RMI绑定到SAME端口但在SAME主机上有不同的IP地址 [英] RMI binding to SAME port but DIFFERENT IP address on SAME host
问题描述
如果我的计算机有3个虚拟IP地址（192.168.1。[5-7]），那么我可以如何启动同一个RMI应用程序的3个实例（每个实例都以
不同的属性/配置），每个都在端口1234上侦听，但每个
实例绑定到不同的IP地址。
是说：
实例＃1绑定到192.168.1.5/port 1234
实例＃2绑定到192.168.1.6/port 1234
实例＃3绑定到192.168.1.7/port 1234
我想我正在寻找类似的东西：
注册表注册表= LocateRegistry.createRegistry（< IPADDR> ;，< PORT>）;
我试过
System.setProperty（" java.rmi.server.hostname"，"< IP ADDR>"）;
但没有运气
当前代码看起来像这样：
/ **** ***服务器端********* /
System.getProperties（）。setProperty（" java.rmi.serve r.hostname"，serverip）;
Re gistry registry = LocateRegistry.createRegistry（serverport）;
registry.rebind（" RMITest"，this）;
// serverip是要绑定的IP到...服务器端口是端口1234
/ *******客户端********** /
Registry registry = LocateRegistry.getRegistry（serverip，serve rport）;
RMITestInterface rmit =（RMITestInterface）（registry.lookup（" RMITest"））;
rmit.dosomethingcool （）;
第二个实例（即使serverip不同）抱怨
java.rmi.server.ExportException：端口已在使用中：1234;嵌套
异常是：java.net.BindException：地址已经在使用
这些必须是每个应用程序的单独实例
客户...我知道可以在不同的端口运行它们，
但是在大型集群环境中这是不可接受的。这个
会很快成为一个完整的噩梦。
我错过了什么？！？！我已经googled高低，看了我所有的java书籍，但没有提到这样的场景！任何人？
TIA！
-alex
If I have a machine with 3 virtual IP addresses (192.168.1.[5-7]), how
can I start 3 instances of the same RMI application (each started with
different properties/configs), each listening on the port 1234, but each
instance binds to a different ip address.
that is to say:
instance #1 binds to 192.168.1.5/port 1234
instance #2 binds to 192.168.1.6/port 1234
instance #3 binds to 192.168.1.7/port 1234
I guess I am looking for something like:
Registry registry = LocateRegistry.createRegistry(<IPADDR>,<PORT>);
I tried
System.setProperty("java.rmi.server.hostname","<IP ADDR>");
but had no luck
current code looks something like this:
/******* server side *********/
System.getProperties().setProperty("java.rmi.serve r.hostname",serverip);
Registry registry = LocateRegistry.createRegistry(serverport);
registry.rebind("RMITest", this);
//serverip is the IP to bind to... server port is port 1234
/******* client side **********/
Registry registry=LocateRegistry.getRegistry(serverip,serve rport);
RMITestInterface rmit=(RMITestInterface)(registry.lookup("RMITest") );
rmit.dosomethingcool();
second instance (even though serverip is different) complains
java.rmi.server.ExportException: Port already in use:1234; nested
exception is: java.net.BindException: Address already in use
These have to be seperate instances of the application for each
customer... I know that it is possible to run them on different ports,
but this is really not acceptable in a large clustered environment. this
would become a complete nightmare very quickly.
what am I missing?!?! I have googled high and low, and looked through
all my java books, but see no mention of such a scenario! anyone?
TIA!
-alex
推荐答案
Alexander N. Spitzer <人** @ spitzer.NOSPAMPLEASE.org>在留言中写道
新闻：mN **************** @ nwrdny03.gnilink.net ...
[snipped]
"Alexander N. Spitzer" <al**@spitzer.NOSPAMPLEASE.org> wrote in message
news:mN****************@nwrdny03.gnilink.net...
[snipped]
我想我正在寻找类似的东西：
注册表注册表= LocateRegistry.createRegistry（< IPADDR>，< PORT>）;
I guess I am looking for something like:
Registry registry = LocateRegistry.createRegistry(<IPADDR>,<PORT>);
LocateRegistry中没有带此签名的方法。你可以使用这种形式的
方法创建一个绑定到特定IP地址的
注册表对象：
public static Registry createRegistry（int port，RMIClientSocketFactory csf，
RMIServerSocketFactory ssf）抛出RemoteException
你必须提供一个实现RMIServerSocketFactory的类
接口（RMIClientSocketFactory parm可以为null）;这个类将
创建一个ServerSocket，你必须绑定到所需的IP地址。
这是一个例子：
import java.rmi.server。*;
import java.io. *;
import java.net。*;
public class AnchorSocketFactory扩展了RMISocketFactory实现
Serializable
{
private InetAddress ipInterface = null;
public AnchorSocketFactory（）{}
public AnchorSocketFactory（InetAddress ipInterface）
{
this.ipInterface = ipInterface;
}
public ServerSocket createServerSocket（int port）
{
ServerSocket serverSocket = null;
try
{
serverSocket = new ServerSocket（port，50，ipInterface）;
}
catch（例外e）
{
System.out.println（e）;
}
return（serverSocket）;
}
public Socket createSocket（String dummy，int抛出IOException
{
return（新套接字（ipInterface，port））;
}
public boolean equals（Object that）
{
return（that！= null&& that.getClass（）== this.getClass（））;
}
}
在你的代码中执行以下操作：
AnchorSocketFactory sf = new AnchorSocketFactory（< your InetAddress>）;
LocateRegistry.createRegistry（port，null，sf）;
HTH
Alex Molochnikov
格式塔公司
www.gestalt.com
" Alexander N. Spitzer" <人** @ spitzer.NOSPAMPLEASE.org>在消息新闻中写道：< mN **************** @ nwrdny03.gnilink.net> ...
"Alexander N. Spitzer" <al**@spitzer.NOSPAMPLEASE.org> wrote in message news:<mN****************@nwrdny03.gnilink.net>...
如果我有一台3虚拟机IP地址（192.168.1。[5-7]），我如何启动同一个RMI应用程序的3个实例（每个应用程序以不同的属性/配置启动），每个实例都在端口1234上监听，但每个
实例绑定到一个不同的IP地址。
也就是说：
实例＃1绑定到192.168.1.5/port 1234
实例＃2绑定到192.168.1.6/port 1234
实例＃3绑定到192.168.1.7/port 1234
我想我正在寻找类似的东西：
Registry registry = LocateRegistry.createRegistry（ < IPADDR>，< PORT>）;
我试过了System.setProperty（" java.rmi.server.hostname"，"< IP ADDR>"） ;
但没有运气
当前代码看起来像这样：
/ *******服务器端******** * /
System.getProperties（）。setProperty（" java.rmi.serve r.hostname&q uot;，serverip）;
注册表注册表= LocateRegistry.createRegistry（serverport）;
registry.rebind（" RMITest"，this）;
// serverip是IP绑定到...服务器端口是端口1234
/ *******客户端********** /
注册表注册表= LocateRegistry.getRegistry （serverip，serve rport）;
RMITestInterface rmit =（RMITestInterface）（registry.lookup（" RMITest"））;
rmit.dosomethingcool（）;
second instance（即使serverip不同）抱怨
java.rmi.server.ExportException：端口已在使用中：1234;嵌套
异常是：java.net.BindException：地址已经在使用
这些必须是每个
客户的应用程序的单独实例...我知道它是可以在不同的端口上运行它们，但是在大型集群环境中这实际上是不可接受的。这很快就会成为一场彻头彻尾的噩梦。
我错过了什么？！？！我已经googled高低，看了我所有的java书籍，但没有提到这样的场景！ TIA！
-alex
If I have a machine with 3 virtual IP addresses (192.168.1.[5-7]), how
can I start 3 instances of the same RMI application (each started with
different properties/configs), each listening on the port 1234, but each
instance binds to a different ip address.
that is to say:
instance #1 binds to 192.168.1.5/port 1234
instance #2 binds to 192.168.1.6/port 1234
instance #3 binds to 192.168.1.7/port 1234
I guess I am looking for something like:
Registry registry = LocateRegistry.createRegistry(<IPADDR>,<PORT>);
I tried
System.setProperty("java.rmi.server.hostname","<IP ADDR>");
but had no luck
current code looks something like this:
/******* server side *********/
System.getProperties().setProperty("java.rmi.serve r.hostname",serverip);
Registry registry = LocateRegistry.createRegistry(serverport);
registry.rebind("RMITest", this);
//serverip is the IP to bind to... server port is port 1234
/******* client side **********/
Registry registry=LocateRegistry.getRegistry(serverip,serve rport);
RMITestInterface rmit=(RMITestInterface)(registry.lookup("RMITest") );
rmit.dosomethingcool();
second instance (even though serverip is different) complains
java.rmi.server.ExportException: Port already in use:1234; nested
exception is: java.net.BindException: Address already in use
These have to be seperate instances of the application for each
customer... I know that it is possible to run them on different ports,
but this is really not acceptable in a large clustered environment. this
would become a complete nightmare very quickly.
what am I missing?!?! I have googled high and low, and looked through
all my java books, but see no mention of such a scenario! anyone?
TIA!
-alex
Alex，
$ b终端主机为每个活动的IP地址保留多个端口。
来自NIC卡的数据被传递到协议栈，并且来源
ip地址已被丢弃到达端口的时间。
您可以尝试在单个端口上侦听单个RMI服务器，将
数据传递给基于jvm的给定实例客户ID。
Sam90
Alex,
I doubt an end host keeps multiple ports for each active ip address.
Data from a nic card is passed up the protocol stack, and the source
ip address has been discarded by the time it reaches the port.
You might try a single RMI server listening on a single port, passing
data to a given instance of a jvm based on customer id.
Sam90
> Alex，
我怀疑终端主机为每个活动的ip地址保留多个端口。
来自nic卡的数据传递到协议栈，源
IP地址在到达端口时已被丢弃。
您可以尝试在单个端口上侦听单个RMI服务器，将
数据传递给基于jvm的给定实例客户ID。
Sam90
I doubt an end host keeps multiple ports for each active ip address.
Data from a nic card is passed up the protocol stack, and the source
ip address has been discarded by the time it reaches the port.
You might try a single RMI server listening on a single port, passing
data to a given instance of a jvm based on customer id.
Sam90
Sam，在ASP环境中，需要单独使用
每个客户的实例。
Alex Molochnikov给了我正在寻找的答案，这是：
LocateRegistry中没有方法这个签名。你可以使用这种形式的
方法创建
a注册表对象绑定到特定的IP地址：
public static Registry createRegistry （int port，RMIClientSocketFactory
csf，RMIServerSocketFactory ssf）抛出RemoteException
谢谢Alex M.等人！
Sam, in an ASP environment, it is a requirement to have seperate
instances for each client.
Alex Molochnikov gave me the answer I was looking for, which was:
There is no method in LocateRegistry with this signature. You can create
a Registry object bound to a specific IP address using this form of the
method:
public static Registry createRegistry(int port, RMIClientSocketFactory
csf,RMIServerSocketFactory ssf) throws RemoteException
Thanks Alex M. et al.!
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