生成长度为5的随机数字 [英] generate random digits with length of 5

问题描述

想知道是否有更好的方法来生成数字字符串

a长度为5，并且数字前面也可以有0。

< pre>

random_number = random.sample（[0,1,2,3,4,5,6,7,8,9]，5）#select 5

元素

code =''这是一个字符串''+ str（random_number [0]）+

str（random_number [1]）+ str（random_number [2 ]）+ str（random_number [3]）

+ str（random_number [4]）

< / pre>

解决方案

2008年9月28日星期日下午12:59，sotirac< so ***** @ gmail.comwrote：

想知道是否有更好的方法来生成数字字符串

a长度为5，并且数字前面也可以有0。


< pre>

random_number = random.sample（[0,1,2,3,4,5,6,7,8,9]，5）#select 5

元素

code =''这是一个字符串''+ str（rand om_number [0]）+

str（random_number [1]）+ str（random_number [2]）+ str（random_number [3]）

+ str（random_number [ 4]）

code =''''。join（random_number中数字的str（数字））


问候，

Chris

< / pre>


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沿着鬣蜥的路径......
http://rebertia.com

9月28日，2：59 * pm，sotirac< soti ... @ gmail.comwrote：

想知道是否有更好的方法来生成
$ b的数字串$ ba长度为5，前面的数字也可以为0.


< pre>

* random_number = random.sample（[0,1,2,3,4,5,6,7,8,9]，5）#select 5

元素

* code =''这是一个字符串''+ str（random_number [0]）+

str（random_number [1]）+ str（random_number [2]）+ str（random_number [3]）

+ str（random_number [4]）

< / pre>

''％05i''％random.randint（0,99999）

Chris Rebert写道：

On Sun，Sep 28,2008 at 12:59 PM，sotirac< so ***** @ gmail.comwrote：

>想知道是否有更好的方法来生成长度为5的数字串，也可以在数字前面加上0。

< pre>
random_number = random.sample（[0,1,2,3,4,5,6,7,8,9]，5）#select 5
elements
code =''这是一个字符串''+ str（random_number [0]）+
str（random_number [1]）+ str（random_number [2]）+ str（random_number [3]）
+ str（random_number [4]）

code =''''。join（random_number中数字的str（数字））


问候，

克里斯

>< / pre>

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http://mail.python.org/mailman/listinfo/python-list

random.randint（10000,99999）会为你工作吗？

Wondering if there is a better way to generate string of numbers with
a length of 5 which also can have a 0 in the front of the number.
<pre>
random_number = random.sample([0,1,2,3,4,5,6,7,8,9], 5) # choose 5
elements
code = ''this is a string'' + str(random_number[0]) +
str(random_number[1]) + str(random_number[2]) + str(random_number[3])
+ str(random_number[4])
</pre>

解决方案

On Sun, Sep 28, 2008 at 12:59 PM, sotirac <so*****@gmail.comwrote:

Wondering if there is a better way to generate string of numbers with
a length of 5 which also can have a 0 in the front of the number.
<pre>
random_number = random.sample([0,1,2,3,4,5,6,7,8,9], 5) # choose 5
elements
code = ''this is a string'' + str(random_number[0]) +
str(random_number[1]) + str(random_number[2]) + str(random_number[3])
+ str(random_number[4])

code = ''''.join(str(digit) for digit in random_number)

Regards,
Chris

</pre>

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Follow the path of the Iguana...
http://rebertia.com

On Sep 28, 2:59*pm, sotirac <[e-mail]:

Wondering if there is a better way to generate string of numbers with
a length of 5 which also can have a 0 in the front of the number.

<pre>
*random_number = random.sample([0,1,2,3,4,5,6,7,8,9], 5) # choose 5
elements
*code = ''this is a string'' + str(random_number[0]) +
str(random_number[1]) + str(random_number[2]) + str(random_number[3])
+ str(random_number[4])
</pre>

''%05i''%random.randint(0,99999)

Chris Rebert wrote:

On Sun, Sep 28, 2008 at 12:59 PM, sotirac <so*****@gmail.comwrote:

>Wondering if there is a better way to generate string of numbers with
a length of 5 which also can have a 0 in the front of the number.
<pre>
random_number = random.sample([0,1,2,3,4,5,6,7,8,9], 5) # choose 5
elements
code = ''this is a string'' + str(random_number[0]) +
str(random_number[1]) + str(random_number[2]) + str(random_number[3])
+ str(random_number[4])

code = ''''.join(str(digit) for digit in random_number)

Regards,
Chris

></pre>

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will random.randint(10000,99999) work for you?

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