我如何传递多个参数的网址是什么？ [英] How do I pass multiple parameter in URL?

问题描述

我试图找出如何在URL中传递多个参数。我想通过经度和纬度，从我的Andr​​oid类一个Java servlet。我该怎么办呢？

I am trying to figure out how to pass multiple parameters in a URL. I want to pass latitude and longitude from my android class to a java servlet. How can I do that?

URL url;
double lat=touchedPoint.getLatitudeE6() / 1E6;
double lon=touchedPoint.getLongitudeE6() / 1E6;
url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+lon);

在这种情况下，输出（写入文件）是28.53438677.472097。 这是工作，但我想通过经度和纬度在两个独立的参数，使我在服务器端的工作是减少。如果它是不可能的我怎么能至少增加纬度和放大器之间的空间; LON这样我就可以使用标记生成器类，让我的经度和纬度。我想下面的行，但无济于事。

In this case output (written to file) is 28.53438677.472097. This is working but I want to pass latitude and longitude in two separate parameters so that my work at server side is reduced. If it is not possible how can I at least add a space between lat & lon so that I can use tokenizer class to get my latitude and longitude. I tried following line but to no avail.

    url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+" "+lon);
output- Nothing is written to file
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"&?param2="+lon);
output- 28.534386 (Only Latitude)
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"?param2="+lon);
output- 28.532577?param2=77.502996

我的servlet code是如下：

My servlet code is as follows:

req.setCharacterEncoding("UTF-8");
resp.setCharacterEncoding("UTF-8");
final String par1 =  req.getParameter("param1");
final String par2 = req.getParameter("param2");
FileWriter fstream = new FileWriter("C:\\Users\\Hitchhiker\\Desktop\\out2.txt");
BufferedWriter out = new BufferedWriter(fstream);
out.write(par1);
out.append(par2);
out.close();

此外，我想在知道这是从Android设备将数据传递给服务器的最安全和最安全的方式。

Also I wanted to the know is this the most safe and secured way to pass the data from android device to server.

推荐答案

这

url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"&param2="+lon);

必须工作。不管出于什么奇怪的原因，你需要 第一个参数前，＆安培; 之前，下面的那些

must work. For whatever strange reason, you need ? before the first parameter and & before the following ones.

使用像

url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"_"+lon);

会的工作，太多，但肯定不是很好。不能使用空格那里，因为它是禁止的网址，但你可以连接code为％20 （但是这是更糟糕的风格）。

would work, too, but is surely not nice. You can't use a space there as it's prohibited in an URL, but you could encode it as %20 (but this is even worse style).

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