C和字符串 [英] C and strings
问题描述
我是c的新手，我遇到字符串有问题，任何人都可以给我一些
快速指针或指向好的c字符串教程？以下是我正在制作的
计划。
亲切的问候，
Anthony Irwin
#include< stdio.h>
char teststring [40] =" test string now";
char teststring1 [40] ;
int main（）{
printf（" teststring =％s"，teststring）;
strcpy（teststring1 ，teststring）;
printf（" \\\
teststring1 =％s"，teststring1）;
/ *如何为teststring分配新值说
*值我改变了字符串文本 * /
printf（" \ n\\\
II将teststring更改为=％s \ n"，teststring）;
返回0;
}
Hi,
I am new to c and am having trouble with strings can anyone give me some
quick pointers or point me to a good c strings tutorial? Below is a
program I am working on.
Kind Regards,
Anthony Irwin
#include <stdio.h>
char teststring[40] = "test string now";
char teststring1[40];
int main() {
printf("teststring = %s", teststring);
strcpy(teststring1, teststring);
printf("\nteststring1 = %s", teststring1);
/* How can I assign a new value to teststring say
* the value "I changed string text" */
printf("\n\nI changed teststring to = %s\n", teststring);
return 0;
}
推荐答案
2005年8月11日星期四09:54:28 +1,000，Anthony Irwin写道：
On Thu, 11 Aug 2005 09:54:28 +1000, Anthony Irwin wrote:
我是c的新手，我遇到字符串问题，任何人都可以给我一些快速指示或指向我好的C弦教程？以下是我正在制作的计划。
亲切的问候，
Anthony Irwin
#include< stdio.h>
char teststring [40] =" test string now" ;;
char teststring1 [40];
int main（）{
printf（" teststring = ％s"，teststring）;
strcpy（teststring1，teststring）;
printf（" \\\
teststring1 =％s"，teststring1）;
/ *我该怎么办？为teststring指定一个新值说
*值我改变了字符串文本 * /
/ *你的意思是？再次调用strcpy（）！ * /
strcpy（teststring，我更改了字符串文本）;
printf（" \ n\\\
II将teststring更改为=％s \ n"，teststring） ;
返回0;
}
Hi,
I am new to c and am having trouble with strings can anyone give me some
quick pointers or point me to a good c strings tutorial? Below is a
program I am working on.
Kind Regards,
Anthony Irwin
#include <stdio.h>
char teststring[40] = "test string now";
char teststring1[40];
int main() {
printf("teststring = %s", teststring);
strcpy(teststring1, teststring);
printf("\nteststring1 = %s", teststring1);
/* How can I assign a new value to teststring say
* the value "I changed string text" */ /* What you mean? just call strcpy() again! */
strcpy(teststring, "I changed string text");
printf("\n\nI changed teststring to = %s\n", teststring);
return 0;
}
Anthony Irwin写道：
Anthony Irwin wrote:
我是c的新手，我遇到字符串问题，任何人都可以给我一些快速指针，或者指向一个好的c字符串教程？以下是我正在制作的计划。
亲切的问候，
Anthony Irwin
#include< stdio.h>
char teststring [40] =" test string now" ;;
char teststring1 [40];
int main（）{
printf（" teststring = ％s"，teststring）;
strcpy（teststring1，teststring）;
printf（" \\\
teststring1 =％s"，teststring1）;
/ *我该怎么办？为teststring指定一个新值说
*值我改变了字符串文本 * /
printf（" \ n\\\
II将teststring更改为=％s \ n"，teststring）;
返回0;
}
Hi,
I am new to c and am having trouble with strings can anyone give me some
quick pointers or point me to a good c strings tutorial? Below is a
program I am working on.
Kind Regards,
Anthony Irwin
#include <stdio.h>
char teststring[40] = "test string now";
char teststring1[40];
int main() {
printf("teststring = %s", teststring);
strcpy(teststring1, teststring);
printf("\nteststring1 = %s", teststring1);
/* How can I assign a new value to teststring say
* the value "I changed string text" */
printf("\n\nI changed teststring to = %s\n", teststring);
return 0;
}
strncpy（teststring，我更改了字符串文本，sizeof teststring-1）;
或
sprintf（teststring，"％。* s"，sizeof teststring-1，" I changed string
text"）;
转换说明符％。Ns表示不应写入不超过N
的字符;例如，我们可以写出
％。39s。使用*而不是常量意味着在
中指定了printf（）的一个参数（在本例中，通过表达式
sizeof teststring-1）。
表达式sizeof teststring-1给出了目的地的大小
缓冲区，少了0个终结符的一个字符，因此在这两种情况下，没有
将超过39个字符写入teststring。 />
strncpy(teststring, "I changed string text", sizeof teststring-1);
or
sprintf(teststring, "%.*s", sizeof teststring-1, "I changed string
text");
The conversion specifier "%.Ns" indicates that no more than N
characters should be written; for example, we could have written
"%.39s". Using * instead of a constant means that N is specified in
one of the arguments to printf() (in this case, by the expression
sizeof teststring-1).
The expression "sizeof teststring-1" gives the size of the destination
buffer, less one character for a 0 terminator, so in both cases, no
more than 39 characters are being written to teststring.
感谢回复人员。出于某种原因，我认为你必须使用带有strcpy的
变量。
亲切的问候，
Anthony Irwin
Thanks for the reply guys. For some reason I thought you had to use
variables with strcpy.
Kind Regards,
Anthony Irwin
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