在gcc中输入一个字符串 [英] input a string in gcc
问题描述
以下是接受来自用户的字符串的代码，但是当我完成输入字符串后我得到
分段错误，即很快我按下了b / b
''输入''键。
following is the code to accept a string from user, but i get
segmentation fault as soon i have finished entering the string i.e. as
soon as i press the ''enter'' key.
推荐答案
文章< e5 * ******** @ f24g2000prh。 googlegroups.com>，
yogicoder< za ***** @ gmail.comwrote：
In article <e5**********************************@f24g2000prh. googlegroups.com>,
yogicoder <za*****@gmail.comwrote:
>以下是代码从用户那里接受一个字符串，但是当我完成输入字符串后我就会出现分段错误，即按下输入键即可。
>following is the code to accept a string from user, but i get
segmentation fault as soon i have finished entering the string i.e. as
soon as i press the ''enter'' key.
> #include< stdio.h>
#include< string.h>
#include<文件stdlib.h>
>#include <stdio.h>
#include <string.h>
#include <stdlib.h>
> int main（void）
{char str [50];
printf（"输入字符串：\ n"）;
fgets（str，sizeof str，stdin）;
>int main (void)
{
char str[50];
printf ("Enter string:\n");
fgets (str, sizeof str, stdin);
那部分对我来说没问题。
That part looks okay to me.
//进一步代码
}
//further code
}
你没有从main（）返回一个值，导致C89 / C90中未定义的
行为。
但我怀疑错误是在//进一步代码中。部分。
-
Allegories属于思想领域，遗骸是什么样的东西。 - Walter Benjamin
You are not returning a value from main(), which leads to undefined
behaviour in C89/C90.
But I suspect the error is in the "//further code" part.
--
"Allegories are in the realm of thoughts, what ruins are in
the realm of things." -- Walter Benjamin
On Sun，2008年6月8日07:38:48 +0000，Walter Roberson写道：
On Sun, 08 Jun 2008 07:38:48 +0000, Walter Roberson wrote:
文章
< e5 ********************************** @ f24g2000prh。 googlegroups.com>，
yogicoder< za ***** @ gmail.comwrote：
In article
<e5**********************************@f24g2000prh. googlegroups.com>,
yogicoder <za*****@gmail.comwrote:
>>以下是用来接受来自用户的字符串的代码，但是当我完成输入字符串后，即使我按下输入键，我就会收到分段错误。
>>following is the code to accept a string from user, but i get
segmentation fault as soon i have finished entering the string i.e. as
soon as i press the ''enter'' key.
>> #include< stdio.h>
#include< string.h>
#include < stdlib.h中>
>>#include <stdio.h>
#include <string.h>
#include <stdlib.h>
>> int main（void）
{char str [50];
printf（ 输入字符串：\ n"）;
fgets（str，sizeof str，stdin）;
>>int main (void)
{
char str[50];
printf ("Enter string:\n");
fgets (str, sizeof str, stdin);
那部分对我来说没问题。
That part looks okay to me.
> //进一步的代码
}
> //further code
}
你没有从main（）返回一个值，
You are not returning a value from main(),
如果您将//进一步的代码视为评论，那么您已经知道这个
不是C90程序。如果你把它当作一个指示符来表示有更多的代码，那么该代码很可能会从main（）返回一个值。
If you treat //further code as just a comment, then you already know this
is not a C90 program. If you treat it as an indicator that there is more
code, that code may very well return a value from main().
这导致C89 / C90中未定义的
行为。
which leads to undefined
behaviour in C89/C90.
不，它不是。它会导致一个未定义的返回值，但在C90中没有未定义的
行为。
No, it doesn''t. It leads to an undefined return value, but not undefined
behaviour, in C90.
但我怀疑错误是在 //进一步的代码部分。
But I suspect the error is in the "//further code" part.
同意。
Agreed.
yogicoder< za ***** @ gmail.comwrites：
yogicoder <za*****@gmail.comwrites:
以下是接受来自用户的字符串的代码，但是当我完成输入字符串时，我得到
分段错误，即
我按下''enter''键。
following is the code to accept a string from user, but i get
segmentation fault as soon i have finished entering the string i.e. as
soon as i press the ''enter'' key.
错误必须在//其他代码部分中，因为其他人已指出
out。使用-g标志编译代码并使用valgrind或gdb
查看有问题的行。在那之后尝试解决它，如果你不能
（但是先尝试）再次寻求帮助。
-
- Filipe Cabecinhas
char * params [] = {" fil"，cab，@，gmail"，。 "，" com"};
puts（" Real signature："）;
for（int i = 0; i< sizeof（params） / sizeof（* params）; ++ i）
printf（"％s"，params [i]）;
putchar（''
''）;
The error must be in the // further code part, as others have pointed
out. Compile your code with the -g flag and use valgrind or gdb to
see the offending line. After that try to fix it and, if you can''t
(but TRY first) ask for help again.
--
- Filipe Cabecinhas
char* params[] = {"fil", "cab", "@", "gmail", ".", "com"};
puts("Real signature:");
for (int i = 0; i < sizeof(params)/sizeof(*params); ++i)
printf("%s", params[i]);
putchar(''
'');
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