浮点减法与FLT_MAX错误 [英] Floating point subtraction with FLT_MAX error

问题描述

只是一个小小的程序。无法弄清楚我做错了什么。


#include< stdio.h>

#include< limits.h>

#include< float.h>


int main（）

{


double max = FLT_MAX;

double sub = 16703.627681;


double result = max - sub;


printf（ ％f - ％f =％f \ n，最大，次，结果）;


返回0;

}


输出：

340282346638528859811704183484516925440.000000 - 16703.627681 =

340282346638528859811704183484516925440.000000

我们非常感谢任何帮助。


谢谢

Just a small little program. Can not figure out what am I doing wrong.

#include <stdio.h>
#include <limits.h>
#include <float.h>

int main()
{

double max = FLT_MAX;
double sub = 16703.627681;

double result = max - sub;

printf("%f - %f = %f\n", max, sub, result);

return 0;
}

Output:
340282346638528859811704183484516925440.000000 - 16703.627681 =
340282346638528859811704183484516925440.000000
Any help would be highly appreciated.

Thanks

推荐答案

10月25日晚上7:56，spooler ... @ gmail。 com写道：

On Oct 25, 7:56 pm, [e-mail] wrote:

只是一个小程序。无法弄清楚我做错了什么。


#include< stdio.h>

#include< limits.h>

#include< float.h>


int main（）

{


double max = FLT_MAX;

double sub = 16703.627681;


double result = max - sub;


printf（ ％f - ％f =％f \ n，max，sub，result）;


返回0;


}


输出：

340282346638528859811704183484516925440.000000 - 16703.627681 =

340282346638528859811704183484516925440.000000


任何帮助都会非常感谢。


谢谢

Just a small little program. Can not figure out what am I doing wrong.

#include <stdio.h>
#include <limits.h>
#include <float.h>

int main()
{

double max = FLT_MAX;
double sub = 16703.627681;

double result = max - sub;

printf("%f - %f = %f\n", max, sub, result);

return 0;

}

Output:
340282346638528859811704183484516925440.000000 - 16703.627681 =
340282346638528859811704183484516925440.000000

Any help would be highly appreciated.

Thanks

看来你正在尝试使用一个打印双倍（％Lf）

浮动（％f）因此您看到的错误。查看下面的链接

了解有关printf（）函数及其修饰符的更多信息。

http://www.cplusplus.com/reference/c...io/printf.html


Keith
http://www.doubleblackdesign.com
http://www.doubleblackdesign.com/forums

It appears that you are trying to print a double (%Lf) by using a
float (%f) hence the error you are seeing. Check out the link below
for more info on the printf() function and it''s modifiers.

http://www.cplusplus.com/reference/c...io/printf.html

Keith
http://www.doubleblackdesign.com
http://www.doubleblackdesign.com/forums

10月25日下午5:06，husterk< hust ... @ gmail.comwrote：

On Oct 25, 5:06 pm, husterk <[e-mail]:

10月25日晚上7:56，spooler ... @ gmail.com写道：

On Oct 25, 7:56 pm, [e-mail] wrote:

只是一个小小程序。无法弄清楚我做错了什么。

Just a small little program. Can not figure out what am I doing wrong.

#include< stdio.h>

#include< limits.h>

#include< float.h>

#include <stdio.h>
#include <limits.h>
#include <float.h>

int main（）

{

int main()
{

double max = FLT_MAX;

double sub = 16703.627681;

double max = FLT_MAX;
double sub = 16703.627681;

double result = max - sub;

double result = max - sub;

printf（"％f - ％f =％f \ n"，max，sub，result）;

printf("%f - %f = %f\n", max, sub, result);

返回0;

return 0;

}

}

输出：

340282346638528859811704183484516925440.000000 - 16703.627681 =

340282346638528859811704183484516925440.000000

Output:
340282346638528859811704183484516925440.000000 - 16703.627681 =
340282346638528859811704183484516925440.000000

我们非常感谢任何帮助。

Any help would be highly appreciated.

谢谢

Thanks

看来您正在尝试打印双倍（％Lf ）使用

浮点数（％f）因此出现错误。查看下面的链接

了解有关printf（）函数及其修饰符的更多信息。

http://www.cplusplus.com/reference/c...io/printf.html


Keithhttp：//www.doubleblackdesign.comhttp：//www.doubleblackdesign.com/forums

It appears that you are trying to print a double (%Lf) by using a
float (%f) hence the error you are seeing. Check out the link below
for more info on the printf() function and it''s modifiers.

http://www.cplusplus.com/reference/c...io/printf.html

Keithhttp://www.doubleblackdesign.comhttp://www.doubleblackdesign.com/forums

已经尝试过了。相同的结果。


％lf

340282346638528859811704183484516925440.000000 - 16703.627681 =

340282346638528859811704183484516925440.000000


％LF（不是长双吗？）

340282346638528859811704183484516925440.000000 - 16703.627681 =

0.000000

感谢您的回复。


另外据我所知，printf并不关心它是％f还是％lf因为

一切都变成了双倍，它是scanf抱怨的。如果我错了，请纠正我。

Tried that already. Same results.

%lf
340282346638528859811704183484516925440.000000 - 16703.627681 =
340282346638528859811704183484516925440.000000

%LF (Isn''t it for long double?)
340282346638528859811704183484516925440.000000 - 16703.627681 =
0.000000
Thanks for the reply.

Also as far as I know printf does not care if it is %f or %lf as
everything goes as double, it is scanf which complains. Correct me if
I am wrong.

sp ******** @ gmail.com 写道：

sp********@gmail.com wrote:

只是一个小小的程序。无法弄清楚我做错了什么。


#include< stdio.h>

#include< limits.h>

#include< float.h>


int main（）

{


double max = FLT_MAX;

double sub = 16703.627681;


double result = max - sub;


printf（ ％f - ％f =％f \ n，最大，次，结果）;


返回0;

}


输出：

340282346638528859811704183484516925440.000000 - 16703.627681 =

340282346638528859811704183484516925440.000000

Just a small little program. Can not figure out what am I doing wrong.

#include <stdio.h>
#include <limits.h>
#include <float.h>

int main()
{

double max = FLT_MAX;
double sub = 16703.627681;

double result = max - sub;

printf("%f - %f = %f\n", max, sub, result);

return 0;
}

Output:
340282346638528859811704183484516925440.000000 - 16703.627681 =
340282346638528859811704183484516925440.000000

如果发生你这样做：

double max = DBL_MAX;

What happens if you do:
double max = DBL_MAX;

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