捕获浮动异常 [英] Catching floating exceptions
问题描述
我无法捕获浮动异常（例如除以0或0/0）
使用stdexcept中定义的标准异常。什么是b / b
推荐的捕获此类异常的方法？
谢谢，
歌
I am unable to catch floating exceptions (e.g. divide by 0 or 0/0)
using the standard exceptions defined in stdexcept. What is the
recommended way to catch such exceptions?
Thanks,
Song
推荐答案
us **** @ sta.samsung.com 写道：
我无法捕捉浮动异常（例如除以0或0/0）
使用在stdexcept。
建议的方法是什么来捕获这些例外？
I am unable to catch floating exceptions (e.g. divide by 0 or 0/0)
using the standard exceptions defined in stdexcept. What is the
recommended way to catch such exceptions?
你不能。至少在标准C ++中，可能存在平台特定扩展，但硬件生成的陷阱与
C ++语言异常不同。
-
Ian Collins。
You can''t. At least not in standard C++, there might be platform
specific extensions, but hardware generated traps are not the same as
C++ language exceptions.
--
Ian Collins.
< us **** @ sta.samsung.comwrote in message
新闻：11 ********************** @ p77g2000hsh.googlegr oups.com ...
<us****@sta.samsung.comwrote in message
news:11**********************@p77g2000hsh.googlegr oups.com...
>我无法捕获浮动异常（例如除以0或0/0）
使用stdexcept中定义的标准异常。
建议的方法是什么来捕获这些异常？
>I am unable to catch floating exceptions (e.g. divide by 0 or 0/0)
using the standard exceptions defined in stdexcept. What is the
recommended way to catch such exceptions?
问题是没有抛出异常？整数除以零将
抛出一个系统错误，一个浮点除以错误应返回
无穷大或负无穷大。考虑下面的程序我刚刚一起扔了
。可能有更好的方法，但我只是不确定它是什么。
#include< iostream>
#include< cfloat> ;
int main（）
{
浮点数零= 0.0f;
float Inf = 5.0f / Zero;
float NegInf = -5.0f / Zero;
float x = -5.0f;
float y = 0.0f;
float z = x / y;
std :: cout<< z<< " \ n";
if（z == Inf || z == -Inf）
std :: cout<< 除以零（无穷大）。 << " \ n";
返回0;
}
Is the problem that no exception is thrown? An integer divide by zero will
throw a system error, a floating point divide by error should return
infinity or negative infinity. Consider the following program I just threw
together. There is probably a better way, but I''m just not sure what it is.
#include <iostream>
#include <cfloat>
int main()
{
float Zero = 0.0f;
float Inf = 5.0f / Zero;
float NegInf = -5.0f / Zero;
float x = -5.0f;
float y = 0.0f;
float z = x/y;
std::cout << z << "\n";
if ( z == Inf || z == -Inf )
std::cout << "Division By Zero (infinity) " << "\n";
return 0;
}
us****@sta.samsung.com 写道：
us****@sta.samsung.com wrote:
我无法捕获浮动异常（例如除以0或0/0）
使用stdexcept中定义的标准异常。
建议的方法是什么来捕获这些异常？
I am unable to catch floating exceptions (e.g. divide by 0 or 0/0)
using the standard exceptions defined in stdexcept. What is the
recommended way to catch such exceptions?
你应该做的第一件事是决定你是用C ++编程
还是用D.
The first thing you should do is decide whether you are programming in C++
or in D.
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