调用函数名称 [英] Calling function name
本文介绍了调用函数名称的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
有没有办法让某个功能知道谁给他打电话?
Is there an way for a function to know who called him ?
推荐答案
最新的gcc,vs.net支持__FUNCTION__,使用它
#include< stdio.h>
int func1(char * str)
{
printf(由%s \ nn,str调用);
返回0;
}
int main(无效)
{
func1(__ FUNCTION__);
返回0;
}
Saroj写道:
lastest gcc ,vs.net support __FUNCTION__, use it
#include <stdio.h>
int func1(char * str)
{
printf("called by %s\n",str);
return 0;
}
int main(void)
{
func1(__FUNCTION__);
return 0;
}
Saroj wrote:
有没有办法让函数知道是谁打电话给他?
Is there an way for a function to know who called him ?
>
baumann @ pan写道:
baumann@pan wrote:
最新的gcc,vs.net支持__FUNCTION__,使用它
#include< stdio.h>
int func1(char * str)
{/> printf("%s \ n" ,str);
返回0;
}
int main(无效)
{
func1(__ FUNCTION__);
返回0;
}
Saroj写道:
lastest gcc ,vs.net support __FUNCTION__, use it
#include <stdio.h>
int func1(char * str)
{
printf("called by %s\n",str);
return 0;
}
int main(void)
{
func1(__FUNCTION__);
return 0;
}
Saroj wrote:
有没有办法让某个函数知道是谁打电话给他?
Is there an way for a function to know who called him ?
还有另一种方式吗?
这种方式如下:
int main()
{
func1(" main"); //但需要将func1(char *)变为
// func1(const char *)
返回0;
}
Is there another way?
This way look like:
int main()
{
func1("main"); // but need to chage func1(char*) to
// func1(const char*)
return 0;
}
#if DISPLAY_CALLER
#define func1_hooked()func1(__ FUNCTION__)
#else
#define func1_hooked()func1(0)
#endif
now
<主要是
,
int main(无效)
{
func1_hooked();
返回0;
}
baumann @ pan写道:
#if DISPLAY_CALLER
#define func1_hooked() func1(__FUNCTION__)
#else
#define func1_hooked() func1(0)
#endif
now
in main,
int main(void)
{
func1_hooked();
return 0;
}
baumann@pan wrote:
最新的gcc,vs.net支持__FUNCTION__,使用它
#include< stdio.h>
int func1(char * str)
{
printf("%s \ n",str);
返回0;
}
int main(void)
{
func1(__ FUNCTION__);
返回0;
}
Saroj写道:
lastest gcc ,vs.net support __FUNCTION__, use it
#include <stdio.h>
int func1(char * str)
{
printf("called by %s\n",str);
return 0;
}
int main(void)
{
func1(__FUNCTION__);
return 0;
}
Saroj wrote:
有没有办法让函数知道谁给他打电话?
Is there an way for a function to know who called him ?
>
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