如何从字节到位变量分配一个位？ [英] How do you assign a bit from a byte to a bit variable?
问题描述
我有一个1位宽的变量。我还有一个变量是一个
字节。我想将这些位从字节中移出到位变量
（一次一个），但我不知道该怎么做或者它是否是偶数
可能。这是我的代码的样子：
//数据是一个大小为1个字节的变量，而bitVariable是一个大小为
的1位。我是一个字节。
for（i = 0; i< 8; i ++）
{
bitVariable =（数据<< i）& 0x80;
}
我不相信这会有效，因为没有迹象表明
真的被分配了to bitVariable。我的编译器没有抱怨和
我发现这很奇怪。本质上，我需要将数据中的位移位。在我的微控制器上输出一个输出端口，并希望尽可能快地完成它。
I have a variable that is 1 bit wide. I also have a variable that is a
byte. I want to shift the bits out of the byte into the bit variable
(one at a time) but am not sure how to do this or whether it is even
possible. Here is what my code looks like:
// data is a variable 1 byte in size while bitVariable is 1 bit in
size. i is a byte.
for (i = 0; i < 8; i++)
{
bitVariable = (data << i) & 0x80;
}
I don''t believe this will work because there is no indication what is
really being assigned to bitVariable. My compiler doesn''t complain and
I find that strange. Essentially, I need to shift the bits in "data" to
an output port on my microcontroller and want to do it as quickly as
possible.
推荐答案
jo*********@yahoo.com 写道：
我有一个1位宽的变量。我还有一个变量是一个
字节。我想将这些位从字节中移位到位变量
（一次一个），但我不知道如何做到这一点，或者它是否可能。以下是我的代码：/ //
//数据大小为1个字节，而bitVariable大小为1位。我是一个字节。
for（i = 0; i< 8; i ++）
{/ / bitVariable =（data<< i）& 0x80;
I have a variable that is 1 bit wide. I also have a variable that is a
byte. I want to shift the bits out of the byte into the bit variable
(one at a time) but am not sure how to do this or whether it is even
possible. Here is what my code looks like:
// data is a variable 1 byte in size while bitVariable is 1 bit in
size. i is a byte.
for (i = 0; i < 8; i++)
{
bitVariable = (data << i) & 0x80;
你想要数据在MS位吗？
应该是
bitVariable =（data>> i）& 0x01;
-
Ian Collins。
Do you want the data to be in the MS bit?
Should it be
bitVariable = (data >> i) & 0x01;
--
Ian Collins.
将数据移出' 'data''变量，必须将最高位
有效位的位分配给变量
''bitVariable''。
Ian Collins写道：
When shifting the data out of the ''data'' variable, the bit in the most
significant bit position must be assigned to the variable
''bitVariable''.
Ian Collins wrote:
你想要数据在MS位吗？
应该是
bitVariable =（data>> ; i）& 0x01;
- Ian Collins。
Do you want the data to be in the MS bit?
Should it be
bitVariable = (data >> i) & 0x01;
--
Ian Collins.
jo ********* @ yahoo.com 写道：
Ian Collins写道：
Ian Collins wrote:
你想要数据在MS位吗？
应该是
bitVariable =（data>> i） &安培; 0x01;
Do you want the data to be in the MS bit?
Should it be
bitVariable = (data >> i) & 0x01;
当从数据变量中移出数据时，必须将最高位位置的位分配给变量
''bitVariable' '。
When shifting the data out of the ''data'' variable, the bit in the most
significant bit position must be assigned to the variable
''bitVariable''.
请不要发帖。
所以bitVariable是一个硬件注册？
-
Ian Collins。
Please don''t top post.
So bitVariable is a hardware register?
--
Ian Collins.
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