引用问题 [英] Problem with references
问题描述
在课程AI中获得''SomeType''的引用：
A级{
SomeType测试;
公开：
A（SomeType& someT）{
test = someT;
}
...
...
};
但是如果我在测试中做的操作在someT实例中不可见
因为test是本地副本。但是我该如何测试一个参考副本
of someT所以当我改变测试时我也改变了一些？
meekee写道：
在课程AI中获得对''SomeType''的引用：
class A {
SomeType测试;
公开：
A（SomeType& someT）{
test = SOMET;
不要分配。初始化。
>
}
..
..
};
但如果我在测试中进行操作，则在someT
实例中不可见，因为test是本地副本。但是我如何进行测试
参考副本？ someT所以当我改变测试时我也改变了一些？
让你的''test''成员成为SomeType的引用，并在初始化列表中初始化它为
。你对''test''所做的所有chagnes都将在''someT'所引用的对象中显示为
。
V
-
请在通过电子邮件回复时删除资金''A'
我不回复热门帖子回复，请不要问
Victor Bazarov写道：
meekee写道：
< blockquote class =post_quotes>
>在类AI中获得对''SomeType''的引用：
A类{
SomeType测试;
public：
A（SomeType& someT）{
test = someT;
不要分配。初始化。
>}
..
..
};
但如果我因为test是本地副本，所以在someT
实例中看不到测试操作。但是我该如何进行测试？参考副本 someT所以当我改变测试时我也改变了一些？
让你的''test''成员成为SomeType的引用，并在初始化列表中初始化它为
。你对''test''所做的所有chagnes都将在''someT'所引用的对象中显示为
。
V
我试过让测试成员引用SomeType：
SomeType&测试;
然后我得到一个错误，禁止它初始化字段。如何使用
构造函数中首次出现的参数初始化一个字段成员？
On Sep 27，下午2:32，meekee< mee ... @dd.comwrote：
在课程AI中获得对''SomeType''的引用：
A级{
// SomeType测试;
SomeType&测试;
>
public：
A（SomeType& someT）{
test = someT;
}
..
..
};
但是如果我在测试中进行操作，则在someT实例中看不到
，因为test是本地副本。但是我该如何测试某个参考副本某些东西的b $ b，所以当我改变测试时我也会改变某些东西？
In class A I get a reference to ''SomeType'':
class A {
SomeType test;
public:
A(SomeType& someT) {
test = someT;
}
...
...
};
But if I do operations on test the are not visible in the someT instance
since test is a local copy. But how do I make test a "reference copy"
of someT so when I change test I also change someT?
meekee wrote:In class A I get a reference to ''SomeType'':
class A {
SomeType test;
public:
A(SomeType& someT) {
test = someT;Don''t assign. Initialise.
>
}
..
..
};
But if I do operations on test the are not visible in the someT
instance since test is a local copy. But how do I make test a
"reference copy" of someT so when I change test I also change someT?Let your ''test'' member be a reference to SomeType, and initialise it
in the initialiser list. The all chagnes you make to ''test'' will be
visible in the object referred to by ''someT'', as well.
V
--
Please remove capital ''A''s when replying by e-mail
I do not respond to top-posted replies, please don''t ask
Victor Bazarov wrote:meekee wrote:>In class A I get a reference to ''SomeType'':
class A {
SomeType test;
public:
A(SomeType& someT) {
test = someT;
Don''t assign. Initialise.
>}
..
..
};
But if I do operations on test the are not visible in the someT
instance since test is a local copy. But how do I make test a
"reference copy" of someT so when I change test I also change someT?
Let your ''test'' member be a reference to SomeType, and initialise it
in the initialiser list. The all chagnes you make to ''test'' will be
visible in the object referred to by ''someT'', as well.
V
I have tried making the test member a reference to SomeType:
SomeType& test;
but then I get an error that its forbidden to initialize the field. How
do I initialize a field member with an argument that first available in
the constructor?
On Sep 27, 2:32 pm, meekee <mee...@dd.comwrote:In class A I get a reference to ''SomeType'':
class A {//SomeType test;
SomeType& test;
>
public:
A(SomeType& someT) {
test = someT;
}
..
..
};
But if I do operations on test the are not visible in the someT instance
since test is a local copy. But how do I make test a "reference copy"
of someT so when I change test I also change someT?
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