的atoi（） [英] atoi()

问题描述

C'的atoi（）的首选C ++替代品是什么？如果有的话？


-

Christopher Benson-Manica |我*应该*知道我在说什么 - 如果我

ataru（at）cyberspace.org |不，我需要知道。火焰欢迎。

What is the preferred C++ alternative to C''s atoi(), if there is one?

--
Christopher Benson-Manica | I *should* know what I''m talking about - if I
ataru(at)cyberspace.org | don''t, I need to know. Flames welcome.

推荐答案

" Christopher Benson-Manica" <在*** @ nospam.cyberspace.org>写在

消息新闻：bu ********** @ chessie.cirr.com ...

"Christopher Benson-Manica" <at***@nospam.cyberspace.org> wrote in
message news:bu**********@chessie.cirr.com...

什么是C'的首选C ++替代品atoi（），如果有
一个？
-
Christopher Benson-Manica |我*应该*知道我在说什么b $ b关于 - 如果我ataru（at）cyberspace.org |不，我需要知道。火焰欢迎。

What is the preferred C++ alternative to C''s atoi(), if there is one?
--
Christopher Benson-Manica | I *should* know what I''m talking about - if I ataru(at)cyberspace.org | don''t, I need to know. Flames welcome.

标准的替代方案是构造一个stringstream并使用>>将其

数据读入int。另见
http://www.boost.org/ libs / conversion / lexical_cast.htm 。


Jonathan

The standard alternative is to construct a stringstream and read its
data into an int using >>. See also
http://www.boost.org/libs/conversion/lexical_cast.htm.

Jonathan

Jonathan Turkanis< te ***** *@kangaroologic.com>这样说：

Jonathan Turkanis <te******@kangaroologic.com> spoke thus:

标准的替代方案是使用>>构造一个字符串流并将其数据读入一个int。

The standard alternative is to construct a stringstream and read its
data into an int using >>.

您会在以下情况下推荐这种方法吗？


#include< cstdlib>


int main（ int argc，char * argv []）

{

int count = 0;

if（argc> 1）{

count = atoi（argv [1]）; //< - 值得设置一个字符串流？

}

返回EXIT_SUCCESS;

}


-

Christopher Benson-Manica |我*应该*知道我在说什么 - 如果我

ataru（at）cyberspace.org |不，我需要知道。火焰欢迎。

You would recommend such an approach in the following situation?

#include <cstdlib>

int main( int argc, char *argv[] )
{
int count=0;
if( argc > 1 ) {
count=atoi( argv[1] ); // <- worth setting up a stringstream?
}
return EXIT_SUCCESS;
}

--
Christopher Benson-Manica | I *should* know what I''m talking about - if I
ataru(at)cyberspace.org | don''t, I need to know. Flames welcome.

Christopher Benson-Manica写道：

Christopher Benson-Manica wrote:

Jonathan Turkanis< te ****** @ kangaroologic.com>这样说：

Jonathan Turkanis <te******@kangaroologic.com> spoke thus:

标准的替代方案是使用>>构建一个字符串流并将其数据读入一个int。

int main（int argc，char * argv []）
{
int count = 0;
if（argc> 1）{
count = atoi（argv [1]）; //< - 值得设置一个字符串流吗？

The standard alternative is to construct a stringstream and read its
data into an int using >>.

You would recommend such an approach in the following situation?

#include <cstdlib>

int main( int argc, char *argv[] )
{
int count=0;
if( argc > 1 ) {
count=atoi( argv[1] ); // <- worth setting up a stringstream?

你忘了std ::。

}
返回EXIT_SUCCESS;
}

You forgot std::.
}
return EXIT_SUCCESS;
}

好​​吧，atoi（）在错误检测和&b; b $ b b恢复方面没有太大帮助。如果我正确地回忆起它，它会在溢出时默默地调用未定义的行为。我建议使用stringstream方法或

可能是strtol（）或相关函数 - 无论你认为哪个是适合这种情况的
。


-Kevin

-

我的电子邮件地址有效，但会定期更改。

要联系我，请使用最近发布的地址。

Well, atoi() doesn''t allow much in the way of error detection &
recovery. It silently invokes undefined behavior on overflow, if I
recall correctly. I''d recommend using either the stringstream method or
possibly strtol() or a related function - whichever you think is
appropriate for the situation.

-Kevin
--
My email address is valid, but changes periodically.
To contact me please use the address from a recent posting.

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