将浮动文字指定为void * [英] assigning floating literal to void*

问题描述

如果我有以下内容：

void * x;

const char str [] =" abcdefghijklmn" ;;


我可以分配x = 0x12345678;

我可以分配x = str;


但是如何为x分配浮点文字以使内容x是这个文字浮点的IEEE754格式吗？

if I have the following:
void *x;
const char str[]="abcdefghijklmn";

I can assign x=0x12345678;
I can assign x=str;

but how can I assign a float literal to x such that the content of x is an IEEE754 format of this literal floating point?

推荐答案

所以你不希望x指向一个浮点变量，你想要的值是指针恰好与某个浮点值相同。


Zounds！我当然希望C不会让你这样做。你希望完成什么？

So you don''t want x to point at a float variable, you want the value of the pointer to coincidentally be the same as some floating-point value.

Zounds! I certainly hope C doesn''t let you do that. What do you hope to accomplish?

你可能有一个小数的播放器:)


但你不能有一个带小数的内存地址。

You may have a player with fractional number :)

But You cant have a memory address with fractional number.

@ hschew00，


我认为这会起作用。试一试......

@hschew00,

I think this''ll work. Give it a shot...

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