数组不是指针，对吧？ [英] Arrays are not Pointers, right?
问题描述
我一直都教过数组不是指针。那我该怎么办：
#include< iostream>
#include< cstdlib>
using namespace std ;
int main（）
{
int myArray [10] = {1,10};
cout<< sizeof（myArray）<< endl;
cout<< sizeof（myArray + 1）<< endl;
cout<< * myArray<< endl;
cout<< *（myArray + 1）<<结束;
系统（暂停）;
返回0;
}
/ *结果是
40
4
1
10
* /
-
Gary
I''ve always taught that arrays are not pointers. So how come I can do:
#include <iostream>
#include <cstdlib>
using namespace std;
int main( )
{
int myArray[10]={1, 10};
cout << sizeof(myArray) << endl;
cout << sizeof(myArray+1) << endl;
cout << *myArray << endl;
cout << *(myArray+1) << endl;
system("Pause");
return 0;
}
/*results are
40
4
1
10
*/
--
Gary
推荐答案
"加里" < GL ******* @ comcast.net>在消息中写道
新闻：Z9 ******************** @ comcast.com ...
"Gary" <gl*******@comcast.net> wrote in message
news:Z9********************@comcast.com...
我我总是教导数组不是指针。那我该怎么做：
#include< iostream>
#include< cstdlib>
使用命名空间std;
int main（ ）
{
int myArray [10] = {1,10};
cout<< sizeof（myArray）<< endl;
cout<< sizeof（myArray + 1）<< endl;
cout<< * myArray<< endl;
cout<< *（myArray + 1）<< endl;
系统（暂停）;
返回0;
}
/ *结果是
40
4 /> 1
10
* /
I''ve always taught that arrays are not pointers. So how come I can do:
#include <iostream>
#include <cstdlib>
using namespace std;
int main( )
{
int myArray[10]={1, 10};
cout << sizeof(myArray) << endl;
cout << sizeof(myArray+1) << endl;
cout << *myArray << endl;
cout << *(myArray+1) << endl;
system("Pause");
return 0;
}
/*results are
40
4
1
10
*/
数组指针不相同但相互关联。
arr [i] = = *（arr + i）
arr是数组起始元素的地址。
arr + 1是数组第二个元素的地址。 br />
* arr是第一个元素的值
*（arr + 1）是数组的第二个元素。
简单:-)
-Sharad
Arrays are pointers are not same but inter-related.
arr[i] == *(arr+i)
arr is the address of the starting element of the array.
arr+1 is the address of the 2nd element of the array.
*arr is the value of the 1st element
*(arr+1) is the 2nd element of the array.
Simple :-)
-Sharad
Gary写道：
我一直都教过数组不是指针。那我该怎么办：
I''ve always taught that arrays are not pointers. So how come I can do:
[SNIP]
因为在某些表达式中，数组_decays_的名称变为指针
到数组的第一个元素。
-
Attila又名WW
[SNIP]
Because in certain expressions the name of the array _decays_ into a pointer
to the first element of the array.
--
Attila aka WW
" Attila Feher" <在********** @ lmf.ericsson.se>在消息中写道
news：bv ********** @ newstree.wise.edt.ericsson.se ...
"Attila Feher" <at**********@lmf.ericsson.se> wrote in message
news:bv**********@newstree.wise.edt.ericsson.se...
Gary写道：
我一直都教过数组不是指针。那我该怎么办：[SNIP]
因为在某些表达式中，数组_decays_的名称变为
I''ve always taught that arrays are not pointers. So how come I can do: [SNIP]
Because in certain expressions the name of the array _decays_ into a
指向数组第一个元素的指针。
pointer to the first element of the array.
是的，但我很惊讶我可以对野兽进行指针运算。
sizeof（数组+ 1）回来了。我原本以为它是整个数组第二个字节的地址
。哦，好吧。
-
加里
Yeah, but I was surprised that I could do pointer arithmetic on the beast.
sizeof(array+1) came back okay. I would have thought it would be the address
of the second byte of the entire array. Oh, well.
--
Gary
这篇关于数组不是指针，对吧？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
