mysql_fetch_array问题 [英] mysql_fetch_array problem
问题描述
我设置了phpmyadmin,它工作正常,但我的代码不起作用。 id是
正确的列(它是主键),stock是正确的数据库。
代码:
$ qresult = mysql_query(" SELECT id FROM''stock''");
echo(" START< P>< HR>");
while($ row = mysql_fetch_array($ qresult)){
echo($ row [" name"]);
echo("< br>" );
}
echo("< P>< HR>< P> END");
输出:
START
警告:mysql_fetch_array():提供的参数不是/ home / houseproudlancs_co_uk / index_to_be中的有效MySQL
结果资源第14行.php
结束
有没有人知道为什么?
I set up phpmyadmin, and it works fine, but my code isn''t working. id is
the correct column (it is the primary key), stock is the correct database.
CODE:
$qresult = mysql_query("SELECT id FROM ''stock''");
echo ("START<P><HR>");
while ($row = mysql_fetch_array($qresult)) {
echo ($row ["name"]);
echo ("<br>");
}
echo ("<P><HR><P>END");
OUTPUT:
START
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL
result resource in /home/houseproudlancs_co_uk/index_to_be.php on line 14
END
does anybody have any idea''s why?
推荐答案
qresult = mysql_query(" SELECT id FROM''stock''");
echo(" START< P>< HR>" ;);
while(
qresult = mysql_query("SELECT id FROM ''stock''");
echo ("START<P><HR>");
while (
row = mysql_f etch_array(
row = mysql_fetch_array(
qresult)){
echo(
qresult)) {
echo (
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