删除POD数组 - 在哪些平台上不起作用？ [英] delete POD array - on which platforms does it not work?
问题描述
大家好！
char * p = new char [n]; // POD！
....
delete [] p; // std compliance
delete p; //将在VC8上工作
free（p）; //也适用于VC8
我对哪两个平台/编译器感兴趣，后两个语句
不起作用。 （访问违规或内存泄漏）。
谢谢！
br，
Martin
Hi all!
char* p = new char[n]; // POD!
....
delete[] p; // std compliant
delete p; // will work on VC8
free(p); // will also work on VC8
I am interested on which platforms/compilers the second two statements
would not work. (access violation or mem-leak).
thanks!
br,
Martin
推荐答案
Martin T.写道，On 2.4.2008 7:30：
Martin T. wrote, On 2.4.2008 7:30:
大家好！
char * p = new char [n]; // POD！
...
delete [] p; // std compliance
delete p; //将在VC8上工作
free（p）; //也适用于VC8
我对哪两个平台/编译器感兴趣，后两个语句
不起作用。 （访问违规或内存泄漏）。
Hi all!
char* p = new char[n]; // POD!
...
delete[] p; // std compliant
delete p; // will work on VC8
free(p); // will also work on VC8
I am interested on which platforms/compilers the second two statements
would not work. (access violation or mem-leak).
为什么重要？即使它编译和工作也是错误的C ++。
-
VH
Why does it matter? It is wrong C++ even if it compiles and works.
--
VH
On 2 huhti，08：30，Martin T. < 0xCDCDC ... @ gmx.atwrote：
On 2 huhti, 08:30, "Martin T." <0xCDCDC...@gmx.atwrote:
delete p; //将在VC8上工作
free（p）; //也适用于VC8
delete p; // will work on VC8
free(p); // will also work on VC8
你确定这些不会搞砸VC8中的任何东西吗？
无论如何这个问题是脑死。您对数组使用delete []
，而对new new使用free（）。
Are you sure these don''t mess up anything in VC8?
Anyway this question is braindead. You use delete[]
for arrays and never free() with operator new.
Krice写道：
Krice wrote:
On 2 huhti，08：30，Martin T. < 0xCDCDC ... @ gmx.atwrote：
On 2 huhti, 08:30, "Martin T." <0xCDCDC...@gmx.atwrote:
> delete p; //将在VC8上工作
free（p）; //也适用于VC8
>delete p; // will work on VC8
free(p); // will also work on VC8
你确定这些不会搞砸VC8中的任何东西吗？
Are you sure these don''t mess up anything in VC8?
是的，100％肯定。
Yes, 100% sure.
无论如何，这个问题是脑死亡。对数组使用delete []
，而对new new使用free（）。
Anyway this question is braindead. You use delete[]
for arrays and never free() with operator new.
这个问题非常有效。事实上它变得更有效了
这样的答案。我还可以改写它：
它（只）*真的*邪恶，或者有没有人知道它会为POD打破
的平台？
br，
Martin
This is question is quite valid. Indeed it becomes more valid with
answers such as this. I could also rephrase it:
Is it (just) *really* evil, or does anyone know of a platform where it
will break for PODs?
br,
Martin
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