处理字节块 [英] Handling Blocks of Bytes

问题描述

关于处理的问题Byte []在java。


我必须读取任何类型的文件并将其切成块以便稍后处理。


想知道如果我做了一个Byte [] []将Byte []保存在一个数组中，或者其他东西是更好的方法，因为我现在知道Byte []数组可以容纳多少元素作为文件可能很大，块可能很小。


谢谢。 ：）

Just a question on handling "Byte[]" in java.

I have to read in a file of any type and chop it up into blocks for processing later on.

Was wondering if I got do a Byte[][] to keep the Byte[] in an array or would something else be a better way of doing it as I do now know how many elements the array of Byte[] can hold as the file might be huge and the blocks might be small.

Thanks. :)

推荐答案

只是关于处理的问题Byte []在java。


我必须读取任何类型的文件并将其切成块以便稍后处理。


想知道如果我做了一个Byte [] []将Byte []保存在一个数组中，或者其他东西是更好的方法，因为我现在知道Byte []数组可以容纳多少元素作为文件可能很大，块可能很小。


谢谢。 :)

Just a question on handling "Byte[]" in java.

I have to read in a file of any type and chop it up into blocks for processing later on.

Was wondering if I got do a Byte[][] to keep the Byte[] in an array or would something else be a better way of doing it as I do now know how many elements the array of Byte[] can hold as the file might be huge and the blocks might be small.

Thanks. :)

为什么不使用ArrayList< byte []>为了那个原因？只需将您在ArrayList中读取的所有byte [] s

叠加起来。


亲切的问候，


Jos

Why don''t you use an ArrayList<byte[]> for that? Simply stack up all the byte[]s
you have read in the ArrayList.

kind regards,

Jos

为什么不使用ArrayList< byte []>为了那个原因？只需将您在ArrayList中读取的所有byte [] s

叠加起来。


亲切的问候，


Jos

Why don''t you use an ArrayList<byte[]> for that? Simply stack up all the byte[]s
you have read in the ArrayList.

kind regards,

Jos

ok谢谢稍后试试：）

ok thanks will give it a try later :)

哦顺便说一句...只是为了确认，当我在将它们分成块之前先读入整个文件，Byte [19]会引用文件中的第20个字节吗？

oh btw... just to confirm, when i read in the whole file at the first go before chopping them up into blocks, Byte[19] would refer to the 20th byte in the file right?

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