all the changes, so how could I easily do this I know
I can do it, and I have but Im looking for the most simple solution.
\\\
Dim Values（）As AnchorStyles = [Enum] .GetValues（GetType（AnchorStyles））
Dim r As新随机
MsgBox（值（r.Next（0，Values.Length - 1））。ToString（））
///
-
Herfried K. Wagner [MVP]
< ;网址：http：//dotnet.mvps.org/>
\\\
Dim Values() As AnchorStyles = [Enum].GetValues(GetType(AnchorStyles))
Dim r As New Random
MsgBox(Values(r.Next(0, Values.Length - 1)).ToString())
///
--
Herfried K. Wagner [MVP]
<URL:http://dotnet.mvps.org/>
" One Handed Man（OHM - 特里伯恩斯） < news.microsoft.com>写了
"One Handed Man ( OHM - Terry Burns )" <news.microsoft.com> wrote
我有一个基本的问题，一直在唠叨我，但我以前没有时间看过它。
如果我有这样的枚举
Fiend Enum TravelDirection
北
南
东西
结束枚举
和
方向= TravelDirection
应该是：
方向= TravelDirection.East
或其他一些特定值。你无法将
整个枚举分配给变量。
现在我想将方向随机设置为其中一个TravelDirection枚举
价值
如果我知道我的枚举在1到4之间，我可以轻松获得一个新的随机数字并分配它，但是，当我添加到枚举时，我不想<担心编码所有的变化，所以我怎么能轻松地做到这一点我知道我可以做到这一点，我有但我正在寻找最简单的解决方案。
doesent似乎是枚举的Max属性。
为什么不使用其中一个值？
东
West
MaxDirection = West End Enum
I have a basic question thats been niggling me, but I never found time to
look at it before.
If I have an enumeration such as this
Fiend Enum TravelDirection
North
South
East
West
End Enum
and
Direction = TravelDirection
That should be:
Direction = TravelDirection.East
Or some other specific value. You wouldn''t be able to assign the
entire enum to a variable.
Now I want to set the Direction Randomly to one of the TravelDirection enum
values
If I know that my enum is between 1 and 4 I can easily get a new random
number and assign it, however, As I add to the enumeration, I wont want to
worry about coding all the changes, so how could I easily do this I know I
can do it, and I have but Im looking for the most simple solution. There
doesent seem to be a Max property for enumerations.
Why not use one of the values?
East
West MaxDirection = West End Enum
LFS
LFS
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