分隔字符串到数组 [英] Delimited String to Array
问题描述
C＃的新手（从Delphi迁移），我不知道如何将一个
分隔的字符串转换为字符串数组。
输入：字符串看起来像 - 01-85-78-15-Q11
输出：带元素的数组 - 01,85,78,15等......
是否有某种简单的衬垫可以做到这一点？很难搜索
帮助我执行此操作的帮助文件。
提前致谢。
New to C# (migrating from Delphi) and I''m not sure how to get a
delimited string into an array of string.
input: string looks like - 01-85-78-15-Q11
output: an array with elements - 01,85,78,15 etc...
Is there some sort of easy one liner that does this? Hard to search
the help files for anything that would assist me in doing this.
Thanks in advance.
推荐答案
" Kyro" < ky ***** @ gmail.comwrote in news：1155322984.111975.115810
@ i3g2000cwc.googlegroups.com：
"Kyro" <ky*****@gmail.comwrote in news:1155322984.111975.115810
@i3g2000cwc.googlegroups.com:
新到C＃（从Delphi迁移），我不知道如何将一个
分隔的字符串放入一个字符串数组中。
输入：string看起来喜欢 - 01-85-78-15-Q11
输出：带元素的数组 - 01,85,78,15等...
是有一种简单的衬垫可以做到这一点吗？难以搜索
帮助文件，以帮助我做这件事。
New to C# (migrating from Delphi) and I''m not sure how to get a
delimited string into an array of string.
input: string looks like - 01-85-78-15-Q11
output: an array with elements - 01,85,78,15 etc...
Is there some sort of easy one liner that does this? Hard to search
the help files for anything that would assist me in doing this.
您有两种选择：
1）简单 - 使用string.Split。
string input =" 01-85-78" ;;
string [] output = input.Split（'' - ''）;
2）简单，更灵活，但也许是矫枉过正 - 使用正则表达式
string input =" 01-85-78" ;;
string [] output = Regex.Split（input，" - "）;
如果你遇到更复杂的
分割要求，我只会使用正则表达式选项。
-mdb
You have two options:
1) Easy - use string.Split.
string input = "01-85-78";
string[] output = input.Split(''-'');
2) Easy, more flexible, but perhaps overkill - use Regex
string input = "01-85-78";
string[] output = Regex.Split(input, "-");
I would only use the Regex option if you get into more complicated
splitting requirements.
-mdb
Hello Kyro，
见String.Split / String.Join方法
KNew到C＃（从Delphi迁移），我不知道如何获得一个
Kdelimited字符串到一个字符串数组。
K>
Kinput：字符串看起来像 - 01-85-78-15-Q11
Koutput：一个数组与元素 - 01,85,78,15等...
KIs有一些简单的一个衬里tha这样做？很难搜索
K帮助文件可以帮助我做任何事情。
K>
KThanks提前。
K>
---
WBR，
Michael Nemtsev ::博客： http://spaces.msn.com/laflour
"有时一个人仍然忠于一个事业，只因为它的对手不会因为他们不会平淡无味。 （c）Friedrich Nietzsche
Hello Kyro,
See String.Split/String.Join methods
KNew to C# (migrating from Delphi) and I''m not sure how to get a
Kdelimited string into an array of string.
K>
Kinput: string looks like - 01-85-78-15-Q11
Koutput: an array with elements - 01,85,78,15 etc...
KIs there some sort of easy one liner that does this? Hard to search
Kthe help files for anything that would assist me in doing this.
K>
KThanks in advance.
K>
---
WBR,
Michael Nemtsev :: blog: http://spaces.msn.com/laflour
"At times one remains faithful to a cause only because its opponents do not
cease to be insipid." (c) Friedrich Nietzsche
你好Kyro，
BTW，你甚至可以使用String.Replace
KNew到C＃（从Delphi迁移），我不知道怎么把一个
Kdelimited字符串变成一个字符串数组。
K> ;
Kinput：字符串看起来像 - 01-85-78-15-Q11
Koutput：包含元素的数组 - 01,85,78,15等...
KIs有哪种简单的衬垫可以做到这一点？很难搜索
K帮助文件可以帮助我做任何事情。
K>
KThanks提前。
K>
---
WBR，
Michael Nemtsev ::博客： http://spaces.msn.com/laflour
"有时一个人仍然忠于一个事业，只因为它的对手不会因为他们不会平淡无味。 （c）Friedrich Nietzsche
Hello Kyro,
BTW, u even could use String.Replace
KNew to C# (migrating from Delphi) and I''m not sure how to get a
Kdelimited string into an array of string.
K>
Kinput: string looks like - 01-85-78-15-Q11
Koutput: an array with elements - 01,85,78,15 etc...
KIs there some sort of easy one liner that does this? Hard to search
Kthe help files for anything that would assist me in doing this.
K>
KThanks in advance.
K>
---
WBR,
Michael Nemtsev :: blog: http://spaces.msn.com/laflour
"At times one remains faithful to a cause only because its opponents do not
cease to be insipid." (c) Friedrich Nietzsche
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