如何使用此逻辑应用于我的代码？ [英] How to use this logic to apply to my code?
问题描述
目前我需要帮助解决这段代码的问题，但是我需要利用相同的逻辑将我的数据发送到actionscripts，这样我该怎么办？
这是代码逻辑：
[PHP]
<？php
$ sqlconnect = mysql_connect（" ; localhost"，" hyperian_tr ack"，" gsmtrack"）;
if（！$ sqlconnect）
die（mysql_error（））;
mysql_select_db（" hyperian_track"，$ sqlconnect）;
$ fetched = mysql_query（" SELECT * FROM location"）;
while（$ row = mysql_fetch_array（$ fetched））
{
$ temp [] = $ row [uname];
}
$ names = sizeof（$ temp）;
$ report =" total = $ names&";
foreach（$ temp as $ list）
$ report。=" name"。$ names - 。" ="。$ list。"& ;" ;;
echo $ report;
mysql_close（$ con）;
？>
[/ PHP]
正如你可以看到这部分代码reallx令人困惑： $ report。=" name"。$ names - 。" ="。$ list。"&"; 但我想做同样的方法所以我如何在我的代码中执行此操作我需要将uid和uname发送到下面的动作脚本是我的代码：
[PHP]
<？php
$ temp ="" ;;
$ sqlconnect = mysql_connect（" localhost"，" hyperian_tr ack"，" gsmtrack"）;
if（！$ sqlconnect）
die（mysql_error（））;
mysql_select_db（" ; hyperian_track"，$ sqlconnect）;
if（$ _ GET [''postal'']））
$邮递区号= SUBSTR（$ _ GET [ '' 邮政 '']，0,2）; //将从0位置返回2个字符
$ resultpostal = mysql_query（" SELECT location.uname，location.uid FROM location，district WHERE districts.districtno =''"。 $ postalcode。"''AND
location.lat BETWEEN districts.startlat AND districts.endlat AND location.lng BETWEEN districts.startlng AND districts.endlng"）;
if（$ row = mysql_fetch_array（$ resultpostal））
{
$ temp [] = $ row [uid];
$ temp1 [] = $ row [uname];
}
foreach（$ temp as $ result）< br $>
$ report。="
foreach（$ temp1 as $ result）
$ report。="
echo $ report;
} // if循环结束
mysql_close（$ con）;
[/ PHP]
我创建的代码2 temp接受uid和uname但是我如何从这里继续发送到actionscripts？
foreach（$ temp as $ result）
$ report。="
foreach（$ temp1 as $结果）
$ report。="
echo $ report;
sqlconnect = mysql_connect（" localhost"，" hyperian_tr ack"，" gsmtrack"）;
if（！
sqlconnect）
die（mysql_error（））;
mysql_select_db（" hyperian_track"，
sqlconnect）;
need help with this code currently I understand abit of what this code is doing but I need to make use of the same logic to send my data to actionscripts so how do I do it?
This is the code logic:
[PHP]
<?php
$sqlconnect=mysql_connect("localhost","hyperian_tr ack","gsmtrack");
if(!$sqlconnect)
die(mysql_error());
mysql_select_db("hyperian_track", $sqlconnect);
$fetched=mysql_query("SELECT * FROM location");
while($row = mysql_fetch_array($fetched))
{
$temp[]=$row[uname];
}
$names=sizeof($temp);
$report="total=$names&";
foreach($temp as $list)
$report.="name".$names--."=".$list."&";
echo $report;
mysql_close($con);
?>
[/PHP]
As you can see this part of the code is reallx confusing: $report.="name".$names--."=".$list."&"; but I want to do the same method so how do I do it in my code I need the uid and uname to be send to actionscript below is my code currently:
[PHP]
<?php
$temp="";
$sqlconnect=mysql_connect("localhost","hyperian_tr ack","gsmtrack");
if(!$sqlconnect)
die(mysql_error());
mysql_select_db("hyperian_track", $sqlconnect);
if($_GET[''postal'']))
$postalcode=substr($_GET[''postal''],0,2); //will return from 0 position 2 characters
$resultpostal=mysql_query("SELECT location.uname,location.uid FROM location,districts WHERE districts.districtno = ''".$postalcode."'' AND
location.lat BETWEEN districts.startlat AND districts.endlat AND location.lng BETWEEN districts.startlng AND districts.endlng");
if($row = mysql_fetch_array($resultpostal))
{
$temp[]=$row[uid];
$temp1[]=$row[uname];
}
foreach($temp as $result)
$report.="
foreach($temp1 as $result)
$report.="
echo $report;
}//end of if loops
mysql_close($con);
[/PHP]
My code I created 2 temp to take in the uid and uname but how do I continue from this part here to send it to actionscripts?
foreach($temp as $result)
$report.="
foreach($temp1 as $result)
$report.="
echo $report;
sqlconnect=mysql_connect("localhost","hyperian_tr ack","gsmtrack");
if(!
sqlconnect)
die(mysql_error());
mysql_select_db("hyperian_track",
sqlconnect);
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