如何确定输出缓冲区的大小 [英] How to determine the size of an output buffer
问题描述
好吧，让我们说我有一个充满异国情调的操作系统，限制了多少奖金。
标准输出。我什么时候去...
#include< stdio.h>
int main（无效）{
int i = 0;
for（i = 0; i< 10; i ++）{
printf（" a \ n"） ;
}
返回0;
}
我得到这个....
[cdalten @ localhost~] $ ./out
a
a
a
a
a
a
a
a
a
a
但是现在，我将printf（）更改为
printf（a test\ n）;
现在当我运行
#include< stdio.h>
int main（void）{
int i = 0;
for（i = 0; i< 10; i ++）{
printf（" a test\ n）;
}
返回0;
}
我得到....
[cdalten @localhost~] $ ./out
a测试
a测试
a测试
a测试
a测试
正如你所看到的那样打印出来的前几行。
无论如何，我可以确定这个输出缓冲区的大小没有
重新试用到试验和错误猜测有多大输出缓冲区
可能是？
Chad
< blockquote> ./ out
a
a
a
a
a
a
a
a
a
a
但是现在，我将printf（）更改为
printf（a test\ n）;
现在我运行时
#include< stdio.h>
int main（无效）{
int i = 0;
为（i = 0; I< 10; i ++）{
printf（" a test\ nn）;
}
返回0;
}
我得到....
[cdalten @ localhost~]
./ out
a测试
a测试
a测试
a测试
a测试
正如你所看到的，只有前几行被打印出来。
无论如何我可以确定这个输出缓冲区的大小没有
重新进行试验和错误以猜测输出缓冲区可能有多大？
可能是什么？
Chad
Chad写道：
好吧，让我们说我有一个异国情调的os限制了多少
stdout。我什么时候去...
#include< stdio.h>
int main（void）{
这是交叉发布到comp.lang.c，我会保存clc人员
麻烦：它不是一个有效的C程序，如果main有错误的
参数数量。
可能是stdio有一个bug，但严格来说，如果你是
没有给系统一个有效的C程序，它没有必要有正确的输出
。
- Logan
Okay, let''s say I have an exotic os that limits how much goes to
stdout. When I go like..
#include <stdio.h>
int main(void) {
int i=0;
for(i=0; i< 10; i++) {
printf("a \n");
}
return 0;
}
I get this....
[cdalten@localhost ~]$ ./out
a
a
a
a
a
a
a
a
a
a
BUT Now, I change the printf() to
printf("a test\n");
Now when I run
#include <stdio.h>
int main(void) {
int i=0;
for(i=0; i< 10; i++) {
printf("a test\n");
}
return 0;
}
I get....
[cdalten@localhost ~]$ ./out
a test
a test
a test
a test
a test
As you can see, only the first few lines get printed out.
Is there anyway I can determine the size of this output buffer without
restorting to trial and error to guess how large the output buffer
might be?
Chad
./out
a
a
a
a
a
a
a
a
a
a
BUT Now, I change the printf() to
printf("a test\n");
Now when I run
#include <stdio.h>
int main(void) {
int i=0;
for(i=0; i< 10; i++) {
printf("a test\n");
}
return 0;
}
I get....
[cdalten@localhost ~]
./out
a test
a test
a test
a test
a test
As you can see, only the first few lines get printed out.
Is there anyway I can determine the size of this output buffer without
restorting to trial and error to guess how large the output buffer
might be?
Chad
Chad wrote:Okay, let''s say I have an exotic os that limits how much goes to
stdout. When I go like..
#include <stdio.h>
int main(void) {This being cross-posted to comp.lang.c, I''ll save the c-l-c people
the trouble: it''s not a valid a C program if main has the wrong
number of arguments.
It could be that stdio has a bug, but strictly speaking, if you''re
not giving the system a valid C program, it doesn''t have to have
correct output.
- Logan
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