将相同值分配给多个变量的最少键入量是多少 [英] what is the least amount of typing to assign the same value to multiple variables

问题描述

这种语法不起作用

nl，nt，ns = 0;

唯一得到初始化的是ns。

nl和nt因为他们没有初始化似乎从

内存得到一些垃圾。


我做了这两个版本的工作：

nl = 0; nt = 0; ns = 0;

nl = nt = ns = 0;


我想知道它的正常工作方式是什么？在下面的上下文我

想知道逗号是如何被解释为：

nl，nt，ns = 0;


谢谢任何见解。

解决方案

vlsidesign写道：

此语法不工作

nl，nt，ns = 0;

唯一获得初始化的是ns。

nl和因为他们没有初始化似乎从

内存中获得了一些垃圾。


我已经完成了这两个版本的工作：

nl = 0; nt = 0; ns = 0;

nl = nt = ns = 0;


我想知道它的正常工作方式是什么？在下面的上下文我

想知道逗号是如何被解释为：

nl，nt，ns = 0;


谢谢任何见解。

只是好奇：为什么这很重要？如果你需要数百万个变量，

只需要make和array，并用循环初始化它。或者使用calloc（），

，它的工作方式类似于malloc（），但是将缩写初始化为0.

merry Xmas，Furious_joe

furious_joe写道：

只是好奇：为什么这很重要？如果你需要数百万个变量，

只需要make和array，并用循环初始化它。或者使用calloc（），

，其作用类似于malloc（），但是将缩写初始化为0.

merry Xmas，Furious_joe

$ b第3行
$ b，make之间和阵列是一个校对的理由，而不是

相信一个拼写检查器。

它不是，我是一个新手，只是想知道。我正在阅读

C编程语言。由Kernighan和Ritchie，第二版

版本 - 这本书看起来非常好。


furious_joe写道：

vlsidesign写道：

此语法不起作用

nl，nt，ns = 0;

唯一被初始化的是ns。

nl和nt因为他们没有初始化似乎从

内存得到一些垃圾。


我做了这两个版本的工作：

nl = 0; nt = 0; ns = 0;

nl = nt = ns = 0;


我想知道它的正常工作方式是什么？在下面的上下文我

想知道逗号是如何被解释为：

nl，nt，ns = 0;


谢谢任何见解。

只是好奇：为什么这很重要？如果你需要数百万个变量，

只需要make和array，并用循环初始化它。或者使用calloc（），

，它的作用类似于malloc（），但是将缩写初始化为0.

merry Xmas，Furious_joe

This syntax does not to work
nl, nt, ns = 0;
The only one that get''s initialized is ns.
nl and nt because they don''t initialize seem to get some junk from
memory.

I have done these two versions that work:
nl = 0; nt = 0; ns = 0;
nl = nt = ns = 0;

I wonder what is the normal way it is done? In the context below I
wonder how the commas are interpreted as:
nl, nt, ns = 0;

Thanks for any insight.

解决方案

vlsidesign wrote:

This syntax does not to work
nl, nt, ns = 0;
The only one that get''s initialized is ns.
nl and nt because they don''t initialize seem to get some junk from
memory.

I have done these two versions that work:
nl = 0; nt = 0; ns = 0;
nl = nt = ns = 0;

I wonder what is the normal way it is done? In the context below I
wonder how the commas are interpreted as:
nl, nt, ns = 0;

Thanks for any insight.

Just curious: why does it matter? If you need millions of variables,
just make and array, and initialize it with a loop. or use calloc(),
which works like malloc(), but initializes the condense to 0.
merry Xmas, Furious_joe

furious_joe wrote:

Just curious: why does it matter? If you need millions of variables,
just make and array, and initialize it with a loop. or use calloc(),
which works like malloc(), but initializes the condense to 0.
merry Xmas, Furious_joe

on line 3, between "make" and "array" is a reason to proofread, and not
trust a spell checker.

It doesn''t, I am a newbie and just wondering. I am going through the
"The C programming language" by Kernighan and Ritchie, the Second
edition -- this book seems very good.

furious_joe wrote:

vlsidesign wrote:

This syntax does not to work
nl, nt, ns = 0;
The only one that get''s initialized is ns.
nl and nt because they don''t initialize seem to get some junk from
memory.

I have done these two versions that work:
nl = 0; nt = 0; ns = 0;
nl = nt = ns = 0;

I wonder what is the normal way it is done? In the context below I
wonder how the commas are interpreted as:
nl, nt, ns = 0;

Thanks for any insight.

Just curious: why does it matter? If you need millions of variables,
just make and array, and initialize it with a loop. or use calloc(),
which works like malloc(), but initializes the condense to 0.
merry Xmas, Furious_joe

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