通过反射创建F＃记录 [英] Creating F# record through reflection

问题描述

如何创建F＃中的记录类型通过使用反射？谢谢

How can I create a record type in F# by using reflection? Thanks

推荐答案

您可以使用<一个href="http://msdn.microsoft.com/en-us/library/ee353790.aspx"><$c$c>FSharpValue.MakeRecord^[MSDN]创造纪录的实例，但我不认为有什么烤成F＃定义记录的类型的。然而，记录编译成简单的类，这样你就可以建立一个类，你会在C＃。 <一href="http://msdn.microsoft.com/en-us/library/system.reflection.emit.typebuilder.aspx"><$c$c>TypeBuilder^[MSDN]可能是一个很好的起点。

You can use FSharpValue.MakeRecord^[MSDN] to create a record instance, but I don't think there's anything baked into F# for defining record types. However, records compile to simple classes, so you could build a class as you would in C#. TypeBuilder^[MSDN] may be a good starting point.

添加 [＆LT; CompilationMapping（SourceConstructFlags.RecordType）GT;] 的类型是所有的需要，使之成为记录。下面是如何在运行时做一个这样的例子。

Adding [<CompilationMapping(SourceConstructFlags.RecordType)>] to the type is all that's required to make it a record. Here's an example of how to do this at run-time.

let asmName = AssemblyName("Foo")
let asm = AppDomain.CurrentDomain.DefineDynamicAssembly(asmName, AssemblyBuilderAccess.RunAndCollect)
let moduleBldr = asm.DefineDynamicModule("Test")
let typeBldr = moduleBldr.DefineType("MyRecord", TypeAttributes.Public)
let attrBldr = CustomAttributeBuilder(
                typeof<CompilationMappingAttribute>.GetConstructor([|typeof<SourceConstructFlags>|]), 
                [|box SourceConstructFlags.RecordType|])
typeBldr.SetCustomAttribute(attrBldr)
let typ = typeBldr.CreateType()
printfn "%b" <| FSharpType.IsRecord(typ) //true

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