如何初始化一个字符数组的指针数组？ [英] How to initialize an array of pointers to an array of characters?
问题描述
您好，
我正在尝试初始化一个字符数组的指针数组，我可以在3行中完成，但我真的想在一行中完成它同时保持#define。
3行初始化（可以编译）
====================== br />
#define A 1
#define B 2
char row1 [] = {A | B，B，A};
char row2 [] = {B，A};
char * test [] = {row1，row2};
1行初始化（失败）
===============================
char * test [] = {{A | B，B，A}，{B，A}}; //< - 我该怎么办？
我不想要这个，因为它浪费了ROM空间
======== =====================================
char test [] [ 3] = {{A | B，B，A}，{B，A}};
非常感谢任何人都可以给我一些指示，thnx - paul 。
Hello,
I am trying to initialize an array of pointers to an array of characters, I can do it in 3 lines but I really want to do it in one line at the same time keeping the #define.
3 lines initialization (can compile)
======================
#define A 1
#define B 2
char row1[] = {A|B, B, A};
char row2[] = {B, A};
char *test[]= {row1, row2};
1 line initialization (failed)
===============================
char *test[] = { {A|B, B, A}, {B, A} }; // <- how do i do this??
I do not want this because it waste ROM space
=============================================
char test[][3] = { {A|B, B, A}, {B, A} };
Much appreciate if anyone can give me some pointers, thnx - paul.
推荐答案
第1行有三个元素，但第2行只有两个元素。您打算如何跟踪每行中有多少元素？您基本上有两个选项：明确指定行大小（添加一个字段以指定它）或隐式（硬编码到您的软件逻辑中。
Row 1 has three elements, but row 2 only has two elements. How do you plan to keep track of how many elements are in each row? You basically have two options: specify the row size explicitly (add a field to specify it) or implicitly (hard-coded into the logic of your software.
您好donbock，
感谢您的回复。是的，我打算添加一个终止字符来标记结束除此之外，您是否知道如何在一行中完成这项工作？
Hi donbock,
thanks for your reply. yes, i intend to add a termination character to mark the end of the row. That aside, are you aware of how this could be done in one line?
这篇关于如何初始化一个字符数组的指针数组？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
