我如何声明一个字节变量？ [英] How do i declare a byte variable?
问题描述
我有一个问题，一个愚蠢的问题。我不能声明一个类型的变量
byte。
g ++说我在这一行中有语法错误。代码是
这个：字节*变量;
好吧，我认为错误是愚蠢但我找不到它。 />
在哪里？
I have a problem, a stupid problem. I can''t declare a variable of type
byte.
The g++ said that i have syntactic error in this line. The code is
this: byte * variable;
well, i think that the mistake is a stupidity but i don''t find it.
where is it?
推荐答案
Manuel写道：
Manuel wrote:
我有一个问题，一个愚蠢的问题。我不能声明一个类型的变量
byte。
g ++说我在这一行中有语法错误。代码是
这个：字节*变量;
好吧，我认为错误是愚蠢但我找不到它。 />
在哪里？
I have a problem, a stupid problem. I can''t declare a variable of type
byte.
The g++ said that i have syntactic error in this line. The code is
this: byte * variable;
well, i think that the mistake is a stupidity but i don''t find it.
where is it?
标准C ++没有称为byte的内置类型。只需使用一个
char或者可能是一个未签名的字符。
试试这个：
char * variable1 ;
unsigned char * variable2;
或许您需要告诉我们更多关于您打算做什么的事情
变量。
祝你好运，
Tom
Standard C++ doesn''t have a built-in type called "byte." Just use a
char or, possibly, an unsigned char.
Try this:
char* variable1;
unsigned char* variable2;
Or perhaps you need to tell us more about what you intend to do with
the variable.
Best regards,
Tom
On 2006年8月10日13:57:01 -0700 in comp.lang.c ++，Manuel
< mf ***** @ gmail.comwrote，
On 10 Aug 2006 13:57:01 -0700 in comp.lang.c++, "Manuel"
<mf*****@gmail.comwrote,
>我有一个问题，一个愚蠢的问题。我不能声明一个类型为
byte的变量。
g ++说我在这一行中有语法错误。代码是这样的：byte * variable;
>I have a problem, a stupid problem. I can''t declare a variable of type
byte.
The g++ said that i have syntactic error in this line. The code is
this: byte * variable;
C ++中的一个字节是char，或unsigned char，或者是signed char。
但是上面的变量不会是一个字节，任何情况。这将是一个指针
。如果你问的是什么是字节，你可能应该
现在避免使用字节和指针并使用std :: string等。
A byte in C++ is char, or unsigned char, or signed char.
But your variable above would not be a byte an any case. It would
be a pointer. If you are asking what is a byte, you should probably
avoid bytes and pointers for now and use std::string etc..
哎哟，我很愚蠢;（
好吧，我考虑过使用byte类型的变量，因为我需要
存储从0到0的值255.
我想我可以用这个：
Thomas Tutone写道：typedef unsigned char byte;
所以这样我可以使用字节。
感谢您的帮助。
再见。
Manuel Fernadez Campos
ouch, iam stupid ;(
well, I thought about using the variable of type byte because I need to
store values from 0 to 255.
I think that i can use this:
Thomas Tutone wrote: typedef unsigned char byte;
So this way i can use byte.
Thank you for your help.
Bye.
Manuel Fernadez Campos
Manuel写道：
Manuel wrote:
hi，
我有一个问题，一个愚蠢的问题。我不能声明一个类型的变量
byte。
g ++说我在这一行中有语法错误。代码是
这个：字节*变量;
好吧，我认为错误是愚蠢但我找不到我t。
在哪里？
I have a problem, a stupid problem. I can''t declare a variable of type
byte.
The g++ said that i have syntactic error in this line. The code is
this: byte * variable;
well, i think that the mistake is a stupidity but i don''t find it.
where is it?
标准C ++没有一个名为byte的内置类型。只需使用一个
char或者可能是一个未签名的字符。
试试这个：
char * variable1 ;
unsigned char * variable2;
或许您需要告诉我们更多关于您打算做什么的事情
变量。
祝你好运，
Tom
Standard C++ doesn''t have a built-in type called "byte." Just use a
char or, possibly, an unsigned char.
Try this:
char* variable1;
unsigned char* variable2;
Or perhaps you need to tell us more about what you intend to do with
the variable.
Best regards,
Tom
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