铸件 [英] casting
问题描述
你好
我正在努力练习这个练习
******** ****************************************** ******** ************
定义一个浮点变量。获取其地址，将该地址转换为
unsigned char，并将其分配给unsigned char指针。使用这个
指针和[]，索引到float变量并使用本章定义的
printBinary（）函数打印出一张地图
$ b float的$ b（从0到sizeof（float））。更改
浮点数的值，看看你是否可以找出正在进行的内容（浮动
包含编码数据）。
printBinary.cpp是
#include" printBinary.h"
#include< iostream>
using namespace std;
void printBinary（const unsigned char val）{
for（int i = 7; i> = 0; i--）
if（val&（1<< i））
cout<< " 1" ;;
else
cout<< 0;
}
************************ ****************************** ********************
我的初始代码输出如下错误如下
****************** ************代码**************** **************
#include< iostream>
#include" ../ printBinary.h"
using namespace std;
int main（）{
float f = 3.3;
unsigned char * ucp =（unsigned char）& f;
for（int i = 0; i< sizeof（f）; ++ i）{
ucp [i] = i;
printBinary（ f [i]）;
}
}
********** ********************错误*************** ************** *
main.cpp：在函数`int main（）''中：
main.cpp：8：警告：从指针转换为不同大小的整数
main.cpp：8：错误：从`unsigned char''无效转换为`unsigned char *''
main.cpp ：12：错误：无效类型`float [int]''对于数组下标
make：*** [main.o]错误1
make：目标`proj1 ''因为错误而没有重新制作。
Hello
I am struggling with this exercise
************************************************** ********************
Define a float variable. Take its address, cast that address to an
unsigned char, and assign it to an unsigned char pointer. Using this
pointer and [ ], index into the float variable and use the
printBinary( ) function defined in this chapter to print out a map
of the float (go from 0 to sizeof(float)). Change the value of the
float and see if you can figure out what\u2019s going on (the float
contains encoded data).
the printBinary.cpp is
#include "printBinary.h"
#include <iostream>
using namespace std;
void printBinary(const unsigned char val) {
for(int i = 7; i >= 0; i--)
if(val & (1 << i))
cout << "1";
else
cout << "0";
}
************************************************** ********************
my initial code which puts out the error below is as follows
******************************code**************** **************
#include <iostream>
#include "../printBinary.h"
using namespace std;
int main(){
float f = 3.3;
unsigned char* ucp = (unsigned char) &f;
for (int i = 0; i < sizeof(f); ++i){
ucp[i] = i;
printBinary(f[i]);
}
}
******************************error*************** ***************
main.cpp: In function `int main()'':
main.cpp:8: warning: cast from pointer to integer of different size
main.cpp:8: error: invalid conversion from `unsigned char'' to `unsigned char*''
main.cpp:12: error: invalid types `float[int]'' for array subscript
make: *** [main.o] Error 1
make: Target `proj1'' not remade because of errors.
推荐答案
" Baloff" < WA **** @ wash.edu>在留言新闻中写道：87 ************ @ wash.edu ...
"Baloff" <wa****@wash.edu> wrote in message news:87************@wash.edu...
你好
我正在努力这个练习
***************************************** ********** ********************
定义一个浮点变量。获取其地址，将该地址转换为
unsigned char，并将其分配给unsigned char指针。使用这个
指针和[]，索引到float变量并使用本章定义的
printBinary（）函数打印出float的地图（从0到sizeof（浮动））。更改
浮动的值，看看你是否可以弄清楚正在进行的内容（浮动
包含编码数据）。
printBinary.cpp是
#include" printBinary.h"
#include< iostream>
using namespace std;
void printBinary（const unsigned char val）{
for（int i = 7; i> = 0; i--）
if（val&（1<< i））
cout<< 1;
其他
cout<< 0;
}
******************************** ****************** ********************
我的初始代码推出以下错误如下
******************************代码*** ************* **************
#include< iostream>
#include" ../ printBinary。 h
使用命名空间std;
int main（）{
float f = 3.3;
unsigned char * ucp =（unsigned char）& ; f;
for（int i = 0; i< sizeof（f）; ++ i）{
ucp [i] = i;
printBinary（f [我]）;
}
}
************************ ******错误*************** ***************
main.cpp：在函数`int main中（）''：
main.cpp：8：警告：从指针强制转换为不同大小的整数
main.cpp：8：错误：从`unsigned char''无效转换为`unsigned
char *''
main.cpp：12：错误：无效类型`float [int]''对于数组下标
make：*** [ma in.o]错误1
make：目标`proj1''因错误而未重新制作。
Hello
I am struggling with this exercise
************************************************** ********************
Define a float variable. Take its address, cast that address to an
unsigned char, and assign it to an unsigned char pointer. Using this
pointer and [ ], index into the float variable and use the
printBinary( ) function defined in this chapter to print out a map
of the float (go from 0 to sizeof(float)). Change the value of the
float and see if you can figure out what\u2019s going on (the float
contains encoded data).
the printBinary.cpp is
#include "printBinary.h"
#include <iostream>
using namespace std;
void printBinary(const unsigned char val) {
for(int i = 7; i >= 0; i--)
if(val & (1 << i))
cout << "1";
else
cout << "0";
}
************************************************** ********************
my initial code which puts out the error below is as follows
******************************code**************** **************
#include <iostream>
#include "../printBinary.h"
using namespace std;
int main(){
float f = 3.3;
unsigned char* ucp = (unsigned char) &f;
for (int i = 0; i < sizeof(f); ++i){
ucp[i] = i;
printBinary(f[i]);
}
}
******************************error*************** ***************
main.cpp: In function `int main()'':
main.cpp:8: warning: cast from pointer to integer of different size
main.cpp:8: error: invalid conversion from `unsigned char'' to `unsigned
char*''
main.cpp:12: error: invalid types `float[int]'' for array subscript
make: *** [main.o] Error 1
make: Target `proj1'' not remade because of errors.
制作：
#include< iostream>
#include" ../ printBinary.h"
using namespace std;
int main（）{
float f = 3.3;
unsigned char * ucp =（unsigned char *）& f;
for（int i = 0;我<的sizeof（F）; ++ i）{
printBinary（ucp [i]）; //将float的每个字节打印为二进制
}
}
Make it:
#include <iostream>
#include "../printBinary.h"
using namespace std;
int main(){
float f = 3.3;
unsigned char* ucp = (unsigned char*) &f;
for (int i = 0; i < sizeof(f); ++i){
printBinary(ucp[i]); // Print each byte of float as binary
}
}
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