从Python脚本调用C程序 [英] Calling a C program from a Python Script
问题描述
是否可以打开文件，然后用C读取程序然后
从这样的Python脚本中调用C程序：
os.walk（path）中的root，files，dirs
文件中的
：
尝试：
EXECUTE_C_PROGRAM
如果可能，这比纯Python解决方案快多少？
谢谢，
布拉德
Is it possible to write a file open, then read program in C and then
call the C program from a Python script like this:
for root, files, dirs in os.walk(path)
for f in files:
try:
EXECUTE_C_PROGRAM
If possible, how much faster would this be over a pure Python solution?
Thank you,
Brad
推荐答案
2004-12-09，Brad Tilley< br ******** @ gmail.com>写道：
On 2004-12-09, Brad Tilley <br********@gmail.com> wrote:
是否可以打开一个文件，然后在C中读取程序，然后从Python脚本中调用C程序，如下所示：
嗯？你的意思是写一个文件打开？你想阅读一个
C源文件并执行C源代码？如果您可以访问
一个C解释器，我猜你可以使用popen从
python调用解释器，并将C源提供给它。或者，你可以从C调用编译器和链接器生成一个
可执行文件，然后执行生成的文件。
for root，files，在os.walk（路径）dirs文件中的f：
尝试：
EXECUTE_C_PROGRAM
你将不得不解释清楚你是什么意思
" EXECUTE_C_PROGRAM"。如果你愿意，你当然可以运行一个从C源生成的
二进制可执行文件（例如，Linux下的一个/ b $ b ELF文件或者任何一个.exe文件。 Windows）。
如果可能的话，这比纯Python的解决方案要快多少？
Is it possible to write a file open, then read program in C and then
call the C program from a Python script like this:
Huh? What do you mean "write a file open"? You want to read a
C source file and execute the C source? If you have access to
a C interpreter, I guess you could invoke the interpreter from
python using popen, and feed the C source to it. Alternatively
you could invoke a compiler and linker from C to generate an
executable and then execute the resulting file.
for root, files, dirs in os.walk(path)
for f in files:
try:
EXECUTE_C_PROGRAM
You''re going to have to explain clearly what you mean by
"EXECUTE_C_PROGRAM". If you want to, you can certainly run a
binary executable that was generated from C source, (e.g. an
ELF file under Linux or whatever a .exe file is under Windows).
If possible, how much faster would this be over a pure Python
solution?
解决方案是什么？
-
格兰特爱德华兹格兰特哇！此外，我的保龄球平均价格为
visi.com无懈可击!!!
Solution to what?
--
Grant Edwards grante Yow! And furthermore,
at my bowling average is
visi.com unimpeachable!!!
Brad Tilley写道：
Brad Tilley wrote:
如果可能的话，这会比纯Python解决方案快多少？
If possible, how much faster would this be over a pure Python solution?
这就像蝙蝠侠的区别好的。
蝙蝠侠比以往更快
It is like the difference between Batman and Ever.
batman is faster than ever
Grant Edwards写道：
Grant Edwards wrote:
嗯？你的意思是写一个文件打开？你想阅读一个
C源文件并执行C源代码吗？如果你有权使用一个C解释器，我想你可以使用popen从
python调用解释器，并将C源提供给它。或者，你可以从C调用一个编译器和链接器来生成一个
可执行文件，然后执行生成的文件。
Huh? What do you mean "write a file open"? You want to read a
C source file and execute the C source? If you have access to
a C interpreter, I guess you could invoke the interpreter from
python using popen, and feed the C source to it. Alternatively
you could invoke a compiler and linker from C to generate an
executable and then execute the resulting file.
用于root，文件，在os.walk（路径）dirs文件中的f：
尝试：
EXECUTE_C_PROGRAM
for root, files, dirs in os.walk(path)
for f in files:
try:
EXECUTE_C_PROGRAM
你将不得不解释清楚你的意思是什么？
EXECUTE_C_PROGRAM。如果你愿意，你当然可以运行一个从C源生成的二进制可执行文件（例如，Linux下的ELF文件或Windows下的.exe文件）。
You''re going to have to explain clearly what you mean by
"EXECUTE_C_PROGRAM". If you want to, you can certainly run a
binary executable that was generated from C source, (e.g. an
ELF file under Linux or whatever a .exe file is under Windows).
看起来我被指责了。我的意思是一个C程序打开并读取
文件而Python做其他一切。如何将C集成到这样的
a Python脚本中？
所以，而不是这样：
for os.walk（路径）中的root，files，dirs文件中f的
：
尝试：
x = file（f，''' rb''）
data = x.read（）
x.close（）
这个：
for root，files，dirs in os.walk（path）
for f in files：
try：
EXECUTE_C_PROGRAM
来自辛普森一家：
Frink：这里我们有一个普通的广场。
Wiggum：哇！减慢蛋头！
Appears I was finger-tied. I meant "a C program that opens and reads
files" while Python does everything else. How does one integrate C into
a Python script like that?
So, instead of this:
for root, files, dirs in os.walk(path)
for f in files:
try:
x = file(f, ''rb'')
data = x.read()
x.close()
this:
for root, files, dirs in os.walk(path)
for f in files:
try:
EXECUTE_C_PROGRAM
From the Simpsons:
Frink: "Here we have an ordinary square."
Wiggum: "Whoa! Slow down egghead!"
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