$ i ++问题理解 [英] $i++ problem understanding

问题描述

目前我正在学习PHP。


我能理解以下内容：

$ a = 10;

$ b = $ a ++;

打印（" $ a，$ b"）;

将在屏幕上打印11,10。

因为当$ b = $ a ++时，首先发生的事情是$ b = $ a

然后$ a = $ a + 1.我愿意并且可以接受。

但是更难接受的是我没有看到其中的逻辑，

如下：

$ i = 1;

打印（$ i ++）;

这将打印1，之后只会将$ i的值增加

1.它介于（）之间所以逻辑首先告诉我$ i ++然后打印。


任何人都可以帮助我理解这个或看到其中的逻辑吗？

thanx，


Pugi！

Currently I am studying PHP.

I can understand the following :
$a = 10;
$b = $a++;
print("$a, $b");
will print 11, 10 on the screen.
because when $b = $a++ first thing that happens is $b = $a
and then $a = $a + 1. I am willing to and can accept that.

But much harder to accept is and I fail to see the logic in it,
is the following :
$i = 1;
print($i++);
This will print 1 and only afterward will the value of $i be increased
by 1. It is between (), so logic tells me first $i++ and then print.

Can anyone help me understand this or see the logic in it ?
thanx,

Pugi!

推荐答案

a = 10;

a = 10;

b =

a ++;

print（"

a++;
print("

这篇关于$ i ++问题理解的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！