在空白处充分利用[10]来输出i的内容 [英] full in the blank , making use of a[10] to outputcontent of i

问题描述

#include< stdio.h>

main（）

{

int i;

char a [10];

scanf（"％d"& i）;

_________________

_________________ \\ *已满在空白处，利用[10]至

输出内容i * \\

printf（"％s"，a）;

}


任何人都可以帮助我吗？

#include<stdio.h>
main()
{
int i;
char a[10];
scanf("%d",&i);
_________________
_________________\\*full in the blank , making use of a[10] to
outputcontent of i*\\
printf("%s",a);
}

can anyone help me?

推荐答案

"喜欢C lang.Chinese写道：

"liking C lang.Chinese" wrote:

>

#include< stdio.h>

main（）

{

int i;

char a [10];

scanf（"％d"，& i） ;

_________________

_________________ \\ *在空白处填写，利用[10]来确定i * \\的
输出内容\\\

printf（"％s"，a）;

}


有人可以帮我吗？

>
#include<stdio.h>
main()
{
int i;
char a[10];
scanf("%d",&i);
_________________
_________________\\*full in the blank , making use of a[10] to
outputcontent of i*\\
printf("%s",a);
}

can anyone help me?

我们不做作业。提示，阅读库的标准

函数。但是......


你的导师给了你一个不可能完成的任务，因为

大纲计划首先是无效的。 main返回一个

int，并且应该写成int main（void）无论如何（必须是

C99）。该程序无法返回一个值，该值对于

C90无效。所以无论你使用什么标准，该程序都是无效的。
无效。


找一位至少知道主题的讲师或课程

正在尝试教学。


-

< http://www.cs.auckland.ac.nz/~pgut001/pubs /vista_cost.txt>

< http://www.securityfocus.com/columnists/423>


"每次都是正确的男人不太可能做得太多。

- Francis Crick，共同发现DNA

没有什么比行动中的愚蠢更令人惊讶了。

- Thomas Matthews

We don''t do homework. Hint, read the C standard for library
functions. However ...

Your instructor has given you an impossible task, because the
outline program is invalid in the first place. main returns an
int, and should be written as "int main(void)" anyhow (must be for
C99). The program fails to return a value, which is invalid for
C90. So regardless of what standard you use, the program is
invalid.

Find an instructor or course that at least knows the subject they
are trying to teach.

--
<http://www.cs.auckland.ac.nz/~pgut001/pubs/vista_cost.txt>
<http://www.securityfocus.com/columnists/423>

"A man who is right every time is not likely to do very much."
-- Francis Crick, co-discover of DNA
"There is nothing more amazing than stupidity in action."
-- Thomas Matthews

On 2 ??15è？，????2ê±57·?, CBFalconer< ; cbfalco ... @ yahoo.comwrote：

On 2??15è?, ????2ê±57·?, CBFalconer <[e-mail]:

" liking C lang.Chinese"写道：

"liking C lang.Chinese" wrote:

#include< stdio.h>

main（）

{

int i;

char a [10];

scanf（"％d"，& i）;

_________________

_________________ \\ *在空白处填写，使用[10]到

输出内容i * \\

printf（"％s"，a）;

}

#include<stdio.h>
main()
{
int i;
char a[10];
scanf("%d",&i);
_________________
_________________\\*full in the blank , making use of a[10] to
outputcontent of i*\\
printf("%s",a);
}

有人可以帮我吗？

can anyone help me?

我们不做作业。提示，阅读库的标准

函数。但是......


你的导师给了你一个不可能完成的任务，因为

大纲计划首先是无效的。 main返回一个

int，并且应该写成int main（void）无论如何（必须是

C99）。该程序无法返回一个值，该值对于

C90无效。所以无论你使用什么标准，该程序都是无效的。
无效。


找一位至少知道主题的讲师或课程

正在尝试教学。


-

< http://www.cs.auckland.ac.nz/~pgut001/pubs /vista_cost.txt>

< http://www.securityfocus.com/columnists/423>


"每次都是正确的男人不太可能做得太多。

- Francis Crick，共同发现DNA

没有什么比行动中的愚蠢更令人惊讶了。

- Thomas Matthews

We don''t do homework. Hint, read the C standard for library
functions. However ...

Your instructor has given you an impossible task, because the
outline program is invalid in the first place. main returns an
int, and should be written as "int main(void)" anyhow (must be for
C99). The program fails to return a value, which is invalid for
C90. So regardless of what standard you use, the program is
invalid.

Find an instructor or course that at least knows the subject they
are trying to teach.

--
<http://www.cs.auckland.ac.nz/~pgut001/pubs/vista_cost.txt>
<http://www.securityfocus.com/columnists/423>

"A man who is right every time is not likely to do very much."
-- Francis Crick, co-discover of DNA
"There is nothing more amazing than stupidity in action."
-- Thomas Matthews

非常感谢你。

Thank you very very very much.

On 2 ??15è？，????2ê±57·?, CBFalconer< cbfalco ... @ yahoo.comwrote：

On 2??15è?, ????2ê±57·?, CBFalconer <[e-mail]:

" ;喜欢C lang.Chinese写道：

"liking C lang.Chinese" wrote:

#include< stdio.h>

main（）

{

int i;

char a [10];

scanf（"％d"，& i）;

_________________

_________________ \\ *在空白处填写，使用[10]到

输出内容i * \\

printf（"％s"，a）;

}

#include<stdio.h>
main()
{
int i;
char a[10];
scanf("%d",&i);
_________________
_________________\\*full in the blank , making use of a[10] to
outputcontent of i*\\
printf("%s",a);
}

有人可以帮我吗？

can anyone help me?

我们不做作业。提示，阅读库的标准

函数。但是......


你的导师给了你一个不可能完成的任务，因为

大纲计划首先是无效的。 main返回一个

int，并且应该写成int main（void）无论如何（必须是

C99）。该程序无法返回一个值，该值对于

C90无效。所以无论你使用什么标准，该程序都是无效的。
无效。


找一位至少知道主题的讲师或课程

正在尝试教学。


-

< http://www.cs.auckland.ac.nz/~pgut001/pubs /vista_cost.txt>

< http://www.securityfocus.com/columnists/423>


"每次都是正确的男人不太可能做得太多。

- Francis Crick，共同发现DNA

没有什么比行动中的愚蠢更令人惊讶了。

- Thomas Matthews

We don''t do homework. Hint, read the C standard for library
functions. However ...

Your instructor has given you an impossible task, because the
outline program is invalid in the first place. main returns an
int, and should be written as "int main(void)" anyhow (must be for
C99). The program fails to return a value, which is invalid for
C90. So regardless of what standard you use, the program is
invalid.

Find an instructor or course that at least knows the subject they
are trying to teach.

--
<http://www.cs.auckland.ac.nz/~pgut001/pubs/vista_cost.txt>
<http://www.securityfocus.com/columnists/423>

"A man who is right every time is not likely to do very much."
-- Francis Crick, co-discover of DNA
"There is nothing more amazing than stupidity in action."
-- Thomas Matthews

但我使用的工具是truboc2.0。

but I use the toolis truboc2.0 .

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