将布尔值传递给函数 [英] Passing Boolean to a Function

问题描述

我在将一个布尔值传递给对象的构造函数时遇到了问题。

出于某种原因，如果我将false传递给构造函数，它就不会$ /
注册。如果我传递整数0，它会。 PHP 5代码如下：


---------------------

class Test {< br $>
var $ testBool;


公共函数__construct（$ testBool）{

print" testBool = $ testBool" ;;

}

}


$ testing = new Test（false）; //这只是打印" testBool ="


$ testing = new Test（0）; //这打印testBool = 0


--------------------

似乎两种方法都应该打印0或false。我错过了什么？

I''m having an issue passing a boolean to the constructor of an object.
For some reason, if I pass false into the constructor, it doesn''t
register. If I pass an integer 0, it does. PHP 5 Code below:

---------------------
class Test {
var $testBool;

public function __construct($testBool) {
print "testBool = $testBool";
}
}

$testing = new Test(false); // this just prints "testBool = "

$testing = new Test(0); // this prints "testBool = 0"

--------------------
Seems to be both methods should print 0 or false. What have I missed?

推荐答案

testBool;


public function __construct（

testBool;

public function __construct(

testBool）{

print" testBool =

testBool) {
print "testBool =

testBool";

}

}

testBool";
}
}

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