双 [英] double

问题描述

我想知道0之后有多少位数会加倍。如果在特殊情况下不够大的话，还有

吗？

谢谢，

MJKUOG

解决方案

MJKUOG写道：

我想知道0之后的数字会保持多少。如果在特殊情况下不够大的话，还有

吗？

谢谢，

MJKUOG

假设IEEE-754，您有一个52位的尾数。从那里开始工作。

red floyd写道：

MJKUOG写道：

>
我想知道''0'之后有多少位数会加倍。

" After''0''"？你的意思是小数点后吗？

是否有

>无论如何增加它在特殊情况下不够大？
谢谢，
MJKUOG

假设IEEE-754，你有一个52位的尾数。从那里开始工作。

没有必要承担任何责任。使用值

std :: numeric_limits< double> :: digits10找出总数

可表示的小数位数，然后减去
$ b的数量小数点前的$ b位数，如果那真的是你之后的价格。


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Hi,
I am wondering how many digits after ''0'' does double keeps. Is there
anyway to increase it if it is not big enough in special cases?
Thanks,
MJKUOG

解决方案

MJKUOG wrote:

Hi,
I am wondering how many digits after ''0'' does double keeps. Is there
anyway to increase it if it is not big enough in special cases?
Thanks,
MJKUOG

Assuming IEEE-754, you have a 52-bit mantissa. Work from there.

red floyd wrote:

MJKUOG wrote:

>Hi,
I am wondering how many digits after ''0'' does double keeps.

"After ''0''"? Do you mean after decimal point?

Is there

>anyway to increase it if it is not big enough in special cases?
Thanks,
MJKUOG

Assuming IEEE-754, you have a 52-bit mantissa. Work from there.

There is no need to assume anything. Use the value of
std::numeric_limits<double>::digits10 to find out the total
representable decimal positions, then subtract the number of
digits before the decimal point, if that''s truly what you''re
after.

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