ARGV [英] Argv
问题描述
我正在尝试创建一个字符数组数组。我会使用字符串，
但是我需要输入的函数看起来像这样
int execve（const char * filename，char * const argv [] ，char * const
envp []）。我知道这不是一个C ++函数，我只询问如何创建像这样的函数实际可以接受的东西。
我不会知道字符数组（参数）的数量，直到
运行时，所以我需要使用new或calloc来完成这个。
我已成功将所有参数解析为字符串，并将它们放在一个漂亮的向量中。 （可能是一个不必要的步骤，但是嘿）
所以类似
make charray;
for（int i = 0; i< vector.size（）; i ++）{
chararray [i] [vector [i] .c_str（）];
}
返回会传递给上述功能的内容。
如果这看起来很奇怪，很抱歉。
感谢阅读。
一个疲惫的java人。
<峰; br **** @ gmail.com> schrieb im Newsbeitrag新闻：11 ********************** @ g10g2000cwb.googlegr oups.com ...我是试图创建一个字符数组数组。我会使用字符串，
但是我需要输入的函数看起来像这样的内容（const char * filename，char * const argv []，char * const
envp []）。我知道这不是一个C ++函数，我只询问如何创建像这样的函数实际可以接受的东西。
函数预期两个指向char的指针数组，而不是字符数组数组。类似
char ** argv = new char * [numberOfStrings + 1];
for（int i = 0; i< numberOfStrings; ++ i）
argv [i] = somePointerToNonConstCharacter（s）;
argv [numberOfStrings] = 0;
应该有帮助。
Heinz
我认为这可行：
char ** array ;
array = malloc（sizeof（char *）* NUMBER_OF_STRINGS）;
-------或-------
char * array [MAX_NUMBER_OF_STRINGS]; （如果你不喜欢这里的malloc :)
那么：
int i;
char buffer [1024 ];
fgets（char * s，int size，FILE * stream）;
for（i = 0; i< NUMBER_OF_STRINGS; i ++）
{
fgets（buffer，1024，stdin）; //得到第i个字符串
array [i] = malloc（sizeof（buffer））; //在
数组中创建新字符串
strcpy（array [i]，buffer）; //分配字符串
}
execve（blah，array，blah）; //传递数组
它有用吗？
对不起，我忘了这是clc ++ ，我在C回复：]抱歉！
I''m trying to create an array of character arrays. I would use strings,
but the function I need to feed into looks like this
int execve(const char *filename, char *const argv [], char *const
envp[] ). I know this is not a C++ function, and I only ask for how to
create something that a function like this will actually accept.
I will not know the amount of character arrays (arguments) until
runtime, so I need to use new or calloc to get this done.
I''ve successfully parsed all the arguments into strings, and placed
them in a nice vector. (Probably an unnecessary step, but hey)
so something like
make charray;
for(int i =0; i< vector.size(); i++){
chararray[i][vector[i].c_str()];
}
return something that will pass into the above function.
Sorry if this seems weird.
Thanks for Reading.
A tired java person.
<br****@gmail.com> schrieb im Newsbeitrag news:11**********************@g10g2000cwb.googlegr oups.com...I''m trying to create an array of character arrays. I would use strings,
but the function I need to feed into looks like this
int execve(const char *filename, char *const argv [], char *const
envp[] ). I know this is not a C++ function, and I only ask for how to
create something that a function like this will actually accept.
The function expects two arrays of pointers to char, not "arrays of character arrays". Something like
char** argv = new char*[numberOfStrings + 1];
for (int i = 0; i < numberOfStrings; ++i)
argv[i] = somePointerToNonConstCharacter(s);
argv[numberOfStrings] = 0;
should help.
Heinz
i think this can work:
char **array;
array = malloc(sizeof(char *) * NUMBER_OF_STRINGS);
-------or-------
char *array[MAX_NUMBER_OF_STRINGS]; (if you don''t like a malloc here :)
then:
int i;
char buffer[1024];
fgets(char *s, int size, FILE *stream);
for (i = 0; i < NUMBER_OF_STRINGS; i++)
{
fgets(buffer, 1024, stdin); // get the ith string
array[i] = malloc(sizeof(buffer)); // create new string in the
array
strcpy(array[i], buffer); // assign the string
}
execve(blah, array, blah); // pass the array
does it work?
Ops sorry, i forgot this was the c.l.c++, i replied in C :] Sorry!
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