Menu_Control_Uno.ino:249：2：错误：在'if'之前预期的unqualified-id错误compilin [英] Menu_Control_Uno.ino:249:2: error: expected unqualified-id before 'if' Error compilin

问题描述

不太确定是否有人可以帮助我但..........


我目前正在尝试为20x4 LCD构建菜单布局。我最初让液晶显示器与键盘一起使用，标题屏幕和密码登录密码是非正确的屏幕。


我正在使用Arduino Uno，它通过I2C连接插入20x04 LCD（显示在fitzrig中的1602型号）。使用6-13针将4x4 Matrix键盘插入uno。


我掌握了LCD上的菜单布局后，我将添加一个时钟模块，用于时间和日期以及LED希望使用晶体管来控制Arduino使用的引脚数量。


添加菜单编码后，我一直遇到连续错误。大多数我已经能够解决，直到这一点改变H文件等，但现在我有点不知道接下来要改变什么，因为我是arduino和编码的初学者。问题发生在第249行。我收到的错误信息是：


Menu_Control_Uno.ino:249：2：错误：在''if''之前预期的不合格ID />
编译错误。


菜单程序似乎在没有键盘和LCD代码的情况下自行编译，只要我把它们放在一起我就不得不工作了通过错误。由于菜单不能用于我的液晶显示器，我无法确定代码的确切含​​义，因此我可以根据自己的需要进行更改。


任何帮助都非常感谢


Arduino代码如下：第249行是菜单循环的第一行，以if开头，



if（Serial.available（））{

switch（Serial.read（））{

case''w''：

if（menu.isCurrentSubMenu（））{

subMenu.down（）; //设置索引接近0

}

休息;

case''s''：

如果（menu.isCurrentSubMenu（））{

subMenu.up（）; //设置索引接近最大值

}

休息;

case''a''：

menu .down（）;

休息;

案例''d''：

menu.up（）;

break;

case''''：

menu.use（）;

休息;

case''0''：

menu.select（0）;

break;

case''1''：

menu.select（1）;

休息;

case''2''：

menu.select（2 ）;

休息;

}

}

}


void menuChanged（ItemChangeEvent event）{

Serial.println（" menuChanged"）;

if（event ==& menuItem1）{

Serial.println（" \ tmenuItem1 selected"）; //用户反馈

}否则if（event ==& menuItemWithSubmenu）{

Serial.println（" \tmenuItemWithSubmenu selected"）; //用户反馈

}否则if（event ==& subMenuItem1）{

Serial.println（" \tsubMenuItem1 selected"）; //用户反馈

}否则if（event ==& subMenuItem2）{

Serial.println（" \ tsubMenuItem2 selected"）; //用户反馈

}否则if（event ==& subMenuItem3）{

Serial.println（" \ bitsubMenuItem3 selected"）; //用户反馈

}否则if（event ==& menuItem3）{

Serial.println（" \tmenuItem3 selected"）; //用户反馈

}

}


void menuUsed（ItemUseEvent event）{

Serial .println（QUOT; menuUsed"）;

if（event ==& menuItem1）{

Serial.println（" \tmenuItem1 used"）; //用户反馈

}否则if（event ==& subMenuItem1）{

Serial.println（" \tsubMenuItem1 used"）; //用户反馈

}否则if（event ==& subMenuItem2）{

Serial.println（" \tsubMenuItem2 used"）; //用户反馈

}否则if（event ==& subMenuItem3）{

Serial.println（" \tsubMenuItem3 used"）; //用户反馈

}否则if（event ==& menuItem3）{

Serial.println（" \tmenuItem3 used"）; //用户反馈

}

}

解决方案

我看到了menuChanged（ItemChangeEvent）和for的函数定义menuUsed（ItemUseEvent），但你的菜单代码不在函数内。


菜单代码在函数内？是吗？

感谢您的回复weaknessforcats。我认为它应该在一个函数内部，所以我可能需要移动它。我基本上有一个displayCodeEntryScreen，它会引导你进入一个menuScreen。


从这个菜单屏幕我希望能够在键盘上选择适用的号码，带我到那个子菜单。


我在arduino网站上找到了菜单代码，但我没有太多运气，所以我最近刚从代码中删除了它。因为我一直试图通过反复试验把不同部分的代码放在不同的部分。当我进入menuScreen并输入键盘时，它总是假设我正在尝试重新输入代码并立即将我恢复为displayCodeEntryScreen。


感谢您的帮助，我附上了完整的代码

展开 | 选择 | Wrap | 行号

您可以尝试这样的事情：

展开 | 选择 | Wrap | 行号

Hi,

Not quite sure if someone will be able to help me but..........

I am currently trying to build a menu layout for a 20x4 LCD. I originally had the LCD working with the keypad to have a title screen and password login with password right and wrong screens.

I am using an Arduino Uno which is plugged into an 20x04 LCD (1602 model shown in fitzrig) via I2C Connection. The 4x4 Matrix keypad is plugged into the uno using pins 6-13.

After I have mastered the menu layout on the LCD I will add in a clock module for time and date and LED''s which will hopefully be controlled using a transistor to reduce the amount of pins used by the Arduino.

After adding the bits of menu coding I have been getting continuous errors. Most I have been able to solve up until this point changing H files etc, but now I am at a bit of a loss as to what to change next as I am a beginner to arduino and coding. the problem is occurring at line 249. The error message I am receiving is:

Menu_Control_Uno.ino:249:2: error: expected unqualified-id before ''if''
Error compiling.

The menu program seems to compile on its own without the keypad and LCD code, as soon as I put them all together I have had to work through errors. Because the menu isn''t working with my LCD I can not tell what exactly the code has done so I can alter it to suit my own needs.

any help out be greatly appreciated

The Arduino code is as follows: line 249 is the first line of the menu loop starting with the word "if"


if (Serial.available()){
switch (Serial.read()){
case ''w'':
if (menu.isCurrentSubMenu()){
subMenu.down(); //set index closer to 0
}
break;
case ''s'':
if (menu.isCurrentSubMenu()){
subMenu.up(); //set index closer to maximum
}
break;
case ''a'':
menu.down();
break;
case ''d'':
menu.up();
break;
case '' '':
menu.use();
break;
case ''0'':
menu.select(0);
break;
case ''1'':
menu.select(1);
break;
case ''2'':
menu.select(2);
break;
}
}
}

void menuChanged(ItemChangeEvent event){
Serial.println("menuChanged");
if( event == &menuItem1 ){
Serial.println("\tmenuItem1 selected"); //user feedback
}else if( event == &menuItemWithSubmenu ){
Serial.println("\tmenuItemWithSubmenu selected"); //user feedback
}else if( event == &subMenuItem1 ){
Serial.println("\tsubMenuItem1 selected"); //user feedback
}else if( event == &subMenuItem2 ){
Serial.println("\tsubMenuItem2 selected"); //user feedback
}else if( event == &subMenuItem3 ){
Serial.println("\tsubMenuItem3 selected"); //user feedback
}else if( event == &menuItem3 ){
Serial.println("\tmenuItem3 selected"); //user feedback
}
}

void menuUsed(ItemUseEvent event){
Serial.println("menuUsed");
if( event == &menuItem1 ){
Serial.println("\tmenuItem1 used"); //user feedback
}else if( event == &subMenuItem1 ){
Serial.println("\tsubMenuItem1 used"); //user feedback
}else if( event == &subMenuItem2 ){
Serial.println("\tsubMenuItem2 used"); //user feedback
}else if( event == &subMenuItem3 ){
Serial.println("\tsubMenuItem3 used"); //user feedback
}else if( event == &menuItem3 ){
Serial.println("\tmenuItem3 used"); //user feedback
}
}

解决方案

I see function definitions for menuChanged(ItemChangeEvent) and for menuUsed(ItemUseEvent) but your menu code is not inside a function.

The menu code is inside a function? Yes?

Thanks for your reply weaknessforcats. I think it is meant to be inside a function so I may need to move it. I basically have a displayCodeEntryScreen which leads you to a menuScreen.

From this menu screen I want to be able select the applicable number on the keypad to take me to that submenu.

I found the menu code on the arduino website, but I wasn''t having much luck with it so I just recently removed it from the code. Since I have been trying to put bits of code in different parts through trial and error. when I get to the menuScreen and input the keyboard, it always assumes that I am trying to re-enter the code and instantly reverts me back to the displayCodeEntryScreen.

Thanks for your help, I have attached the full code

Expand|Select|Wrap|Line Numbers

You might try something like this:

Expand|Select|Wrap|Line Numbers

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