基本的c / o和EOF [英] basic c i/o and EOF

问题描述

下面是我编写的代码，用于计算输入的字符数.I

假设EOF为-1，所以如果我输入-1然后按回车不应该

程序结束？如果我在while循环中输入类似''q'的东西，那么它就会结束循环。


是什么东西？


< code>


#include< stdio.h>


void main（）{


long nc;


nc = 0;

while（getchar（）！=''EOF''） {

++ nc;

}

printf（"％ld \ n"，nc）;


}


< / code>


谢谢

Dave

Below is the code ive written just to count the characters typed in. I
assumed EOF is -1, so if i type -1 and then press enter shouldnt the
program end? It orks if i put something like ''q'' in the while loop to
end the loop.

what is up?

<code>

#include <stdio.h>

void main() {

long nc;

nc = 0;
while (getchar() != ''EOF'') {
++nc;
}
printf("%ld\n", nc);

}

</code>

thanks
Dave

推荐答案

" Dave" <无***** @ noemail.com> skrev i meddelandet

新闻：bj ********** @ titan.btinternet.com ...

"Dave" <no*****@noemail.com> skrev i meddelandet
news:bj**********@titan.btinternet.com...

以下是我编写的代码输入的字符.I
假设EOF是-1，所以如果我输入-1然后按回车，
程序结束了吗？

Below is the code ive written just to count the characters typed in. I
assumed EOF is -1, so if i type -1 and then press enter shouldnt the
program end?

不，因为当你输入-1时，它不会被存储为一个角色，而是两个

个字符'' - ''和''1'。 -1然而是一个单个字符，而那两个

值并不匹配。


但是，你可以自己做一个测试，并检查一系列字母。

你应该很容易做到。我相信理论是将所有

输入字符放入一个数组中，并检查

数组中的最后两个字符是否等于'' - ''和''1'。


-

Tim Cambrant

< tim at cambrant dot com>

No, because when you type -1 it isn''t stored as a character, but two
characters ''-'' and ''1''. ''-1'' however is a single character, and those two
values doesn''t match.

However, you could do a test yourself, and check for a series of letters.
Should be quite easy for you to do. I believe the theory is to put all the
input characters into an array, and check if the last two characters in the
array is equal to ''-'' and ''1''.

--
Tim Cambrant
<tim at cambrant dot com>

2003年9月11日星期四，格林威治标准时间15:09:58，Tim Cambrant < ti*@cambrant.com.net>写道：

On Thu, 11 Sep 2003 15:09:58 GMT, "Tim Cambrant" <ti*@cambrant.com.net> wrote:

" Dave" <无***** @ noemail.com> skrev i meddelandet
新闻：bj ********** @ titan.btinternet.com ...

"Dave" <no*****@noemail.com> skrev i meddelandet
news:bj**********@titan.btinternet.com...

下面是我编写的代码，用于计算输入的字符数我假设EOF是-1，所以如果我输入-1然后按回车，
程序结束了吗？

Below is the code ive written just to count the characters typed in. I
assumed EOF is -1, so if i type -1 and then press enter shouldnt the
program end?

不，因为当你输入时 - 1它不是作为一个角色存储的，而是两个
字符 - 和1。 ''-1''然而是一个单个字符，而且这两个值不匹配。

然而，你可以自己做一个测试，并检查一系列字母。
你应该很容易做到。我相信理论是将所有
输入字符放入一个数组中，并检查
数组中的最后两个字符是否等于'' - ''和''1'。

No, because when you type -1 it isn''t stored as a character, but two
characters ''-'' and ''1''. ''-1'' however is a single character, and those two
values doesn''t match.

However, you could do a test yourself, and check for a series of letters.
Should be quite easy for you to do. I believe the theory is to put all the
input characters into an array, and check if the last two characters in the
array is equal to ''-'' and ''1''.

或者更好的是，如果您的平台支持它，请输入用于表示输入数据结束信号的密钥或密钥组合

。 />

在基于MSDOS的系统上，这将是^ Z键组合

在基于Unix的系统上，这将是组合产生''eof'的原因'

信号（通常是^ D，但请检查你的stty设置以确定）。

-

Lew Pitcher

企业技术解决方案IT顾问

多伦多道明银行金融集团


（表达的意见是我自己的，而不是我的雇主''） >

Or better yet, if your platform supports it, enter the key or key combination
that signals end-of-input-data.

On MSDOS-based systems, this would be the ^Z key combination
On Unix-based systems, this would be what ever combination generates the ''eof''
signal (typically ^D, but check your stty settings to be sure).
--
Lew Pitcher
IT Consultant, Enterprise Technology Solutions
Toronto Dominion Bank Financial Group

(Opinions expressed are my own, not my employers'')

Dave< no ***** @ noemail.com>写道：

Dave <no*****@noemail.com> wrote:

下面是我编写的代码，用于计算输入的字符数.I
假设EOF为-1，所以如果我输入-1然后按Enter键
程序结束了吗？
已经在其他回复中解决过了。

如果我在while循环中输入类似q的内容来结束循环，那么它就可以了。

< code>

#include< stdio.h>

void main（）{
int main（void）{

long nc;

nc = 0;
while（getchar（）！=''EOF''）{
^^^^^

非法字符常量，只需写入EOF（在stdio.h中定义）

++ nc;
}
printf（"％ld \ n"，nc）;

返回0;}

< / code>
AFAIK实现定义如何通过

键盘生成EOF（例如Ctr-Z，Ctrl-C，Ctrl-D，...）。
谢谢
戴夫

Below is the code ive written just to count the characters typed in. I
assumed EOF is -1, so if i type -1 and then press enter shouldnt the
program end? Already addressed in the other replies.
It orks if i put something like ''q'' in the while loop to
end the loop.

what is up?

<code>

#include <stdio.h>

void main() { int main( void ) {

long nc;

nc = 0;
while (getchar() != ''EOF'') { ^^^^^
illegal character constant, just write EOF (it is defined in stdio.h)
++nc;
}
printf("%ld\n", nc);
return 0;}

</code> AFAIK it is implementation defined how to produce an EOF via the
keyboard (e.g. Ctr-Z, Ctrl-C, Ctrl-D, ... ).
thanks
Dave

问候


Irrwahn

-

闭上眼睛，按三次逃生。

Regards

Irrwahn
--
Close your eyes and press escape three times.

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