的WebView - 无法下载文件，而无需请求了两次？ [英] WebView - can't download file without requesting it twice?

问题描述

如果我听与 DownloadListener ，我得到我需要请求的后，浏览器已经请求它的网址。浏览器已经打开到URL的连接（这是怎么知道这是一个下载），为什么不能把它传给我的连接？

If I listen with DownloadListener, I get the URL which I need to request after the browser already requested it. The browser already opened a connection to the URL (which is how it knows this is a download), why can't it pass me the connection?

我也试过分配一个自定义的 WebViewClient 到的WebView 和使用 shouldOverrideUrlLoading 赶上网址，他们被要求先。要下载文件的方式，我要求每一个URL浏览器之前和它的内容类型我决定是否下载与否，如果是那么我从本已打开的连接下载它，否则我关闭连接并指示浏览器加载它，浏览器...再次请求了。另外，在 shouldOverrideUrlLoading 我没有告诉哪种方法，我应该使用要求给定的URL是什么饼干。

I also tried to assign a custom WebViewClient to the WebView and use shouldOverrideUrlLoading to catch URLs before they are requested. To download files that way, I request every URL before the browser and by it's Content-Type I decide whether to download it or not, if it is then I download it from the already-opened connection, otherwise I close the connection and instruct the browser to load it, and the browser... requests it again. Plus, in shouldOverrideUrlLoading I'm not told which method and what cookies should I use to request the given URL.

我如何的没有的不必要请求两次，仍然能够下载文件的WebView？

How can I not unnecessarily request twice and still be able to download files with WebView?

推荐答案

为什么不直接使用的网址使用的OutputStream下载？下面是一个例子：

Why not just use the url to download it using outputstream? Here is an example:

private class DownloadFile extends AsyncTask<String, Integer, String> {
@Override
protected String doInBackground(String... sUrl) {
    try {
        URL url = new URL(sUrl[0]);
        URLConnection connection = url.openConnection();
        connection.connect();

        // download the file
        InputStream input = new BufferedInputStream(url.openStream());
        OutputStream output = new FileOutputStream("/sdcard/file_name.extension");

        byte data[] = new byte[1024];
        long total = 0;
        int count;
        while ((count = input.read(data)) != -1) {
            total += count;
            output.write(data, 0, count);
        }

        output.flush();
        output.close();
        input.close();
    } catch (Exception e) {
    }
    return null;
}

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