python会在线程中有信号处理程序吗？ [英] Will python ever have signalhandlers in threads?

问题描述

我已经看过信号模块和示例

并得出结论，示例不会工作

如果您尝试在线程中执行此操作。


那么类似的代码是否有机会在一个帖子中运行？


-

Antoon Pardon

解决方案

Op 2004-11-09，Antoon Pardon schreef< ap ***** @ forel.vub.ac.be>：< blockquote class =post_quotes>我已经看过信号模块和示例
并得出结论，如果您尝试在一个线程中执行此操作，该示例将无法工作。

那么类似的代码是否有可能在一个线程中起作用？

我想，缺乏响应意味着anser是：

不太可能。

可惜！


-

Antoon Pardon

Antoon Pardon写道：

Op 2004-11-09，Antoon Pardon schreef< ap ***** @ forel。 vub.ac.be>：

我看了一下信号模块和示例
并得出结论，如果你试图这个例子不会工作
这是一个线程。

那么类似的代码是否有可能在一个线程中工作？

我想，缺乏响应意味着anser是：

不太可能。

很抱歉，我没有时间浏览你提到的代码，但是最近

for ipython我不得不处理线程中的信号处理。如果你关心的话，你可以查看

IPython'的Shell.py来解决我最终使用的黑客攻击。


它的主旨是这个功能，安装到gtk / WX计时器：


def runco​​de（self）：

"""执行代码对象。 />

围绕IPython'的runco​​de（）的多线程包装。"""


＃锁定线程保护的东西

self.ready.acquire（）


＃安装sigint处理程序

signal.signal（signal.SIGINT，sigint_handler）


if self._kill：

print>> Term.cout，''关闭线程......''，

Term.cout。 flush（）

forkill in self.on_kill：

tokill（）

print>> Term.cout，''完成。 ''


＃通过调用父类运行挂起代码

如果self.code_to_run不是None：

self.ready。 notify（）

self.parent_runco​​de（self.code_to_run）

＃清除c已运行的ode对象

self.code_to_run =无


＃我们已完成线程保护变量

self.ready.release（）

＃必须返回true才能运行gtk线程

返回True


如你所见在锁定后，我最终在*每次*调用

函数时安装了处理程序。我无法找到如何将处理程序分配给线程的
，所以这是我的暴力方法。


这非常难看，而且可能有更好的解决方案。但是在这个具体的案例中，黑客的工作和最终用户的惩罚并不明显。


最好，


f

>我已经看过信号模块和示例

并得出结论，如果你尝试在一个线程中执行此操作，示例将无法工作。

我认为根据Posix Thread规范，信号只被删除到

这个过程，永远不会线程......我可能错了......


-

damjan

I have had a look at the signal module and the example
and came to the conclusion that the example wont work
if you try to do this in a thread.

So is there a chance similar code will work in a thread?

--
Antoon Pardon

解决方案

Op 2004-11-09, Antoon Pardon schreef <ap*****@forel.vub.ac.be>:

I have had a look at the signal module and the example
and came to the conclusion that the example wont work
if you try to do this in a thread.

So is there a chance similar code will work in a thread?

Well I guess that the lack of response means the anser is:

Not likely.
Pity!

--
Antoon Pardon

Antoon Pardon wrote:

Op 2004-11-09, Antoon Pardon schreef <ap*****@forel.vub.ac.be>:

I have had a look at the signal module and the example
and came to the conclusion that the example wont work
if you try to do this in a thread.

So is there a chance similar code will work in a thread?

Well I guess that the lack of response means the anser is:

Not likely.

Sorry that I don''t have time to go through the code you mention, but recently
for ipython I had to deal with signal handling in threads. You can look in
IPython''s Shell.py for the hacks I ended up using, if you care.

The gist of it is this function, which gets installed into a gtk/WX timer:

def runcode(self):
"""Execute a code object.

Multithreaded wrapper around IPython''s runcode()."""

# lock thread-protected stuff
self.ready.acquire()

# Install sigint handler
signal.signal(signal.SIGINT, sigint_handler)

if self._kill:
print >>Term.cout, ''Closing threads...'',
Term.cout.flush()
for tokill in self.on_kill:
tokill()
print >>Term.cout, ''Done.''

# Run pending code by calling parent class
if self.code_to_run is not None:
self.ready.notify()
self.parent_runcode(self.code_to_run)
# Flush out code object which has been run
self.code_to_run = None

# We''re done with thread-protected variables
self.ready.release()
# This MUST return true for gtk threading to work
return True

As you see, I ended up installing the handler on *every* invocation of the
function, after taking a lock. I couldn''t find how to assign the handler to
the thread, so this was my brute-force approach.

This is incredibly ugly, and there may be a better solution. But in this
particular case, the hack works and the penalty is not noticeable to end users.

Best,

f

> I have had a look at the signal module and the example

and came to the conclusion that the example wont work
if you try to do this in a thread.

So is there a chance similar code will work in a thread?

I think acording to the Posix Thread specs, signals are only delevered to
the process and never to threads... I could be wrong though...

--
damjan

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