枚举类型的匿名结构 [英] enum-type anonymous structs
问题描述
如果我尝试在gcc中编译它，它会说：错误：请求成员
`baz''在非结构或联合的东西中。
关于如何制作一个结构的任何变通方法或提示
表现得像一个枚举，但其成员可以用''来表达。''？
我不喜欢我想要使用#defines来做这件事，因为它太多了
凌乱。
代码：
static struct {
static const int baz = 1;
} bar;
void foo（）{
int x = bar.baz;
}
If I try compiling this in gcc, it says: "error: request for member
`baz'' in something not a structure or union".
Any workarounds or tips on how to make a structure such that it
behaves like an enum but its members can be addressed with ''.''?
I don''t want to have to do this using #defines, as it would be far too
messy.
code:
static struct {
static const int baz = 1;
} bar;
void foo() {
int x = bar.baz;
}
推荐答案
andreyvul< andrey .... @ gmail.comwrote：
andreyvul <andrey....@gmail.comwrote:
如果我尝试在gcc中编译它，它会说：错误：请求
成员`baz''在某个结构中或者联合。
关于如何制作这样的结构的任何变通方法或提示
它表现得像枚举，但其成员可以是
用''。''解决？
If I try compiling this in gcc, it says: "error: request
for member `baz'' in something not a structure or union".
Any workarounds or tips on how to make a structure such
that it behaves like an enum but its members can be
addressed with ''.''?
No.
No.
我不想使用#defines这样做，因为它将是b / b
太乱了。
代码：
静态结构{
* * static const int baz = 1;
I don''t want to have to do this using #defines, as it
would be far too messy.
code:
static struct {
* * static const int baz = 1;
这不合法C.
This is not legal C.
} bar;
void foo（）{
* * int x = bar.baz;
}
} bar;
void foo() {
* * int x = bar.baz;
}
C ++可能具有你正在寻找的功能。
明智的命名约定就像你将来的那样接近
in C.
-
Peter
C++ probably has the feature you''re looking for.
Judicious naming conventions is as close as you''ll come
in C.
--
Peter
1月2日晚上8:03，Peter Nilsson< ai。 .. @ acay.com.auwrote：
On Jan 2, 8:03 pm, Peter Nilsson <ai...@acay.com.auwrote:
andreyvul< andrey .... @ gmail.comwrote：
andreyvul <andrey....@gmail.comwrote:
如果我尝试在gcc中编译它，它会说：错误：请求
成员`baz''在非结构或联合的东西中。
关于如何制作这样一个结构的任何变通方法或技巧
它的行为就像一个枚举，但它的成员可以用''。''来代表
？
If I try compiling this in gcc, it says: "error: request
for member `baz'' in something not a structure or union".
Any workarounds or tips on how to make a structure such
that it behaves like an enum but its members can be
addressed with ''.''?
No.
No.
我不想使用#defines这样做，因为它将会非常混乱。
代码：
静态结构{
static const int baz = 1 ;
I don''t want to have to do this using #defines, as it
would be far too messy.
code:
static struct {
static const int baz = 1;
这不合法C.
This is not legal C.
} bar;
} bar;
void foo（）{
int x = bar.baz;
}
void foo() {
int x = bar.baz;
}
C ++可能具有您正在寻找的功能。
C++ probably has the feature you''re looking for.
我知道。
I know.
明智的命名惯例尽可能接近
in C.
Judicious naming conventions is as close as you''ll come
in C.
:(
所以我坚持#defines，然后呢？
:(
So I''m stuck to #defines, then?
-
Peter
--
Peter
2008年1月2日星期三16:12:14 -0800（太平洋标准时间），andreyvul
< an ******** @ gmail.comwrote：
On Wed, 2 Jan 2008 16:12:14 -0800 (PST), andreyvul
<an********@gmail.comwrote:
>如果我尝试在gcc中编译它，它说：错误：请求成员
`baz''在某种结构或联合的东西中。
任何关于如何建立一个结构的解决方法或提示
表现得像一个枚举，但其成员可以用''。''来解决？
我不想使用#defines这样做，因为它太麻烦了。
代码：
静态结构{
static const int baz = 1;
}吧;
void foo（）{
int x = bar.baz; }
>If I try compiling this in gcc, it says: "error: request for member
`baz'' in something not a structure or union".
Any workarounds or tips on how to make a structure such that it
behaves like an enum but its members can be addressed with ''.''?
I don''t want to have to do this using #defines, as it would be far too
messy.
code:
static struct {
static const int baz = 1;
} bar;
void foo() {
int x = bar.baz;
}
枚举和结构的功能是如何相交的？
-
Dan Henry
How does the functionality of enums and structures intersect?
--
Dan Henry
这篇关于枚举类型的匿名结构的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
