class，用于保存2个表示x和y坐标的double值 [英] class to hold 2 double values representing the x and y coordinates
问题描述
我的论文中有一个问题，我没有正确的答案，所以在这里我问任何可以提供帮助的人，给我一个合适的答案。
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写一个名为Point的类，它包含两个表示x和y的double值图上点的坐标。提供以下内容：
1.一个合适的默认构造函数，它也可以将2个值中的一个或两个作为参数。默认值应为0.
2.成员函数get_x和get_y获取每个值。
3. Memeber函数set_x和set_y设置每个值。
4.重载输出运算符以格式输出Point：
（1.2,3.4）
5.成员函数长度返回点与原点的距离，即（0,0）。公式是sqrt（x2 + y2）。 （2是x和y的超级对象）
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这是我到目前为止完成的代码，但我可以完成函数长度（），我不确定我编码的所有内容是否正确。所以请帮助我.....
i have a question from my paper, which i dont have the correct answer, so here i asking anyone who can help, provide me the appropriate answer.
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Write a class called Point that holds two double values representing the x and y coordinates of a point on graph. Provide the following:
1. A suitable default constructor that can also take one or both of the 2 values as arguments. Default values should be 0.
2. Member function get_x and get_y to get each of the values.
3. Memeber function set_x and set_y to set each of the values.
4. An overloaded output operator to output the Point in the format:
(1.2, 3.4)
5. A member function "length" to return the distance of the point from the origin, i.e.(0,0). The formula is the sqrt(x2 + y2). (2 is the supercase to x and y)
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Here is my code that i done so far, but i could finish the function length(), and i''m not sure everything i coded is correct. So please help me.....
推荐答案
讲师为您提供了公式用于计算距离。如果你假设你有有效的输入，你所要做的就是取y坐标this。点和另一个点并使用公式返回结果。
The instructor has provided you with the formula for calculating the distance. If you assume that you have valid input all you have to do is take the y coordinates of "this" point and another point and use the formula to return the result.
if function" length"是从原点返回点的距离，即（0,0）它应该返回一个double而不是一个Point ??，例如
if function "length" is to return the distance of the point from the origin, i.e.(0,0) it should return a double not a Point??, e.g.
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